Table of contents | |
Electrolysis of an Aqueous Solution Using Inert Electrodes | |
Electrode Reactions | |
Solved Examples | |
Determining what Gas is Produced |
We now have an electrolyte that contains ions from the compound plus ions from the water
Which ions get discharged and at which electrode depends on the relative reactivity of the elements involved
Note: The concentration of the solution can affect the products of electrolysis, however, this is beyond the scope of this course and you are not expected to know the specific details of this
Exam Tip
When answering questions on this topic, it helps if you first write down all of the ions present first. Only then you should start comparing their reactivity and deducing the products formed.
The reactivity series of metals including hydrogen and carbon
- Work out what ions are attracted to the cathode
- Hydrogen (H+) and magnesium (Mg2+)
- Decide which element will be discharged:
- The less reactive element is usually formed
- Hydrogen is discharged at the cathode as it is less reactive than magnesium
- Work out what ions are attracted to the anode
- Hydroxide (OH-) and iodide (I-)
- Decide which element will be discharged:
- If a halide is present, the corresponding halogen is formed, otherwise, oxygen is formed
- Iodine is discharged at the anode as iodide ions are present
Example 2: Predict the products formed at each electrode in the electrolysis of copper sulfate solution
- Work out what ions are attracted to the cathode
- Hydrogen (H+) and copper (Cu2+)
- Decide which element will be discharged:
- The less reactive element is usually formed
- Copper is discharged at the cathode as it is less reactive than hydrogen
- Work out what ions are attracted to the anode
- Hydroxide (OH-) and sulfate (SO42-)
- Decide which element will be discharged:
- If a halide is present, the corresponding halogen is formed, otherwise, oxygen is formed
- Oxygen is discharged at the anode as no halide ions are present
Exam Tip
Once you have identified the ions, the next step is to decide towards which electrode will they be drawn and identify the product formed. It helps if you recall the reactivity series.
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