Table of contents | |
Forces & Rotation | |
The Moment of a Force | |
The Principle of Moments | |
Solved Example |
If two forces act on an object without passing through the same point, then the object can still rotate
If the forces are equal and opposite, this is known as a couple
The above forces are balanced, but will still cause the object to rotate clockwise as they don’t act through a common point
Tip: The units of a moment is Newton metres (N m), but can also be Newton centimetres (N cm) ie. where the distance is measured in cm insteadIf the exam question doesn't ask for a specific unit, always convert the distance into metres
Tip: Make sure that all the distances are in the same units and you’re considering the correct forces as clockwise or anticlockwise, as seen in the diagram below
Clockwise is defined as the direction the hands of a clock move (and anticlockwise as the opposite)
Example: A parent and child are at opposite ends of a playground see-saw. The parent weighs 690 N and the child weighs 140 N. The adult sits 0.3 m from the pivot. Calculate the distance the child must sit from the pivot for the see-saw to be balanced.
Step 1: List the know quantities
Clockwise force (child), Fchild = 140 N
Anticlockwise force (adult), Fadult = 690 N
Distance of adult from the pivot, dadult = 0.3 mStep 2: Write down the relevant equation
Moment = force × distance from pivot
For the see-saw to balance, the principle of moments states that
Total clockwise moments = Total anticlockwise momentsStep 3: Calculate the total clockwise moments
The clockwise moment is from the child
Momentchild = Fchild × dchild = 140 × dchildStep 4: Calculate the total anticlockwise moments
The anticlockwise moment is from the adult
Momentadult = Fadult × dadult = 690 × 0.3 = 207 NmStep 5: Substitute into the principle of moments equation
140 × dchild = 207Step 6: Rearrange for the distance of the child from the pivot
dchild = 207 ÷ 140 = 1.48 m
124 videos|149 docs|37 tests
|
|
Explore Courses for Grade 10 exam
|