Class 8 Exam  >  Class 8 Notes  >  Mathematics (Maths) Class 8  >  Short Question Answer: Comparing Quantities

Class 8 Maths Chapter 7 Question Answers - Comparing Quantities

Q1: A number is increased by 20% and then it is decreased by 20%. Find the net increase or decrease per cent.
Ans:
Let the number be 100
20% increase Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
Increased value = 100 + 20 = 120
Now it is decreased by 20%
Decreased value Class 8 Maths Chapter 7 Question Answers - Comparing Quantities

Net decrease = 100 – 96 = 4
Decrease per cent Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
Hence, the net decrease per cent = 4%

Q2: A man whose income is ₹ 57,600 a year spends ₹ 43,200 a year. What percentage of his income does he save?
Ans:

Annual income of a man = ₹ 57,600
Amount spent by him in the year = ₹ 43,200
Net amount saved by him = ₹ 57,600 – ₹ 43,200 = ₹ 14,400
Percentage of his annual saving Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
Hence, the saving percentage = 25%

Q3: Two candidates Raman and Rajan contested an election. Raman gets 46% of the valid votes and is defeated by 1600 votes. Find the total number of valid votes cast in the election.
Ans:

Let the total number of valid votes be 100
Number of votes got by Raman = 46% of 100 Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
Number of votes got by Rajan = 100 – 46 = 54
Difference between the votes = 54 – 46 = 8
8% of Valid votes = 1,600
Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
Hence, the total number of valid votes = 20,000

Q4: A car is marked at ₹ 3,00,000. The dealer allows successive discounts of 6%, 4% and Class 8 Maths Chapter 7 Question Answers - Comparing Quantities on it. What is the net selling price of it?
Ans:
 
Marked price of the car = ₹ 3,00,000
Net selling price after the successive discounts
Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
Hence, the net selling price = ₹ 2,63,952

Q5: Find the amount of ₹ 6,250 at 8% pa compounded annually for 2 years. Also, find the compound interest.
Ans:

Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
Class 8 Maths Chapter 7 Question Answers - Comparing Quantities

Q6: Vishakha offers a discount of 20% on all the items at her shop and still makes a profit of 12%. What is the cost price of an article marked at ₹ 280?
Ans:

Marked Price = ₹ 280
Discount = 20% of ₹ 280
Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
So selling price = ₹ (280 – 56) = ₹ 224
Let the cost price be ₹ 100
Profit = 12% of ₹ 100 = ₹ 12
So selling price = ₹ (100 + 12) = ₹ 112
If the selling price is ₹ 112, cost price = ₹ 100
If the selling price is ₹ 224, cost price = ₹ Class 8 Maths Chapter 7 Question Answers - Comparing Quantities  = ₹ 200

Q7: A CD player was purchased for ₹ 3,200 and ₹ 560 were spent on its repairs. It was then sold at a gain of Class 8 Maths Chapter 7 Question Answers - Comparing Quantities%. How much did the seller receive?
Ans:
 
Cost price of the CD player = ₹ 3,200
Amount spent on its repairing = ₹ 560
Net cost price = ₹ 3,200 + ₹ 560 = ₹ 3,760
Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
Hence, the required amount = ₹ 4,230

Q8: Ramesh bought a shirt for ₹ 336, including 12% ST and a tie for ₹ 110 including 10% ST. Find the list price (without sales tax) of the shirt and the tie together.
Ans:
List price of the shirt Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
List price of the tie Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
List price of both together = ₹ 300 + ₹ 100 = ₹ 400

Q9: Find the compound interest on ₹ 31,250 at 12% pa for Class 8 Maths Chapter 7 Question Answers - Comparing Quantities years.
Ans:

Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
Hence, compound interest = ₹10, 302

Q10: Find the compound interest on ₹ 48,000 for one year at 8% per annum when compounded half yearly.
Ans:
Principal (P) = ₹ 48,000
Rate (R) = 8% p.a.
Time (n) = 1 year
Interest is compounded half yearly
Class 8 Maths Chapter 7 Question Answers - Comparing Quantities
Therefore Compound Interest = A – P = ₹ (519,16.80 – 48,000) = ₹ 3,916.80.

The document Class 8 Maths Chapter 7 Question Answers - Comparing Quantities is a part of the Class 8 Course Mathematics (Maths) Class 8.
All you need of Class 8 at this link: Class 8
Are you preparing for Class 8 Exam? Then you should check out the best video lectures, notes, free mock test series, crash course and much more provided by EduRev. You also get your detailed analysis and report cards along with 24x7 doubt solving for you to excel in Class 8 exam. So join EduRev now and revolutionise the way you learn!
Sign up for Free Download App for Free
81 videos|413 docs|31 tests

Up next

81 videos|413 docs|31 tests
Download as PDF

Up next

Explore Courses for Class 8 exam
Related Searches

Extra Questions

,

Class 8 Maths Chapter 7 Question Answers - Comparing Quantities

,

Previous Year Questions with Solutions

,

study material

,

pdf

,

Summary

,

video lectures

,

MCQs

,

Free

,

practice quizzes

,

Objective type Questions

,

Class 8 Maths Chapter 7 Question Answers - Comparing Quantities

,

ppt

,

past year papers

,

Sample Paper

,

Semester Notes

,

shortcuts and tricks

,

Class 8 Maths Chapter 7 Question Answers - Comparing Quantities

,

mock tests for examination

,

Viva Questions

,

Important questions

,

Exam

;