CBSE Class 8  >  Class 8 Notes  >  Mathematics (Maths)   >  Worksheet Solutions: Comparing Quantities

Class 8 Maths - Comparing Quantities CBSE Worksheets Solutions

Multiple Choice Questions

Q1: The ratio of 50cm to 2.5m is
(a) 10 : 1
(b) 5 : 1
(c) 1 : 5
(d) None of these

Ans: (c)
We know that, 1m = 100cm
2.5m  =  2.5 × 100  =  250cm
Ratio of 50cm to 2.5m = Multiple Choice Questions


Q2: The number of unelectrified villages in India decreased from 18,000 to 12,000 in last 6 years. What is the percentage of decrease?
(a) 30%
(b) 50%
(c) Multiple Choice Questions

(d) None of these.
Ans: (c)
Multiple Choice Questions


Q3: Cost of an item is Rs. 50. It was sold with a profit of 12%. Find the selling price
(a) Rs.56
(b) Rs. 60
(c) Rs.70
(d) None of these.

Ans: (a)
We know that
Cost Price = Rs. 50
and, Profit % = 12
Therefore, Profit = Multiple Choice Questions
⇒ Profit = 6
⇒ S.P. = C.P. + Profit
⇒ S.P. = 50 + 6
⇒ S.P. = Rs 56


Q4: The simple interest on Rs.6000 for 1 year at 4% per annum is
(a) Rs.126.50
(b) Rs.240
(c) Rs.43
(d) None of these

Ans: (b)
Multiple Choice Questions


Q5: The fraction form of 45% is
(a) 3/20
(b) 9/20
(c) 11/20
(d) 13/2
Ans: (b)
45% = 45/100 = 9/20


Q6: The fraction form of 60% is
(a) 3/5
(b) 4/5
(c) 3/10
(d) 7/10

Ans: (a)
60% = 60/100 = 6/10 = 3/5


Q7: The percent form of 3.05 is
(a) 61/20%
(b) 61/50%
(c) 305%
(d) 350%

Ans: (c)
3.05 x 100% = 305/100 x 100 = 305%


Q8: The Decimal form of 21% is
(a) 0.21
(b) 2.1
(c) 21
(d) 210

Ans: (a)
21%  = 21/100 = 0.21


Q9: The decimal form of 300% is
(a) 0.3
(b) 0.03
(c) 3.0
(d) 30.0

Ans: (c)
300% = 300/100 = 3.0


Q10: 35% of 1 kg is equal to
(a) 3.5 GM
(b) 35 GM
(c) 350 GM
(d) 3.5 KG

Ans: (c)
35%  x 1000gm
35/100 x 1000gm = 350gm        


Answer the following Questions

Q1: A school trip is being planned in a school for class VIII. Girls are 60% of the total strength and are 18 in number. Find the ratio of number of boys to number of girls.
Ans:
Let ‘x’ be the total number of students.
Thus, number of girls = 60% of x = 18
Answer the following Questions

Number of boys = (Total number of students) - (Total number of girls)
= 30 – 18
= 12.
Hence ratio of number of boys to girls is
= 12 : 18
= 2 : 3.

Q2: In a constituency there are 120 voters 90 of them voted Yes. What percent voted Yes?
Ans: Given:
Number of voters = 120
Number of voters who voted Yes = 90
Answer the following Questions


Q3: If Rs. 250 is divided among Rakshith, Ravi and Raju. So that Rakshith gets 3 parts, Ravi gets 2 parts and Raju gets 5 parts. How much money will each get in percentages?
Ans: Given: total amount = 250
Total number of parts = 10

Answer the following Questions


Q4: My grandmother says in her childhood milk was at Rs.2 per litre. It was Rs.36 per litre today. By what percentage has the price gone up?
Ans: Given:
Old value = Rs. 2 per litre
New price = Rs. 36 per litre
Answer the following Questions
=1700%.


Q5: The cost of a toy car is Rs. 140. If the shopkeeper sells it at a loss of 10%. Find the price at which it is sold.
Ans: 
Given:
C.P. of toy car = Rs. 140
Loss% = 10%
S.P. = ?
We know that,
Answer the following Questions
Loss = C.P. – S.P.
S.P. = C.P. – Loss
S.P. = 140 – 14
S.P. = Rs.126


Q6: Rashida purchased an air-conditioner for Rs. 3400 including a tax of 10%. Find the actual price of the air conditioner before VAT was added.
Ans: 
Let ‘x’ be the cost before adding VAT.
VAT = 10% of x = 0.1x
Cost after adding VAT = x + 0.1x = 1.1x
Given: cost = Rs.3,400
1.1x  =  Rs. 3400
Answer the following Questions
Thus, the price of an air-conditioner = Rs. 3090.9.


Q7: At what rate of simple interest will the sum double itself in 2 years?
Ans: We know that,
A = S.I. + P
Where,Answer the following Questions
Given: A  =  2 × principle  = 2P
Time = t = 2 years

R = ?
Formula becomes 2P = S.I. + P

Answer the following Questions
Therefore, at the rate of 50%, the sum will double.


Q8: In what time will Rs. 1600 amount to Rs. 1768 at 6% per annum simple interest?
Ans:
Given:
Principle = Rs. 1600
Amount = Rs. 1768
Rate = 6% per year
Time = ?
A = S.I. + P
Answer the following Questions


Q9: What amount Harish has to pay at the end of 2 years of Rs. 40,000 at an interest of 16% compounded annually?
Ans: 
We know that, formula for compound interest,
Answer the following Questions
Where, P = principle
N = no. of years
P = Rs. 40,000, R = 16%, n = 2.
Answer the following Questions
Amount paid by Harish at the end of 2 years is Rs. 53,824.


Q10: Mahesh sells two tables for Rs. 3000 each. He gains 20% on one table and on the other he loses 20%. Find his gain or loss percent on whole transaction.
Ans: For the first table: given:
S.P. = Rs. 3000
Gain% = 20% = Answer the following Questions
Gain percent implies increased percent on cost price.
For Rs.100 cost price, the gain = Rs.20
S.P. = C.P. + gain
S.P. = 100 + 20 = Rs.120
Thus, S.P. is Rs. 120 when C.P. is Rs.100
Therefore, for S.P. of Rs. 3000, the cost price will be
Answer the following Questions
For second table,
S.P. = Rs.300
Loss percent = 20% =Answer the following Questions
Loss percent decreases percent on cost price.
For Rs.100 of C.P., loss = Rs.20
S.P. = C.P. – loss = 100 – 20 = Rs.80.
Thus, S.P. is Rs.80 when C.P. is Rs.100
For S.P. of Rs.3000, the cost price is given by

Answer the following Questions
Total cost price = 2500 + 3750 = 6250
Total S.P. = 2500 + 3750 = 6000
Here, S.P. < C.P., Hence loss is Occured
Loss = C.P. – S.P. = 6250 – 6000 = 250

Loss percent =Answer the following Questions
Therefore, there is a loss of 4% on whole transaction.


Q11: Prateeksha went to a shopping mall to purchase a saree. Marked price of the saree is Rs.1000. Shop owner gave a discount of 20% and then 5%.Find the single discount equivalent to these 2 successive discounts.
Ans: 

Answer the following Questions

Q12: Rajanna purchased 25 dozen bananas for RS. 625. He spent Rs. 125 for transportation. He could not sell 5 dozen bananas as they were spoiled. He sold the remaining banana’s at Rs. 30 for each dozen. Find loss and profit percent.
Ans: 
Total cost price = Cost price of bananas + transportation charge
=Rs. 625  +  Rs. 125  =  Rs. 750
Number of dozens of bananas sold = No. of purchased – No. of spoiled
= 25 – 5
= 20
Given: 1 dozen = Rs.30
Therefore, S.P. = 20×30=Rs.600
Since, S.P. < C.P., it is a loss
Loss = C.P. – S.P. = 750 – 600 = 150

Answer the following Questions

The document Worksheet Solutions: Comparing Quantities is a part of the Class 8 Course Mathematics (Maths) Class 8.
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FAQs on Worksheet Solutions: Comparing Quantities

1. What is the concept of comparing quantities in Class 8 mathematics?
Ans. The concept of comparing quantities in Class 8 mathematics involves understanding and analyzing the relationship between two quantities. It includes comparing quantities using various mathematical operations such as addition, subtraction, multiplication, and division. Students learn to solve problems related to ratios, percentages, profit and loss, discounts, and simple interest, among others.
2. How can I compare two quantities using ratios and proportions?
Ans. To compare two quantities using ratios and proportions, you need to express both quantities in the form of a ratio. A ratio is a comparison of two numbers or quantities. Once you have the ratios, you can compare them to determine their relationship. For example, if the ratio of apples to oranges is 3:2, it means that for every 3 apples, there are 2 oranges. By comparing the ratios, you can analyze which quantity is larger or smaller.
3. What is the significance of understanding profit and loss in comparing quantities?
Ans. Understanding profit and loss is significant in comparing quantities as it helps in analyzing the financial outcome of a business transaction. By calculating the profit or loss percentage, students can compare different business deals or investments and make informed decisions. It also aids in understanding the concept of selling price, cost price, and calculating the profit or loss incurred.
4. How can I calculate simple interest to compare quantities?
Ans. Simple interest is calculated using the formula: Simple Interest = (Principal × Rate × Time) / 100. By using this formula, you can calculate the interest earned or paid on a certain amount of money over a specific period. Comparing the amounts of interest earned or paid allows you to analyze the profitability or cost-effectiveness of different investments or loans.
5. How can I apply the concept of comparing quantities in real-life situations?
Ans. The concept of comparing quantities is applicable in various real-life situations. For example, you can use it to compare prices of different products to find the best deal, calculate discounts during shopping, analyze profit or loss in a business venture, compare interest rates offered by different banks, or determine the percentage increase or decrease in a population. Understanding and applying this concept helps in making informed decisions and solving everyday problems.
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