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Long Question Answer: Comparing Quantities

Q1. Mohit sold a T.V. for Rs. 3,600, gaining one-sixth of its selling price. Find the gain (in Rs.)
Ans:

Given, S.P. = Rs. 3600
Gain = 3600 / 6
= Rs. 600

Q2. A man buys a certain number of articles at a rate of 15 for Rs. 112.50 and sells them at a rate of 12 for Rs. 108. Find His gain as percentage;
Ans:

Cost price of one article = 112.50/15 = 22.5/3 = Rs. 7.5
Selling price of one article = 108/12 = Rs. 9
Profit on one article = Rs. 9 - Rs. 7.5 =  Rs. 1.5
Profit % = Profit / Cost Price x 100 = 1.5/7.5 x 100 = 20%

Q3. By selling a certain number of goods for Rs. 5,500, a shopkeeper loses equal to one-tenth of their selling price. Find the loss.
Ans:

Given, S.P.=Rs5500
Now as per given condition
Loss = 5500 / 10 = Rs. 550

Q4. A shopkeeper makes a profit of 20% on selling a transistor radio for Rs. 840. For how much should he sell another transistor radio, whose cost price is Rs. 25 more than the first one, to make the same percentage profit ?
Ans:
Case 1:

S.P of transistor = 840  Rs.
Profit = 20%
Then C.P.= 100/120 x 840 = 700 Rs.
Case 2:
C.P.of transistor = 700 + 25 = 725 Rs.
Profit = 20%
ThenS.P = 120/100 x 725 = Rs. 870

Q5. By selling tea for Rs 67.20 per kg, a profit of 12% is made, Find quantity of tea ( in kg ) bought and sold in order to gain Rs 144.
Ans:

Given,  Profit % by selling 1 kg of tea = Long Question Answer: Comparing Quantities

Long Question Answer: Comparing Quantities
67.20-C.P. = 0.12C.P.
1.12C.P. = 67.20
C.P.=Rs60
Profit per kg = SP - CP = Rs67.20 - Rs60 = Rs7.20
To gain Rs144, number of kg of tea bought and sold = 144/7.20 = 20kg

Q6. State true or false:In △ABC, AD is the median and DE is parallel to BA, where E is a point in AC and hence BE is parallel to BC
A. True
B. False
Ans:

Long Question Answer: Comparing QuantitiesGiven: AD is the median of △ABC. Hence, BD = DC.
Also, DE ∥ AB and DE is drawn from the mid point of AC, i.e. D.
Thus, by converse of mid-point theorem, DE bisects the third side, which is AC.
Then, E is the mid point of AC.
Hence, BE is the median of △ABC.
That is, the given statement is false and option B is correct.

Q7. An article marked at Rs.1000 is sold at a discount of 20%.. Find selling price of the article in Rs.
Ans: 
Since, Market price of an article = Rs.1000
Discount% = 20%
Discount = 1000 × 20/100 = Rs. 200
Selling price = Market price - Discount
= 1000  - 200
= Rs.800

Q8. A dealer is selling an article at a discount of 5 % on the marked price and its marked price is Rs. 140. What is the cost price, if the marked price is 12% above the cost price?
Ans:

Let the cost price be Rs. x
12% above = Rs. 1.12x
⇒ 1.12x = 140
⇒ x = 140 x 100 / 112 = Rs. 125
Therefore, the cost price of an article is Rs. 125.

Q9. A chair is bought by a trader  at 20% discount on its marked price. The marked price is Rs 7,200. If he sells it at 16% discount on its marked price, find the profit percent made in the whole transaction.
Ans:

Brought cost of chair after 20% discount = 7200 x 80 / 100 = 5760
Selling cost after 16% discount = 7200 x 84 / 100 = 6048
Profit on chair = 6048 - 5760 = 288 Rs
% of profit = 288 x 100 / 5760 = 5 %

Q10. The profit earned after selling an article for Rs. 625 is the same as loss incurred after selling the article for Rs. 435. What is the cost price of the article?
Ans:

Let the C.P. = Rs x
Then according to the question
625 - x = x-435
2x = 625 + 435
2x = 1060
x = 530
Hence C.P. of the article =Rs.530

Q11. Mohan bought 20 dining tables for Rs. 12000 and sold them at a profit equal to the selling price of 4 dining tables. The selling price of each dining table is?
Ans:

Profit = (S.P. of 20 tables) - (C.P. of 20 tables)
⇒ S.P. of 4 tables = S.P. of 20 tables - C.P. of 20 tables
⇒ S.P. of 16 tables = C.P. of 20 tables = Rs. 12000
⇒ S.P. of 1 dining table = Rs. 12000 / 16 = Rs. 750

Q12. If a merchant estimates his profits as 20 % of the selling price, what is his real profit percent.
Ans:

Suppose SP = Rs. 100
Profit = Rs. 20
CP = 100 - 20 = Rs. 80
Profit % = Profit / CP x 100
= 20/80 x 100
= 25%

Q13. The shopkeeper gives a discount of 12% on the pair of shoes marked for Rs. 1425, then S.P is:
Ans:

Given M.P. = Rs. 1425
Discount = 12% of Rs. 1425 = 12/100  x 1425
= Rs. 171
Selling price of shoes = Rs. (1425-171) = Rs. 1254.

Q14. A scientific calculator is available at Universal shop in Hazratganz at 20% discount and the same is available at only 15% discount at Bhootnath market. Pooja has just sufficient amount of Rs.800 to purchase it at Universal shop, Hazratganz. What is the amount that Pooja has less than the required amount to purchase it at Bhootnath?
Ans:

Let cost of calculator is Rs.10
Calculator is available at Universal shop in Hazratganj at 20% discount then sell cost =100-20=80 RS
Pooja paid Rs.800 at Universal shop
So actual cost of calculator = 800 /80 x 100 = 1000
same as 15% discount at Bhootnath market
Then selling price of calculator at bhootnath market = 85/100 x 1000 = 850 Rs.
Amount that Pooja has less paid = 850 - 800 = Rs.50

Q15. Nitesh & Jitesh invested Rs.15000 and Rs.18000 respectively in a business. If the total profit at the end of the year is Rs.8800 and Nitesh being an active partner gets an additional 12.5% of the profit. Find the total profit of Nitesh.
Ans:

Profit sharing ratio =15000:18000=5:6
Total profit =8800
Nitesh gets 12.5 % of the profit = 12.5/100 x 8800 = Rs. 1100
Net profit = 8800 - 1100 = Rs.7700
Nitesh share in profit = 5/5 + 6 x 7700 = Rs. 3500
Total profit of Nitesh = 3500 + 1100 = Rs.4600

The document Long Question Answer: Comparing Quantities is a part of the Class 7 Course Mathematics (Maths) Class 7 (Old NCERT).
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FAQs on Long Question Answer: Comparing Quantities

1. What is the concept of comparing quantities in mathematics?
Ans. Comparing quantities in mathematics involves evaluating two or more amounts to determine their relative sizes, differences, or ratios. This is essential for understanding relationships between numbers and can be applied in various contexts, such as finance, statistics, and everyday problem-solving.
2. How can ratios be used to compare quantities?
Ans. Ratios are a way of expressing a relationship between two quantities by division. For example, if there are 2 apples and 3 oranges, the ratio of apples to oranges is 2:3. This allows for a comparison of the quantities in a straightforward manner, highlighting their proportional relationship.
3. What role do percentages play in comparing quantities?
Ans. Percentages are used to express a quantity as a fraction of 100, making it easier to compare different amounts. For example, if a student scores 80 out of 100 in one exam and 60 out of 80 in another, converting these scores to percentages allows for a direct comparison of performance across different contexts.
4. Can you explain the importance of unit conversion in comparing quantities?
Ans. Unit conversion is crucial in comparing quantities because it ensures that the amounts being compared are expressed in the same units. For instance, if comparing distances measured in kilometres and miles, converting both to either unit allows for an accurate comparison of lengths.
5. What strategies can be employed to solve problems involving the comparison of quantities?
Ans. Effective strategies for solving comparison problems include identifying the quantities involved, determining the relationship (ratio, percentage, etc.), performing necessary calculations (such as conversions or simplifications), and interpreting the results in the context of the problem to draw meaningful conclusions.
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