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Important Formulas: Simplification & Approximation | SSC CGL Tier 2 - Study Material, Online Tests, Previous Year PDF Download

Simplification & Approximation

The simplification and approximation topic is one of the easiest in the numerical ability section and only efficient calculation can help a candidate solve questions from this section easily.
The main idea behind asking questions from the approximation and simplification topic is to test the ability of a candidate to work with numbers and basic calculations.
Questions are made to confuse the candidates with long decimal numbers and calculations which may seem complicated but this topic is one where a candidate can score most without making errors. 

The simplification questions can be asked in two ways:

  • Missing numbers – An equation can be given in the paper and candidates need to fill the blank in that equation, given either in LHS (Left-hand side) or RHS (Right-hand side).
    For example, 252 – _____ + 100 = 5 × 45 + 275. 
  • Simplifying the equation –  The second way in which the simplification questions may be asked is the direct way of giving an equation and solving it to find the answer. For example: 252 – 225 + 100 = ?. In such questions, candidates have to answer what comes in place of the question mark (?)

Solve Simplification/ Approximation Questions

To ensure that the candidate does not lose marks in this topic, there are some basic tips and tricks which may be used to solve the approximation and simplification questions. Refer to the tips given below:

  • Always solve the Approximation or simplification questions following the BODMAS rule. 
  • Numbers which are given in a decimal format, use a rounded-off value for those numbers. For example, 45.62 can be taken as 46, 22.10 can be taken as 22, etc. 
  • Learning tables till at least 20 can be of great help for the candidates and help them save some time
  • Remember the basic important formulas which can be used in such question:
    • (a+b)2 = a2 + b2 + 2ab
    • (a-b)2 = a2 + b2 – 2ab
    • a2 – b2 = (a+b) (a-b)
    • a3 + b3 = (a+b) (a2 – ab + b2)
    • (a+b)3 = a3 + b3 + 3ab (a+b)
    • (a-b)3 = a3 – b3 – 3ab (a-b)
  • Do not overcomplicate the questions and make sure that long calculations need to be skipped in order to solve the equations within the shorter time period

The image given below shows what is the BODMAS rule as mentioned in the first point of tips:

Important Formulas: Simplification & Approximation | SSC CGL Tier 2 - Study Material, Online Tests, Previous Year

Example 1: 98/3 % of 769.002 + 24% of 160.89 – 67.9900=?
(a) 220
(b) 224
(c) 225
(d) 226
(e) 227
Ans:
(d)
Divide the question into parts,
(98/3 % of 769.002) + (24% of 160.89) – 67.9900
⇒ 98/3 % of 769.002 = 33% × 769 = 254.77 = 255 —– (1)
⇒ 24% of 160.89 = 24% × 161 = 38.64 = 39 —– (2)
Finally,
255 + 39 – 68 = 294 – 68 = 226

Example 2: What shall come in place of question mark (?)
794.89 ÷ 15.001+ 767.99 ÷ 12.001 – 1273.012 ÷ 18.9968=?
(a) 42
(b) 35
(c) 50
(d) 55
(e) 47
Ans:
(c)
As per BODMAS,
The division needs to be done first.
794.89 ÷ 15.001 = 795 ÷ 15 = 53
767.99 ÷ 12.001 = 768 ÷ 12 = 64
1273.012 ÷ 18.9968 = 1273 ÷ 19 = 67
So, 53 + 64 – 67 = 117 – 67 = 50

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FAQs on Important Formulas: Simplification & Approximation - SSC CGL Tier 2 - Study Material, Online Tests, Previous Year

1. What are some important formulas for simplification and approximation in the SSC CGL exam?
Ans. Some important formulas for simplification and approximation in the SSC CGL exam include: - BODMAS rule: This rule states that in any mathematical expression, brackets should be simplified first, followed by orders (powers and roots), then division and multiplication from left to right, and finally addition and subtraction from left to right. - Percentage formula: Percentage is calculated as (part/whole) * 100. It is often used in simplification and approximation problems. - Square and cube formulas: These include formulas for calculating the square and cube of a number, such as (a + b)^2 = a^2 + 2ab + b^2 and (a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3. - Approximation formulas: These formulas help in approximating values quickly, such as rounding off decimals to the nearest whole number or using shortcut methods for multiplication and division.
2. How can the BODMAS rule be applied in simplification problems?
Ans. The BODMAS rule is a guideline for simplifying mathematical expressions. It stands for Brackets, Orders, Division and Multiplication, and Addition and Subtraction. To apply the BODMAS rule in simplification problems, follow these steps: - Simplify any expressions inside brackets first. - Evaluate any orders (powers and roots) next. - Perform any division and multiplication operations from left to right. - Finally, perform any addition and subtraction operations from left to right. By following this order of operations, you can simplify complex expressions and arrive at the correct answer.
3. How is percentage calculation used in simplification and approximation problems?
Ans. Percentage calculation is often used in simplification and approximation problems to quickly estimate values. It involves calculating a certain percentage of a given number or finding the original value when a percentage is known. For example, if you need to find 20% of 200, you can use the formula (part/whole) * 100. In this case, (20/100) * 200 = 40. So, 20% of 200 is 40. Similarly, if you know that a certain value is 80% of the original value, you can use the formula (part/whole) * 100 to find the original value. If the known value is 80 and the percentage is 80%, the original value would be (80/80) * 100 = 100. By using percentage calculation, you can quickly approximate values and simplify calculations in the SSC CGL exam.
4. How can approximation formulas be used to simplify calculations?
Ans. Approximation formulas are helpful in simplifying calculations by providing quick and close estimations of values. Some common approximation formulas include rounding off decimals to the nearest whole number, using shortcut methods for multiplication and division, and using approximate values for trigonometric functions. For example, instead of calculating the square root of 37, which is a complex and time-consuming process, you can approximate it to the nearest whole number as 6. This approximation would be close enough for most simplification problems. Similarly, shortcut methods like the "Multiplying by 11" trick or the "Dividing by 9" trick can be used to simplify multiplication and division calculations. By using approximation formulas, you can save time and effort in solving complex calculations during the SSC CGL exam.
5. How can square and cube formulas be applied in simplification problems?
Ans. Square and cube formulas are useful in simplification problems that involve finding the square or cube of a number. These formulas can be applied to quickly calculate the values and simplify the expressions. For example, if you need to calculate (32 + 18)^2, you can use the square formula (a + b)^2 = a^2 + 2ab + b^2. In this case, (32 + 18)^2 = 32^2 + 2 * 32 * 18 + 18^2 = 1024 + 1152 + 324 = 2500. Similarly, if you need to calculate (5 + 2)^3, you can use the cube formula (a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3. In this case, (5 + 2)^3 = 5^3 + 3 * 5^2 * 2 + 3 * 5 * 2^2 + 2^3 = 125 + 150 + 60 + 8 = 343. By applying square and cube formulas, you can simplify expressions and solve problems more efficiently in the SSC CGL exam.
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