Q.1. What is Principal Quantum Number (N)?
The foundation of orbitals chemistry starts with Bohr who established that electron orbitals represent an energy level in terms of their distance from the Nucleus. The Orbitals are named K, L, M, N… or 1, 2, 3, 4… in ascending order. These numbers are the Principal Quantum Numbers. A Principal Quantum number is denoted as 'n'. For example, for the K-orbital n = 1, for L-orbital n = 2, for M-orbital n = 3.
Q.2. What is the Azimuthal Quantum Number (L)?
Arnold Sommerfeld delved deeper into the orbitals chemistry, he viewed every orbital energy level or shell is made up of many subshells. He imagined that other than the circular orbits that Bohr established, there are elliptical orbits as well. The Azimuthal or Subsidiary quantum number helps to determine the ellipticity of the subshells. It is generally denoted as ‘l’.
To denote the value of 'l' instead of 1, 2, 3… some spectroscopic symbols are used -
It should be noted that the subshells are energy levels as well, called Subsidiary orbital energy levels, so if we sort the subshells in ascending order in terms of their energy levels, it would be s < p < d < f.
This equation is used for a single electron orbiting a single nucleus of charge +Z.
With the increase in quantum number, n increases (holding Z constant), and the energy increases i.e. it becomes less negative. In the limit that n goes to infinity then the energy goes to zero. With the increase in artitary charge, z, the energy decreases i.e. it becomes more negative.
A higher Z means a more positively charged nucleus, therefore it holds the electron tighter.
Q.3. Which Factors Affect Orbital Energy?
The s orbital electron is more tightly bound to the nucleus in comparison to the p orbital electron, which is more tightly bound with respect to a d orbital electron for a given value of the principal quantum number.
The orbital energy decreases in the same subshell with the increase in the atomic number (Zeff).
As compared to p orbital electrons, s orbital electrons have lesser amounts of energy and are more negative. In this case, the p orbital electrons will have lesser energy than that of d orbital electrons.
The extent of shielding from the nucleus is different for the electrons in different orbitals. Hence, it leads to the splitting of energy levels that have the same principal quantum number. Hence, the orbital energy depends on the values of both the principal quantum number and azimuthal quantum number, which are symbolized as n and l respectively. Therefore, the lower the value of (n + 1) for an orbital, the lower is its energy.
The Energy of Orbital in Hydrogen Atom
The energy of an electron in a hydrogen atom is calculated solely by the principal quantum, m (n). Therefore, the energy of the orbitals in hydrogen atom increases as follows :
1s < 2s = 2p < 3s = 3p = 3d <4s = 4p = 4d = 4f <..
The shapes of 2s and 2p orbitals are different, an electron has the same energy when it is in the 2s orbital as when it is present in a 2p orbital. The orbitals which have the same energy are called degenerate orbitals, whereas the orbitals which have the same energy are called degenerate orbitals.
The 1s orbital in a hydrogen atom is the most stable condition and is called the ground state and an electron living in this orbital is most strongly sustained by the nucleus. An electron in the 2s, 2p or higher orbitals in a hydrogen atom is in an excited state.
Q.4. Which of these orbitals has a lower orbital energy level 3d or 4s?
The n + l value of 3d orbital is (3 + 2) = 5, Similarly the (n + l) value of 4s is (4 + 0) = 5.
So the 4s orbital has a higher (n+l) value, thus has a higher orbital energy level.
3d
Q.5. Which of these orbitals has a higher orbital energy level 3d or 4p?
The (n+l) value of 3d orbital is (3+2) = 5, and 4p orbital is (4+1)=5. Both have the same (n+l) value with 3d having a lower n-count; thus, it is weaker and has a lower orbital energy level.
3d
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1. How does orbital energy vary with atomic number? |
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