Q.1. (CH3)3CBr
Ans. 2
Compound (C) has one chiral C-atom. Therefore, it has two stereoisomers.
Q.2. An organic compound (A) contains only C, H and O atoms. On reaction with excess of CH3MgI, one mole of (A) gives a gas (X) whose volume under STP conditions was found to be 67.2 litre. The number of hydroxyl groups in the compound (A) are
Ans. 3
67.2/22.4 = mole of gas(X) evolved = 3 mole of gas(X)
The number of active H-atom present in a molecule is equal to the number of moles of gas obtained i.e. no. of - OH groups in compound (A) = 3.
Q.3. The number of possible enantiomeric pairs that can be produced during monochlorination of 2-methylbutane is
Ans. 2
Thus, 2 pair of enantiomers are formed.
Q.4. Isopentane can form four monobromo isomeric derivatives. How many of them are optically active?
Ans. 2
Q.5. The treatment of CH3OH with CH3MgI release 1.04 mL of a gas at STP. The mass of CH3OH added is
Ans. 1.49
1.49 mg
Q.6. The enthalpy of combustion of cyclohexane, cyclohexene and H2 are respectively –3920, –3800 and –241 kJ mol–1. The heat of hydrogenation of cyclohexene is
Ans. –121
C6H12 + 9O2 → 6CO2 + 6H2O …(i)
2C6H12 + 17O2 → 12CO2 + 10H2O …(ii)
H2 + ½O2 → H2O …(iii)
To arrive this equation
C6H10 + H2 → C6O12 …(iv)
Adding equation (ii) and (iii) and then subtracting (i), we get equation (iv)
(–3800 –241) – (–3920) kJ mol–1
–4041 + 3920 = –121 kJ mol–1
Q.7. The number of possible enantiomeric pairs that can be produced during monochlorination of 2-methyl butane is
Ans. 2
gives two pairs of enantiomersand
Q.8. The number of monochloro derivatives that the compound 'D' can give
Ans. 2
CH3 — CH3 — CH2 — CH2 — Cl
Q.9. Find the number of p bond in the final product of following reaction.
Ans. 1
Q.10.
Mono halo substitution Product(s) total no. of possible enantiomeric pairs will form are
Ans. 2
Only two products contain chiral carbon atom. Hence no. of possible enantiomeric pairs are 2.
447 docs|930 tests
|
|
Explore Courses for JEE exam
|