When we talk about something being "big," we mean how much space it takes up, like if it's tall or wide. When we say something is "heavy," we mean it weighs a lot, like if it's hard to lift. You can figure out both by finding out how much room something takes up, which we call its volume.
Example: Find the length, width, height, and volume of the matchbox.
Take a matchbox and a measuring scale.
Measure the length, width and height of the matchbox.
Then calculate its volume = length x width x heightHere, The length of the matchbox is 5cm long, Its width is 3cm wide and its height is 1cm.
So Its volume = 5 ×3 × 1 = 15cm3
Cuboid
Example 1: Find the number of cubes that can be packed into the cuboidal box with length = 10 cm, breadth=6 cm and height = 20 cm.
Sol: Length = 10 cm, Breadth = 6 cm and Height = 20 cm.
Number of cubes packed = Volume of cuboidal box = length x width x height
Number of cubes packed = Volume = 10 x 6 x 20
So, 1200 cubes can be packed.
Example 2: Find the volume of a cuboid whose length = 5 cm, width = 2 cm and height = 3 cm.
Sol: Given, length = 5 cm, width = 2 cm and height = 3 cm
By the formula, we know;
Volume of cuboid = length x width x height
= 5 cm x 2 cm x 3 cm
= 30 cm3.
Example 3: Calculate the amount of air that can be accumulated in a room that has a length of 5 m, a breadth of 6 m, and a height of 10 m.
Sol: Amount of air that can be accumulated in a room = capacity of the room = volume of a cuboid
The volume of cuboid = l × b × h = 5 ×6 ×10 = 300 m3
Thus, this room can accommodate a maximum of 300 m3 of air.
Volume of Cube
Example 1: Find the volume of the cubical box with length=11 cm, breadth= 11 cm and height =11 cm.
Sol: Length=11 cm, Breadth=11 cm and Height =11 cm.
Volume = length x width x height
Volume = s x s x s
Volume = 11 x 11 x 11
Volume = 1331 cm3
Example 2: What is the volume of a cube of side 15 cm?
Sol: Given,
Side of the cube = a = 15 cm
The volume of a Cube V = a3
V = 153 cm3
∴ V = 3375 cm3
Example 3: If the volume of a cube is 216 cm3, then what is the measure of the edge of a cube?
Solution:Given, Volume of a cube = V = 216 cm3
We know that, V = (side)3 or (edge)3
(edge)3 = 216 = 63
Therefore, edge of the cube = 6 cm
Example 1: The weight of a 5 rupee coin is 9 g. How many coins are there in a sack of 5 rupee coins if it weighs 27 Kg?
Sol: The weight of a 5 rupee coin is 9 g, and the weight of a sack is 27Kg.
We know that 1Kg =1000g.
Step1: Find the total weight of sack = Weigh of sack × 1000 = 27 × 1000 = 2700.
Step2: Write the weight of each coin = 9 g
Step3: Number of coins = Total Weight of sack ÷
Weight of each coin= 2700 ÷ 9 = 300
So, the number of coins is 300.
Example 2: A 2 rupee coin weight 5 g. What is the weight of a sack with 2000 coins?
Sol: Step1: Write the weight of each coin = 5 g
Step2: Write the total number of coins = 2000
Step3: Find the total weight of sack = Total number of coins × weight of each coin = 2000 × 5 g = 10,000 g.
So, the total weight of the sack is 10,000 g.
28 videos|169 docs|41 tests
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1. What is the difference between volume and weight? |
2. How can I measure the volume of a coin or a marble? |
3. Why is it important to understand the volume of objects like coins and marbles? |
4. Can different shapes of the same volume have different weights? |
5. How does temperature affect the volume of materials like coins and marbles? |
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