Word Problem: Roman Numerals - 1 | Mathematics for Class 4 PDF Download

Q1: In a sports event, Team A scored XX points, and Team B scored XIII points. How many more points did Team A score than Team B?

Ans: First, convert the Roman numerals to Arabic numerals. XX = 20 XIII = 13

Now, find the difference: 20 - 13 = 7

So, Team A scored 7 more points than Team B.

Q2: Sarah has X chocolates, and she buys VII more. How many chocolates does she have now in Roman numerals?

Ans: First, convert the Roman numerals to Arabic numerals. X = 10 VII = 7

Now, add the numbers: 10 + 7 = 17

Convert the sum back to Roman numerals: 17 = XVII

So, Sarah now has XVII chocolates.

Q3: A book has XLV pages, and John has read XXIII pages. How many pages does he have left to read in Roman numerals?

Ans: First, convert the Roman numerals to Arabic numerals. XLV = 45 XXIII = 23

Now, find the difference: 45 - 23 = 22

Convert the difference back to Roman numerals: 22 = XXII

So, John has XXII pages left to read.

Q4: There are XXIV students in a class. If VIII students are absent, how many students are present in Roman numerals?

Ans: First, convert the Roman numerals to Arabic numerals. XXIV = 24 VIII = 8

Now, find the difference: 24 - 8 = 16

Convert the difference back to Roman numerals: 16 = XVI

So, there are XVI students present.

Q5: A container has XXX liters of water. If X liters are used, how many liters of water are left in Roman numerals?

Ans: First, convert the Roman numerals to Arabic numerals. XXX = 30 X = 10

Now, find the difference: 30 - 10 = 20

Convert the difference back to Roman numerals: 20 = XX

So, there are XX liters of water left in the container.

Q6: A movie starts at VI o'clock and ends at IX o'clock. How long is the movie in Roman numerals?

Ans: First, convert the Roman numerals to Arabic numerals. VI = 6 IX = 9

Now, find the difference: 9 - 6 = 3

Convert the difference back to Roman numerals: 3 = III

So, the movie is III hours long.

Q7: Write the Roman numerals in normal form.
XLV = ____

Sol:

XLV = 45

To convert the Roman numeral XLV to normal form, we follow these steps:
1. Identify the Roman numerals in XLV: X = 10, L = 50, and V = 5
2. Read the numerals from left to right: X (10) comes before L (50), which is a smaller numeral before a larger one. So, we subtract the smaller numeral from the larger one: 50 - 10 = 40.
3. Add the result from step 2 to the next Roman numeral: 40 (from step 2) + V (5) = 45.
So, XLV = 45. 

Q8: Write the Roman numerals in normal form.
CCLV = ____

Sol:

CCLV = 255

To convert the Roman numeral CCLV to normal form, we can follow these steps:
1. Identify the Roman numerals and their values. C = 100, L = 50, V = 5
2. Write down the values in the order they appear. 100, 100, 50, 5
3. Add the values together. 100 + 100 + 50 + 5 = 255
So, CCLV = 255. 

Q9: Write the Roman numerals in normal form.
CCCXII = ____

Sol:

CCCXII = 312

To convert the Roman numeral CCCXII into a normal form, we will follow the steps below:

1. Write down the value of each symbol: C = 100, C = 100, C = 100, X = 10, I = 1, I = 1, I = 1

2. Add the values together: 100 + 100 + 100 + 10 + 1 + 1 + 1 = 312

So, CCCXII = 312 in normal form.

Q10: Write the Roman numerals in normal form.
CII = ____

Sol:

CII = 102

To convert the Roman numeral CII into a normal number, we can follow these steps:
1. Identify the symbols and their respective values: C = 100 and I = 1
2. Add the values from the steps above: 100 + 1 + 1 = 102

Therefore, the Roman numeral CII is equal to 102 in normal form. 

Q11: Write the Roman numerals in normal form.
CCLVI = ____

Sol:

CCLVI = 256

To convert the Roman numeral CCLVI to normal form, we can follow these steps:
1. Identify the Roman numerals: C = 100, C = 100, L = 50, V = 5, and I = 1.
2. Write the numerals in the order they appear: 100, 100, 50, 5, 1.
3. Check if a smaller numeral appears before a larger numeral (i.e. if subtraction is needed). In this case, there are no smaller numerals before larger ones.
4. Add the numerals together: 100 + 100 + 50 + 5 + 1 = 256.

So, CCLVI in normal form is 256.