JEE Previous Year Questions (2021-23): Compounds Containing Nitrogen | 35 Years Chapter wise Previous Year Solved Papers for JEE PDF Download

Q.1. Increasing order of stability of the resonance structures is:     [JEE Main 2023]
(A)
(B)
(C)
(D)
Choose the correct answer from the options given below:
(a) D, C, A, B
(b) D, C, B, A
(c) C, D, A, B
(d) C, B, A, D

Ans. d
Final correct order C<B<A<D

Q.2. Consider the following reaction sequence:    [JEE Main 2022]
The product 'B' is :
(a)

(b)

(c)

(d)

Ans. b

Q.3. Which among the following represent reagent 'A'?    [JEE Main 2022]
(a)

(b)

(c)

(d)

Ans. a

Q.4. Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R    [JEE Main 2022]
Assertion A : Aniline on nitration yields ortho, meta & para nitro derivatives of aniline.
Reason R : Nitrating mixture is a strong acidic mixture.
In the light of the above statements, choose the correct answer from the options given below
(a) Both A and R are true and R is the correct explanation of A
(b) Both A and R are true but R is NOT the correct explanation of A
(c) A is true but R is false
(d) A is false but R is true

Ans. a
Due to formation of anilinium ion in acidic medium meta product is also obtained in significant amount

Q.5. Arrange the following in increasing order of reactivity towards nitration    
[JEE Main 2022]
A. p-xylene
B. bromobenzene
C. mesitylene
D. nitrobenzene
E. benzene
Choose the correct answer from the options given below
(a) C < D < E < A < B
(b) D < B < E < A < C
(c) D < C < E < A < B
(d) C < D < E < B < A

Ans. b
The correct order of reactivity towards nitration is

as electron releasing groups on benzene ring facilitate the nitration at benzene ring.

Q.6. An organic compound ′A′ contains nitrogen and chlorine. It dissolves readily in water to give a solution that turns litmus red. Titration of compound ′A′ with standard base indicates that the molecular weight of ′A′ is 131 ± 2. When a sample of ′A′ is treated with aq. NaOH, a liquid separates which contains N but not Cl. Treatment of the obtained liquid with nitrous acid followed by phenol gives orange precipitate. The compound ′A′ is :    [JEE Main 2022]
(a)

(b)

(c)

(d)

Ans. d

Q.7. Match List I with List II.    [JEE Main 2022]

Choose the correct answer from the options given below:
(a) A-IV, B-III, C-II, D-I
(b) A-IV, B-II, C-I, D-III
(c) A-III, B-IV, C-I, D-II
(d) A-IV, B-III, C-I, D-II

Ans. c
(A) Benzene sulphonyl chloride is also known as Hinsberg reagent.
(B) Hoffmann bromamide reaction involves conversion of amide to amine having one C atom less. This reaction involves isocyanate as intermediate.
(C) Carbylamine reaction is a test given by all primary amines.
(D) Hoffmann orientation refers to the addition of molecules to unsymmetrical alkenes according to anti Saytzeff's rule.
Correct match is
A-III, B-IV, C-I, D-II

Q.8. The correct sequential order of the reagents for the given reaction is    [JEE Main 2022]
(a) HNO₂, Fe/H⁺, HNO₂, KI, H₂O/H+
(b) HNO₂, KI,Fe/H⁺, HNO₂, H₂O/ warm
(c) HNO₂, KI,HNO₂,Fe/H⁺,H₂O/H+
(d) HNO₂, Fe/H₊,KI,HNO₂,H2O/ warm

Ans. b

Q.9. Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).    [JEE Main 2022]
Assertion (A) : Experimental reaction of CH₃Cl with aniline and anhydrous AlCl₃ does not give o and p-methylaniline.
Reason (R): The −NH₂ group of aniline becomes deactivating because of salt formation with anhydrous AlCl3 and hence yields m-methyl aniline as the product.
In the light of the above statements, choose the most appropriate answer from the options given below :
(a) Both A and R are true and (R) is the correct explanation of (A).
(b) Both A and R are true but (R) is not the correct explanation of (A).
(c) (A) is true, but (R) is false.
(d) (A) is false, but (R) is true.

Ans. c

Q.10. The correct stability order of the following diazonium salt is    [JEE Main 2022]
(a) (A)>(B)>(C)>(D)
(b) (A)>(C)>(D)>(B)
(c) (C)>(A)>(D)>(B)
(d) (C)>(D)>(B)>(A)

Ans. b

Q.11. The major product of the following reaction is    [JEE Main 2022]
(a)

(b)

(c)

(d)

Ans. a

Q.12. The correct structure of C is    [JEE Main 2022]
(a) CH₃−CH₂−CH₂−CH₃
(b)
(c)
(d) CH₃−CH₂−CH=CH₂

Ans. a

Q.13. Most stable product of the following reaction is:    [JEE Main 2022]
(a)

(b)

(c)

(d)

Ans. b

Q.14. The major product of the above reactions is :    [JEE Main 2022]
(a)

(b)

(c)

(d)

Ans. d

Q.15. In the given reaction sequence, the major product 'C' is :    [JEE Main 2022]
(a)

(b)

(c)

(d)

Ans. b
C₈H₁₀ DU = 9 – 5 = 4 

Q.16. The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents is    [JEE Main 2022]
(a) (i) SOCl₂ (ii) KCN (iii) H₂/Ni, Na(Hg)/C₂H₅OH
(b) (i) HCl (ii) H₂/Ni, Na(Hg)/C₂H₅OH
(c) (i) SOCl₂ (ii) KCN (iii) CH₃NH₂
(d) (i) HCl (ii) CH₃NH₂

Ans. a

Q.17. The reaction of
with bromine and KOH gives RNH₂ as the end product. Which one of the following is the intermediate product formed in this relation?    [JEE Main 2022]
(a)

(b) R − NH − Br
(c) R − N = C = O
(d)

Ans. c
The given reaction is Hoffmann-Bromide degradation method.

Q.18. Amongst the following, the major product of the given chemical reaction is 
[JEE Main 2022]
(a)

(b)

(c)

(d)

Ans. a

Q.19. Which statement is NOT correct for p-toluenesulphonyl chloride?    [JEE Main 2022]
(a) It is known as Hinsberg's reagent.
(b) It is used to distinguish primary and secondary amines.
(c) On treatment with secondary amine, it leads to a product, that is soluble in alkali.
(d) It doesn't react with tertiary amines.

Ans. c

Q.20. Halogenation of which one of the following will yield m-substituted product with respect to methyl group as a major product?    [JEE Main 2022]
(a)

(b)

(c)

(d)

Ans. c

Q.21. Given below are two statements :    [JEE Main 2022]
Statement I : In Hofmann degradation reaction, the migration of only an alkyl group takes place from carbonyl carbon of the amide to the nitrogen atom.
Statement II : The group is migrated in Hofmann degradation reaction to electron deficient atom.
In the light of the above statements, choose the most appropriate answer from the options given below :
(a) Both Statement I and Statement II are correct.
(b) Both Statement I and Statement II are incorrect.
(c) Statement I is correct but Statement II is incorrect.
(d) Statement I is incorrect but Statement II is correct.

Ans. d

Q.22. The major product of the following reaction is :    [JEE Main 2022]
(a)

(b)

(c)

(d)

Ans. a

Q.23. A primary aliphatic amine on reaction with nitrous acid in cold (273 K) and there after raising temperature of reaction mixture to room temperature (298 K), gives a/an
[JEE Main 2022]
(a) nitrile
(b) alcohol
(c) diazonium salt
(d) secondary amine

Ans. b

Q.24. Identify the major product formed in the following sequence of reactions:   
[JEE Main 2022]
(a)

(b)

(c)

(d)

Ans. c

Q.25. With respect to the following reaction, consider the given statements :   
[JEE Main 2022]
(A) o-Nitroaniline and p-nitroaniline are the predominant products.(B) p-Nitroaniline and m-nitroaniline are the predominant products.
(C) HNO₃ acts as an acid.
(D) H₂SO₄ acts as an acid.
Choose the correct option.
(a) (A) and (C) are correct statements.
(b) (A) and (D) are correct statements.
(c) (B) and (D) are correct statements.
(d) (B) and (C) are correct statements.

Ans. c

Q.26. In Friedel-Crafts alkylation of aniline, one gets.    [JEE Main 2022]
(a) alkylated product with ortho and para substitution.
(b) secondary amine after acidic treatment.
(c) an amide product.
(d) positively charged nitrogen at benzene ring.

Ans. d

Q.27. Match the compounds in LIST-I with the observations in LIST-II, and choose the correct option.    [JEE Advance 2022]
(a) I → P,Q; II → S;III→ Q,R; IV → P
(b) I → P; II → R, S; III → R; IV → Q,S
(c) I → Q,S; II → P,T; III → P; IV → S

(d) I → P, S; II → T; III → Q,R; IV→ P

Ans. d
(I) Aniline has N atoms hence gives prussian blue colour in Sodium fusion extract test. Aniline also gives white precipitate with Bromine water.
(II) O-Cresol has phenolic group hence gives violet colour complex with netural FeCl3.
(III) Cysteine has 'S' atom, hence gives blood red color when odium S fusion extract of this compound is treated with sodium nitroprusside.
(IV) Caprolactam has N atom, hence sodium extract of this compound gives prussian blue color. 

Q.28. The total number of reagents from those given blow, that can convert nitrobenzene into aniline is ___________. (Integer answer)    [JEE Main 2021]
I. Sn − HCl
II. Sn − NH₄OH
III. Fe − HCl
IV. Zn − HCl
V. H₂ − Pd
VI. H₂ − Raney Nickel

Ans. 5
(i) Sn + HCl
(ii) Fe + HCl
(iii) Zn + HCl
(iv) H₂ − Pd
(v) H₂ (Raney Ni)

Q.29. In gaseous triethyl amine the "−C−N−C−" bond angle is _________ degree.
[JEE Main 2021]

Ans. 108
In gaseous triethyl amine the "−C−N−C−" bond angle is 108 degree.

Q.30. The number of nitrogen atoms in a semicarbazone molecule of acetone is ______________.
[JEE Main 2021]

Ans. 3
Three nitrogen atoms are present as per structure below
Semicarbazone molecule of acetone

Q.31. The total number of amines among the following which can be synthesized by Gabriel synthesis is __________. [JEE Main 2021]

Ans. 3
Gabriel phthalimide synthesis is used to prepare 1^o aliphatic or alicyclic amine. Hence, amine which can be synthesised by Gabriel phthalimide synthesis method contains α-carbon.
Aniline (C₆H₅NH₂) does not contain α-C cannot be prepared by Gabriel reaction.
Remaining amines all contain α-C in its respective position, hence they can easily give Gabriel phthalimide reaction.

Q.32. Which one of the following gives the most stable Diazonium salt? [JEE Main 2021]
(a) CH₃−CH₂−CH₂−NH₂
(b)

(c)

(d)

Ans. b
1o aromatic amines give the most stable diazonium salt.

Q.33. Identify A in the following reaction. [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. a

K₂Cr₂O₇ is oxidizing agent. 

Q.34. Identify correct A, B and C in the reaction sequence given below : [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. b

Q.35. The major products A and B formed in the following reaction sequence are : 
[JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. c

Q.36. The major products A and B in the following set of reactions are : [JEE Main 2021]

(a)

(b)

(c)

(d)

Ans. b

Q.37. The correct structures of A and B formed in the following reactions are :
[JEE Main 2021]

(a)

(b)

(c)

(d)

Ans. d

Q.38. Which one of the following is the major product of the given reaction? [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. a

Q.39. In the following sequence of reactions the P is : [JEE Main 2021]

(a)

(b)

(c)

(d)

Ans. a

Q.40. Which of the following is not a correct statement for primary aliphatic amines?
[JEE Main 2021]
(a) The intermolecular association in primary amines is less than the intermolecular association in secondary amines.
(b) Primary amines on treating with nitrous acid solution from corresponding alcohols except mythyl amine.
(c) Primary amines are less basic than the secondary amines.
(d) Primary amines can be prepared by the Gabriel phthalimide synthesis.

Ans. a
The intermolecular association is more prominent in case of primary amines as compared to secondary, due to the availability of two hydrogen atom.

Q.41. Consider the given reaction, identify 'X' and 'Y' :

(a)

(b)

(c)

(d)

Ans. c
Cyanohydrin is formed when carbonyl compound reacts with HCN in the presence of alkali (NaOH).
So, X is alkali i.e. NaOH.
Cyanohydrin on reacting with LiAlH4 forms amine.

Q.42. The major product in the above reaction is : [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. d

Q.43. Match List - I with List - II : [JEE Main 2021]
Choose the most appropriate match :
(a) a-ii, b-iv, c-iii, d-i
(b) a-iv, b-ii, c-iii, d-i
(c) a-ii, b-iii, c-iv, d-i
(d) a-iii, b-ii, c-i, d-iv

Ans. c

Q.44. The correct sequential addition of reagents in the preparation of 3-nitrobenzoic acid from benzene is : [JEE Main 2021]
(a) Br₂/AlBr₃, HNO₃/H₂SO₄, Mg/ether, CO₂, H₃O⁺
(b) Br2/AlBr₃, NaCN, H₃O+, HNO₃/H₂SO₄
(c) Br₂/AlBr3, HNO₃/H₂SO₄, NaCN, H₃O+
(d) HNO₃/H₂SO₄, Br₂/AlBr₃, Mg/ether, CO₂, H₃O⁺

Ans. d

Q.45. The correct sequence of correct reagents for the following transformation is :
[JEE Main 2021]
(a) (i) Fe, HCl
(ii) Cl₂, HCl
(iii) NaNO₂, HCl, 0^∘C
(iv) H₂O/H⁺
(b) (i) Fe, HCl
(ii) NaNO₂, HCl, 0∘C
(iii) H₂O/H⁺
(iv) Cl₂, FeCl₃
(c) (i) Cl₂, FeCl₃
(ii) Fe, HCl
(iii) NaNO₂, HCl, 0^∘C
(iv) H₂O/H⁺
(d) (i) Cl₂, FeCl₃
(ii) NaNO₂, HCl, 0^∘C
(iii) Fe, HCl
(iv) H₂O/H⁺

Ans. c

Q.46. What is A in the following reaction? [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. d

Q.47. Given below are two statements : [JEE Main 2021]
Statement I : Aniline is less basic than acetamide.
Statement II : In aniline, the lone pair of electrons on nitrogen atom is delocalized over benzene ring due to resonance and hence less available to a proton.
Choose the most appropriate option;
(a) Statement I is true but statement II is false.
(b) Statement I is false but statement II is true.
(c) Both statement I and statement II are true.
(d) Both statement I and statement II are false.

Ans. b
aniline is more basic than acetamide because in acetamide, lone pair of nitrogen is delocalized to more electronegative element oxygen.
In Aniline lone pair of nitrogen delocalized over benzene ring.

Q.48. What is the major product "P" of the following reaction? [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. d

Q.49. A reaction of benzonitrile with one equivalent CH₃MgBr followed by hydrolysis produces a yellow liquid "P". The compound "P" will give positive _________.
[JEE Main 2021]
(a) Iodoform test
(b) Schiff's test
(c) Ninhydrin's test
(d) Tollen's test

Ans. a

Q.50. Consider the below reaction, the product "P" is : [JEE Main 2021]

(a)

(b)

(c)

(d)

Ans. b

Q.51. Which one of the following compounds will liberate CO₂, when treated with NaHCO₃?
[JEE Main 2021]
(a)
(b)
(c)
(d)

Ans. a

Q.52. Which one of the products of the following reactions does not react with Hinsberg reagent to form sulphonamide? [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. b

Q.53. Which one of the following reactions does not occur? [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. c
(1) Aniline is lewis base acid bae reaction with AlCl₃ and form Anilinium ion.
(2) Anilinium ion has strongest deactivated ring so further Friedel craft Alkylation not occurs. 

Q.54. In the chemical reactions given below A and B respectively are : [JEE Main 2021]

(a) H₃PO₂ and CH₃CH₂Cl
(b) CH₃CH₂OH and H₃PO₂
(c) H₃PO₂ and CH₃CH₂OH
(d) CH₃CH₂Cl and H₃PO₂

Ans. a

Q.55. In Carius method, halogen containing organic compound is heated with fuming nitric acid in the presence of : [JEE Main 2021]
(a) HNO₃
(b) AgNO₃
(c) CuSO₄
(d) BaSO₄

Ans. b
Organic compound is heated with fuming nitric acid in the presence of silver nitrate in carius method.
Lunar caustic (AgNO₃) is used as reagent hare to distinguish Cl⁻, Br^- and I⁻ respectively as follows.

Q.56. Consider the below reaction, compound B is : [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. c

Q.57. Benzene on nitration gives nitrobenzene in presence of HNO3 and H2SO4 mixture, where: [JEE Main 2021]
(a) both H₂SO₄ and HNO₃ act as a bases
(a) HNO₃ acts as an acid and H₂SO₄ acts as a base
(a) both H₂SO₄ and HNO₃ act as an acids
(a) HNO₃ acts as a base and H₂SO₄ acts as an acid

Ans. d
Reagent for nitration of Benzene

Q.58. In the above reactions, product A and product B respectively are : [JEE Main 2021]

(a)

(b)

(c)

(d)

Ans. d

Q.59. Compound A is converted to B on reaction with CHCl₃ and KOH. The compound B is toxic and can be decomposed by C. A, B and C respectively are : [JEE Main 2021]
(a) primary amine, nitrile compound, conc. HCl
(b) secondary amine, isonitrile compound, conc. NaOH
(c) primary amine, isonitrile compound, conc. HCl
(d) secondary amine, nitrile compound, conc. NaOH

Ans. c
Primary amine reacts in presence of chloroform gives isonitrile which is toxic in nature which further reacts in presence of HCl/H₃O⁺ to give primary amine and acid. 

Q.60. The correct structure of Rhumann's Purple, the compound formed in the reaction of ninhydrin with proteins is : [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. d
Rhumann’s purple is confirmatory test for the presence of protein. The correct structure of Rhumann’s Purple, the compound formed in the reaction of ninhydrin with proteins is an follows

Q.61. An organic compound "A" on treatment with benzene sulphonyl chloride gives compound B. B is soluble in dil. NaOH solution. Compound A is : [JEE Main 2021]
(a)
(b) C₆H₅ − NHCH₂CH3
(c) C₆H₅ − N − (CH₃)₂
(d) C₆H₅ − CH₂NHCH₃

Ans. a

Q.62. In the reaction of hypobromite with amide, the carbonyl carbon is lost as :
[JEE Main 2021]
(a) CO₂
(b) CO
(c) HCO³⁻
(d) CO₃²⁻

Ans. d
Carbonyl carbon is lost as CO₃²⁻.

Q.63. Consider the given reaction, percentage yield of : [JEE Main 2021]
(a) B > C > A
(b) A > C > B
(c) C > A > B
(d) C > B > A

Ans. d
During nitration of aniline, meta-nitroaniline is also formed as product due to formation of NH₃⁺ group which is meta directing group under strongly acidic medium. The percentage of p, m and o product is 51%, 47% and 2%, respectively. 

Q.64. Considering the below reaction, X and Y respectively are : [JEE Main 2021]

(a)

(b)

(c)

(d)

Ans. b

Q.65. Primary, secondary and tertiary amines can be separated using: [JEE Main 2021]
(a) Chloroform and KOH
(b) cetyl amide
(c) Benzene sulphonic acid
(d) para-Toluene sulphonyl chloride

Ans. d

Q.66. Which of the following is correct structure of tyrosine? [JEE Main 2021]
(a)

(b)

(d)

(e)

Ans. d
Tyrosine is p-hydroxyphenylalanine. Its structure is

Q.67. Hoffmann bromomide degradation of benzamide gives product A, which upon heating with CHCl₃ and NaOH gives product B. [JEE Main 2021]
The structures of A and B are :
(a)

(b)

(c)

(d)

Ans. a

Q.68. Ammonolysis of Alkyl halides followed by the treatment with NaOH solution can be used to prepare primary, secondary and tertiary amines. The purpose of NaOH in the reaction is : [JEE Main 2021]
(a) to remove acidic impurities
(b) to remove basic impurities
(c) to activate NH₃ used in the reaction
(d) to increase the reactivity of alkyl halide

Ans. a
During the reaction HX (acid) is formed
Hence, we use NaOH to remove these acidic impurities

Q.69. Which of the following reactions DOES NOT involve Hoffmann bromamide degradation? [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. b
(1)
(2)
(3)
(4) 

Q.70. Choose the correct order of basic nature of the above amines. [JEE Main 2021]
A. Phenyl methanamine
B. N,N-Dimethylaniline
C. N-Methyl aniline
D. Benzenamine
(a) D > C > B > A
(b) A > C > B > D
(c) D > B > C > A
(d) A > B > C > D

Ans. d
In phenyl methanamine, the lone pair on nitrogen of -NH₂ group is localised and does not undergoes resonance. 
(B), (C) and (D) are aromatic amines in which lone pair of electrons of N-atoms goes in resonance (+R effect) with the benzene ring. So, Lewis basicity or donation of lone of electrons of these amines will be decreased in comparison to (A).
+ I effects of two -CH₃ groups increases electron density on N atom while lone pair of N atom take part in resonance with the benzene ring and decreases electron density on N atom. Both this effect try to compensate each other.
It has no + I-effect on N-atom to increase electron density on the N atom which was decreased due to lone pair of N atom take part in resonance with the benzene ring. So, A is purely aliphatic 1°-amine. B is aromatic. 3°-amine with more aliphatic nature (for two -CH₃ groups). C is aromatic 2°-amine with less aliphatic nature (for one -CH₃ group).
D is purely aromatic 1°-amine.
Hence basicity order is A > B > C > D.

Q.71. An amine on reaction with benzensulphonyl chloride produces a compound insoluble in alkaline solution. This amine can be prepared by ammonolysis of ethyl chloride. The correct structure of amine is : [JEE Main 2021]
(a) CH₃CH₂NH₂
(b) CH₃CH₂CH₂NHCH₃
(c)
(d)

Ans. c
Given amine on reaction with PhSO₂Cl produces a compound insoluble in alkaline solution it means it is a 2º amine.
Also It is prepared by ammonolysis of C₂H₅Cl, it must contain an ethyl group. 
  is a 2° amine as well as it contain ethyl group.

Q.72. Given below are two statements : [JEE Main 2021]
Statement I : A mixture of chloroform and aniline can be separated by simple distillation.
Statement II : When separating aniline from a mixture of aniline and water by steam distillation aniline boils below its boiling point.
In the light of the above statements, choose the most appropriate answer from the options given below :
(a) Both Statement I and Statement II are true
(b) Both Statement I and Statement II are false
(c) Statement I is true but Statement II is false
(d) Statement I is false but Statement II is true

Ans. a
Mixture of chloroform and aniline can be separated by simple distillation as these two liquids have sufficient difference in boiling point. Chloroform (b.p. 334 K), aniline (b.p. 457 K)
In steam distillation, if one of the substances is water and the other, a water insoluble substance (like aniline) then the mixture will boil close to but below 373 K.

Q.73. For the given reaction [JEE Main 2021]
What is 'A'?
(a)

(b)

(c)

(d)

Ans. a

Q.74. Carbylamine test is used to detect the presence of primary amino group in an organic compound. Which of the following compound is formed when this test is performed with aniline? [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. d

Q.75. Correct statement about the given chemical reaction is : [JEE Main 2021]
(a)  group is ortho  and para directive, so product (B) is not possible.
(b) Reaction is possible and compound (B) will be the major product.
(c) Reaction is possible and compound (A) will be major product.
(d) The reaction will form sulphonated product instead of nitration.

Ans. c

Q.76. The correct sequence of reagents used in the preparation of 4-bromo-2-nitroethyl benzene from benzene is : [JEE Main 2021]
(a) CH₃COCl/AlCl₃,Br₂/AlBr₃,HNO₃/H₂SO₄,Zn/HCl
(b) CH₃COCl/AlCl₃,Zn−Hg/HCl,Br₂/AlBr₃,HNO₃/H₂SO₄
(c) Br₂/AlBr₃,CH₃COCl/AlCl₃,HNO₃/H₂SO₄,Zn/HCl
(d) HNO₃/H₂SO₄,Br2/AlCl₃,CH₃COCl/AlCl₃,Zn−Hg/HCl

Ans. b

Q.77. Which of the following reaction/s will not give p-aminoazobenzene? [JEE Main 2021]
(a) C only
(b) A only
(c) A and B
(d) B only

Ans. d

Q.78. Compound(s) which will liberate carbon dioxide with sodium bicarbonate solution is/are : [JEE Main 2021]
(a) C only
(b) B only
(c) B and C only
(d) A and B only

Ans. b
Compounds which are more acidic then H₂CO₃, gives CO₂ gas on reaction with NaHCO₃.
Compound B i.e. Benzoic acid and compound C i.e. picric acid both are more acidic than H₂CO₃.

Q.79. The diazonium salt of which of the following compounds will form a coloured dye on reaction with β-Naphthol in NaOH? [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. c

Q.80. What is the correct sequence of reagents used for converting nitrobenzene into m-dibromobenzene? [JEE Main 2021]
(a)
(b)
(c)
(d)

Ans. c

Q.81. 'A' and 'B' in the following reactions are : [JEE Main 2021]
(a)

(b)

(c)

(d)

Ans. d
Step 1 : In step 1, NaNO₂ + HCl , 0-5°C used for diazotisation reaction. It will form diazonium salt. Further, it will react with KCN to form cyanobenzene.
Step 2 : In step 2, SnCl₂ and HCl is a Stephen’s reduction reagent. Cyanobenzene reduced to benzaldehyde by SnCl₂/HCl. 

Q.82. In the following reaction the reason why meta-nitro product also formed is :
[JEE Main 2021]

(a) –NH2 group is highly meta-directive
(b) –NO2 substitution always takes place at meta-position
(c Formation of anilinium ion
(d) low temperature

Ans. c
Aniline on protonation forms anilinium ion, which is meta-directing. So, a considerable amount of meta product is formed alongwith o-nitroaniline and p-nitroaniline.