Logarithms
So the two sets of statements, one involving powers and one involving logarithms are equivalent.
In the general case, we have:
Key Point
if x = an then equivalently loga x = n
loga a = 1
We can see from the Examples above that indices and logarithms are very closely related. In the same way that we have rules or laws of indices, we have laws of logarithms. These are developed in the following sections.
There are two main types of logarithms that we commonly use: common logarithms and natural logarithms.
1. Common Logarithm:
2. Natural Logarithm:
When you multiply two logarithmic values, it's like adding their individual logarithms:
logb(mn) = logbm + logbn
Dividing two logarithmic values is like subtracting their individual logarithms:
logb(m/n) = logbm - logbn
The logarithm of a product with a rational exponent is equal to the exponent times its logarithm:
logb(mn) = n logbm
Switching between different bases is done by dividing the logarithm in the original base by the logarithm in the new base:
logbm = logam / logab
Inverting the logarithm's base is done by taking the reciprocal of the logarithm in the new base:
logba = 1 / logab
If f(x) = logb(x), then the derivative of f(x) is given by:
f'(x) = 1 / (x ln(b))
The integral of a logarithmic function is given by:
∫logb(x)dx = x(logb(x) - 1/ln(b)) + C
- logbb = 1
- logb1 = 0
- logb0 = undefined
We can use logarithms to solve equations where the unknown is in the power. Suppose we wish to solve the equation 3x = 5. We can solve this by taking logarithms of both sides. Whilst logarithms to any base can be used, it is common practice to use base 10, as these are readily available on your calculator. So, log 3x = log 5
Now using the laws of logarithms, the left-hand side can be re-written to give
x log 3 = log 5
This is more straightforward. The unknown is no longer in the power. Straightaway
If we want, this value can be found in a calculator.
Example 1: Suppose we wish to find log2 512.
This is the same as being asked ‘What is 512 expressed as a power of 2 ?’
Now 512 is 29 and so log2 512 = 9.
Example 2: Suppose we wish to find log8 1/64.
This is the same as being asked ‘What is 1/64 expressed as a power of 8 ?’
Now 1/64 can be written 64−1. Noting also that 82 = 64 it follows that
using the rules of indices. So log8 = 1/64 = -2
Example 3: Suppose we wish to find log5 25.
This is the same as being asked ‘What is 25 expressed as a power of 5 ?’
Now 52 = 25 and so log5 25 = 2.
Example 4: Suppose we wish to find log25 5.
This is the same as being asked ‘What is 5 expressed as a power of 25 ?’
We know that 5 is a square root of 25, that is 5 = √25. So 25 1/2 = 5 and so log25 5 = 1/2.
Example 5: Consider log2 8. We are asking ‘What is 8 expressed as a power of 2 ?’ We know that 8 = 23 and so log2 8 = 3.
What about log8 2 ? Now we are asking ‘What is 2 expressed as a power of 8 ?’ Now 23 = 8 and so 2 = ∛8 or 81/3. So log8 2 =1/3.
We see again
1. Why do we study logarithms? |
2. What is a Logarithm? |
3. What are the types of logarithms? |
4. What are the rules for logarithmic operations? |
5. How can logarithms be used to solve equations? |
|
Explore Courses for JEE exam
|