Tables Questions for CAT with Answers PDF

Total income earned by multiplex G on day 1 and day 2 = {(156 - 41) + 45 + 41} x 125 + {(264 - 23) + 62 + 23} x 150
= 201 x 125 + 326 x 150 = 25,125 + 48,900 = Rs. 74,025
Income earned by multiplex H on day 1 = {(137 - 10) + 32 + 10} x 225 = 169 x 225 = Rs. 38,025
Required percent = ((74,025 - 38,025)/38,025) x 100 = 94.67%

Income earned by multiplex G on day 1
= 45 x 0.85 x 125 + 115 x 125 + 41 x 0.79 x 125
= 4781.25 + 14,375 + 4048.75
= Rs. 23,205
Income earned by multiplex G on day 2
= 62 x 0.85 x 150 + 241 x 150 + 23 x 0.79 x 150
= 7905 + 36,150 + 2725.5
= Rs. 46,780.5
Income earned by multiplex H on day 1
= 32 x 0.85 x 225 + 127 x 225 + 10 x 0.79 x 225
= 6120 + 28,575 + 1777.5 = Rs. 36,472.5
Total = 23,205 + 46,780.5 + 36,472.5 = Rs. 1,06,458

Total number of persons who went to all the multiplexes on day 1 and day 2 = 156 + 45 + 234 + 68 + 168 + 35 + 421 + 41 + 137 + 32 + 264 + 62 + 420 + 75 + 368 + 89 + 159 + 31 + 196 + 22 = 3023
Total number of persons who went to all the multiplexes on day 1 and day 2 aged 0-55 years = 3023 - 41 - 36 - 55 - 32 - 10 - 23 - 23 - 56 - 36 - 10 = 2701
Total number of persons who went to all the multiplexes on day 1 and day 2 aged less than 55 years = 2701 - 27 x 5 - 27 x 5 = 2431 (Subtracting the 27 persons aged 55 years who visited each of the 5 multiplexes on day 1 and day 2)
Required percent =  x 100 = 80.42%.

Total income earned by multiplex G on day 2 = 241 x 150 + 23 x 0.76 x 150 + 62 x 0.88 x 150 = 36,150 + 2622 + 8184 = Rs. 46,956
Total income earned by multiplex H on day 2 = 186 x 200 + 10 x 0.76 x 200 + 22 x 0.88 x 200 = 37,200 + 1520 + 3872 = Rs. 42,592
Total income earned by multiplex W on day 2 = 397 x 180 + 75 x 0.88 x 180 + 23 x 0.76 x 180 = 71,460 + 11,880 + 3146 = Rs. 86,486.4
Total = 46,956 + 42,592 + 86,486.4 = Rs. 1,76,034.4

Based on the information given in the table, in order to get the maximum output of 527 units for Apple, it can be concluded that 85 units of Apple were sold in March.

Required difference = 587 - 414 = 173

The required difference is maximum for Sony and is equal to 181.

The transportation cost from depot PS to district PPV = Rs. 0
The transportation cost from factory QR to depot PS = Rs. 50.10
∴ Minimum cost of transportation from any factory to district PPV = Rs. 50.10

The highest cost of transportation from a factory to a depot = Rs. 1,157.70 (QT to PT)
Cost of transportation from PT to PPU takes up the highest charge of Rs. 1,035.30.
∴ Maximum cost = 1157.70 + 1035.30 = Rs. 2,193.00
Thus, option 2 is correct answer.

Number of ways = Six factory × Seven depots × Nine districts  
= 6 x 7 x 9 = 378 
Hence, option 2 is the correct answer.

The cost of transporting one unit from factory QS to depot PT is Rs. 0 and the cost of transporting one unit from depot PT to district PPQ is also Rs. 0.
∴ The minimum cost of transporting one unit from any factory to any district is Rs. 0.

The number of trainees failing in any phase will be a single digit natural number i.e. the number of trainees failing in Phase 1 can be 1 to 9.
If we consider 1 trainee fails in 2017, then following table can be inferred.

While calculating, we found that trainees failing from Phase 3 is 0, which is not possible as it should be a single digit natural number, so this case is not possible.
If we consider 2 trainees are failing in Phase 1 of 2017, we get the following table.

After calculations, we find that trainees failing from Phase 5 in 2017 is 0, which is not possible.
If we consider that 3 trainees fail in Phase 1 in 2017, the following can be tabulated.

Thus, when the number of trainees failing in Phase 1 is 3, then all conditions are satisfied.
For any other value, number of trainees failing in any phase will become 0 or more than two digit number, which is not possible.
Total number of trainees in 2017 is 359.
Total number of trainees who failed = 31
Thus, total pass percentage of the company in 2017  = 91.365%
Individual phase percentage.
Phase 1 = 92.5%
Phase 2 = 91.667%
Phase 3 = 96.226%
Phase 4 = 90%
Phase 5 = 96.875%
Phase 6 = 88.636%
Phase 7 = 87.5%
Thus, 4 phases had pass percentage greater than the overall pass percentage of company in 2017.

The number of trainees failing in any phase will be a single digit natural number i.e. the number of trainees failing in Phase 1 can be 1 to 9.
If we consider 1 trainee fails in 2017, then following table can be inferred.

While calculating, we found that trainees failing from Phase 3 is 0, which is not possible as it should be a single digit natural number, so this case is not possible.
If we consider 2 trainees are failing in Phase 1 of 2017, we get the following table.

After calculations, we find that trainees failing from Phase 5 in 2017 is 0, which is not possible.
If we consider that 3 trainees fail in Phase 1 in 2017, the following can be tabulated.

Thus, when the number of trainees failing in Phase 1 is 3, then all conditions are satisfied.
For any other value, number of trainees failing in any phase will become 0 or more than a two digit number, which is not possible.
Total number of trainees in 2017 = 359
Number of trainees who failed = 3 + 4 + 2 + 7 + 1 + 5 + 9 = 31

The number of trainees failing in any phase will be a single digit natural number i.e. the number of trainees failing in Phase 1 can be 1 to 9.
If we consider 1 trainee fails in 2017, then following table can be inferred.

While calculating, we found that trainees failing from Phase 3 is 0, which is not possible as it should be a single digit natural number, so this case is not possible.
If we consider 2 trainees are failing in Phase 1 of 2017, we get the following table.

After calculations, we find that trainees failing from Phase 5 in 2017 is 0, which is not possible.
If we consider that 3 trainees fail in Phase 1 in 2017, the following can be tabulated.

Total number of trainees in 2017 = 359
Total number of new trainees from previous phase in 2018 = 47 + 37 + 44 + 51 + 63 + 31 + 39 = 312
Number of trainees who failed = 3 + 4 + 2 + 7 + 1 + 5 + 9 = 31
The number of new trainees who joined DCBA Company in the year 2018 = 359 - 312 = 47
Thus, we can see that 47 new trainees joined DCBA Company in the year 2018.

The number of trainees failing in any phase will be a single digit natural number i.e. the number of trainees failing in Phase 1 can be 1 to 9.
If we consider 1 trainee fails in 2017, then following table can be inferred.

While calculating, we found that trainees failing from Phase 3 is 0, which is not possible as it should be a single digit natural number, so this case is not possible.
If we consider 2 trainees are failing in Phase 1 of 2017, we get the following table.

After calculations, we find that trainees failing from Phase 5 in 2017 is 0, which is not possible.
If we consider that 3 trainees fail in Phase 1 in 2017, the following can be tabulated.

Total number of trainees who passed from DCBA Company in the year 2017 = The number of trainees who passed from Phase 7 in 2017.
Number of trainees who failed in Phase 7 = 9
Thus, 72 - 9 = 63 trainees passed in Phase 7 of the year 2017.