The value of the modulus function is always non-negative. If f(x) is a modulus function, then we have:
This means if the value of x is greater than or equal to 0, then the modulus function takes the actual value, but if x is less than 0 then the function takes minus of the actual value 'x'.
We can apply the modulus function to any real number. The range of the modulus function is the set of non-negative real numbers which is denoted as (0,∞) and the domain of the modulus function is R (where R refers to the set of all real numbers). Hence, the domain of the modulus function is R and the range is (0,∞).
Now, that we know the modulus function formula, let us consider a few examples to understand its application. The steps to calculate modulus function are given below:
Example: Consider the modulus function f(x) = |x|.
Note that f(-3) = f(3) here. In other words, |3| = |-3| = 3.
Now let us see how to plot the graph for a modulus function. Let us consider x to be a variable, taking values from -5 to 5. Calculating modulus for the positive values of 'x', the line plotted in the graph is 'y = x' and for the negative values of 'x', the line plotted in the graph is 'y = -x'.
Now, that we have the formula for the modulus function and the graph of the modulus function, let us now explore the properties of the modulus function:
Since we know that a modulus function f(x) = |x| is equal to x if x > 0 and -x if x < 0, therefore the derivative of modulus function is 1 if x > 0 and -1 if x < 0. The derivative of the modulus function is not defined for x = 0. Hence the derivative of modulus function can be written as d(|x|)/dx = x/|x|, for all values of x and x not equal to 0.
Using the formula of the modulus function and integration formulas, the integral of the modulus function is (1/2)x2 + C if x ≥ 0, and its integral is -(1/2)x2 + C if x < 0. Hence the integration of the modulus function can be clubbed as:
Important Notes on Modulus Function
Example 1: Find the value of the modulus function |x| for x = -5 and x = 10
If x = -5, then |x| = |-5| = 5
If x = 10, then |x| = |10| = 10|x| = 5 for x = -5 and |x| = 10 for x = 10
Example 2: Solve |x + 3| = 8 using modulus function definition.
We know that the modulus function value is always non-negative, therefore we have two cases:
If x + 3 > 0, then |x + 3| = x + 3 and if x + 3 < 0, then |x + 3| = -(x + 3).
Case 1: If x + 3 > 0, we have
|x + 3| = x + 3
⇒ x + 3 = 8
⇒ x = 8 - 3 = 5
Case 2: If x + 3 < 0, we have
|x + 3| = -(x + 3)
⇒ -(x + 3) = 8
⇒ -x - 3 = 8
⇒ x = -3 - 8 = -11
Hence, the solution is x = 5, -11
Example 3: Solve the inequality |x - 1| < 3.
Here, 3 > 0. So by the properties of modulus function,
-3 < x - 1 < 3
Adding 1 on all the sides,
-3 + 1 < x < 3 + 1
-2 < x < 4
The solution of the given inequality is -2 < x < 4.
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