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Worksheet Questions And Solutions : Comparing Quantities

Multiple Choice Questions

Q1: The ratio of 50cm to 2.5m is
(a) 10 : 1
(b) 5 : 1
(c) 1 : 5
(d) None of these

Ans: (c)
We know that 1m = 100cm
2.5m  =  2.5 × 100  =  250cm
Ratio of 50cm to 2.5m = Multiple Choice Questions


Q2: The number of unelectrified villages in India decreased from 18,000 to 12,000 in the last 6 years. What is the percentage of decrease?
(a) 30%
(b) 50%
(c) Multiple Choice Questions

(d) None of these.
Ans: (c)
Multiple Choice Questions


Q3: Cost of an item is Rs. 50. It was sold with a profit of 12%. Find the selling price
(a) Rs.56
(b) Rs. 60
(c) Rs.70
(d) None of these.

Ans: (a)
We know that
Cost Price = Rs. 50
and, Profit % = 12
Therefore, Profit = Multiple Choice Questions⇒ Profit = 6⇒ S.P. = C.P. + Profit
⇒ S.P. = 50 + 6
⇒ S.P. = Rs 56


Q4: The simple interest on Rs.6000 for 1 year at 4% per annum is
(a) Rs.126.50
(b) Rs.240
(c) Rs.43
(d) None of these

Ans: (b)
Multiple Choice Questions


Q5: The fraction form of 45% is
(a) 3/20
(b) 9/20
(c) 11/20
(d) 13/2
Ans:(b)
45% = 45/100 = 9/20


True false 

Q1. State whether the following statements are true  or false :

(a) If the cost price of an item is more than the selling price, there is a profit.
Ans. False (If the cost price is more than the selling price, it results in a loss, not profit.)

(bThe formula for percentage is Percentage = ValueTotal/Value×100
Ans. False

True false 

(cSimple Interest is calculated using the formula SI = P×R×T/100, where P is the principal, R is the rate of interest, and T is the time in years.
Ans. True

(dDiscount is always calculated on the cost price of an item.
False (Discount is calculated on the marked price of an item.)

(eThe ratio of two quantities with the same units is expressed in the form of a fraction.
Ans. True

Answer the following Questions

Q1: Find the rate of discount given on a shirt whose selling price is ₹1092 after deducting a discount of ₹208 on its marked price.

Ans. We know that the SP = ₹1092

The discount = ₹208

By using the formula market price = SP + Discount

= 1092 + 208 = ₹1300

∴ The discount % = (discount/market price) × 100

= (208/1300) × 100 = 16%


Q2: In a constituency, there are 120 voters, 90 of them voted Yes. What per cent voted Yes?
Ans: Given:
Number of voters = 120
Number of voters who voted Yes = 90
Answer the following Questions
Q3: A particular football team won 10 matches out of all the total number of matches they played. If their winning percentage was 40 %, how many matches did they play?
Ans:

Winning percentage

= Matches won/Total matches played × 100

Total matches played = 10 × 100 ÷ 40

Total matches = 25

Ans: The team played 25 matches.


Q4: My grandmother says in her childhood milk was at Rs.2 per litre. It was Rs.36 per litre today. By what percentage has the price gone up?
Ans: Given:
Old value = Rs. 2 per litre
New price = Rs. 36 per litre
Answer the following Questions=1700%.

Q5: The cost of a toy car is Rs. 140. If the shopkeeper sells it at a loss of 10%. Find the price at which it is sold.
Ans: 
Given:
C.P. of toy car = Rs. 140
Loss% = 10%
S.P. =?
We know that,
Answer the following QuestionsLoss = C.P. - S.P.S.P. = C.P. - Loss
S.P. = 140 - 14
S.P. = Rs 126


Q6: Rashida purchased an air-conditioner for Rs. 3400, including a tax of 10%. Find the actual price of the air conditioner before VAT was added.
Ans: 
Let 'x' be the cost before adding VAT.
VAT = 10% of x = 0.1x
Cost after adding VAT = x + 0.1x = 1.1x
Given: cost = Rs.3,400
1.1x  =  Rs. 3400
Answer the following QuestionsThus, the price of an air-conditioner = Rs. 3090.9.

Q7: At what rate of simple interest will the sum double itself in 2 years?
Ans: We know that,
A = S.I. + P
Where,Answer the following QuestionsGiven: A  =  2 × principle  = 2PTime = t = 2 years

R =?
Formula becomes 2P = S.I. + P

Answer the following QuestionsTherefore, at the rate of 50%, the sum will double.

Q8: At what time will Rs. 1600 amount to Rs. 1768 at 6% per annum simple interest?
Ans:
Given:
Principal = Rs. 1600
Amount = Rs. 1768
Rate = 6% per year
Time = ?
A = S.I. + P
Answer the following Questions
Q9: What amount does Harish have to pay at the end of 2 years of Rs. 40,000 at an interest of 16% compounded annually?
Ans: 
We know that, formula for compound interest,
Answer the following QuestionsWhere, P = principleN = no. of years
P = Rs. 40,000, R = 16%, n = 2.
Answer the following QuestionsAmount paid by Harish at the end of 2 years is Rs. 53,824.

Q10:Compute the amount and compound interest on the principal amount ₹ 10,800 for 3 years at 12½ % per annum compounded annually.

Ans: Principal (P) = ₹ 10,800

Rate (R) = 12½ % = 25/2 % (annual) 

Number of years (n) = 3

Amount (A) = P(1 + R/100)n

= 10800(1 + 25/200)3

= 10800(225/200)3

= 15377.34375

= ₹ 15377.34 (approximately)

Compound interest = A - P  = ₹ (15377.34 - 10800) = ₹ 4,577.34

The document Worksheet Questions And Solutions : Comparing Quantities is a part of the Class 8 Course Mathematics (Maths) Class 8.
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FAQs on Worksheet Questions And Solutions : Comparing Quantities

1. What is the difference between simple interest and compound interest in comparing quantities?
Ans.Simple interest is calculated on the principal amount only, while compound interest is calculated on the principal plus any interest that has already been added. This means that compound interest grows faster than simple interest over time.
2. How do you calculate percentage increase or decrease when comparing quantities?
Ans.To calculate percentage increase, subtract the original quantity from the new quantity, divide the result by the original quantity, and then multiply by 100. For percentage decrease, use the same formula but subtract the new quantity from the original quantity.
3. What are some real-life applications of comparing quantities?
Ans.Real-life applications of comparing quantities include budgeting, calculating discounts during sales, understanding interest rates for loans, and analyzing profit margins in business.
4. How can proportions be used when dealing with comparing quantities?
Ans.Proportions allow you to set up equations that show the relationship between two quantities. By using cross-multiplication, you can find unknown quantities when you know one quantity and its corresponding proportion.
5. What are the common mistakes to avoid when comparing quantities?
Ans.Common mistakes include not converting units properly, miscalculating percentages, and failing to account for all relevant quantities in a comparison. It's important to double-check calculations and ensure all data is correctly interpreted.
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