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Important Formulas Arithmetic Progression and Geometric Progression - Quantitative

Basic Concept on Arithmetic Progression

An arithmetic progression (AP) is a sequence of numbers in which the difference between any two successive members is always the same. This fixed difference is called the common difference.

  • First term is denoted by a.
  • Common difference is denoted by d.
  • nth term is denoted by tn or Tn.
  • Sum of first n terms is denoted by Sn.
  • Example: 4, 8, 12, 16, ... is an AP with a = 4 and d = 4.

Formula of Arithmetic Progression

nth term of an AP

  • Formula: Tn = a + (n - 1)d
  • where Tn = nth term, a = first term, d = common difference, and n = number of terms.

Number of terms in an AP

If the first term is a, the last term is l, and the common difference is d, then the number of terms n satisfies the relation

l = a + (n - 1)d

Number of terms in an AP

Thus,

n =  (l - a)/d + 1

Sum of first n terms in an AP

The sum of the first n terms, Sn, can be obtained in two common forms.

Sn = n/2 [2a + (n - 1)d]

or, if the last term l = Tn is known,

Sn = n/2 (a + l)

Sum of first n terms in an AP

where a = first term, d = common difference, and Tn = l = a + (n - 1)d.

Arithmetic Mean

If three numbers a, b, c are in AP, then b is the arithmetic mean of a and c. In symbols,

b = (a + c)/2

Arithmetic Mean

Some other important formulas of Arithmetic Progression

Sum of first n natural numbers

The sum of the first n natural numbers is given by S = n(n + 1)/2. A standard derivation is shown below.

Write the sum forwards and backwards and add corresponding terms.

Let S = 1 + 2 + 3 + ... + (n - 1) + n

Write S in reverse order: n + (n - 1) + (n - 2) + ... + 2 + 1

Add the two expressions termwise to obtain 2S = (n + 1) + (n + 1) + ... + (n + 1) (n terms)

Therefore 2S = n(n + 1)

S = n(n + 1)/2

Sum of first n natural numbers

Sum of squares of first n natural numbers

The sum of squares of the first n natural numbers is

S = 12 + 22 + 32 + ... + n2 = n(n + 1)(2n + 1)/6

Sum of squares of first n natural numbers

Sum of first n odd numbers

The sum of the first n odd numbers is

S = n2

That is, 1 + 3 + 5 + ... (n terms) = n2.

Sum of first n even numbers

The sum of the first n even numbers is

S = n(n + 1)

That is, 2 + 4 + 6 + ... (n terms) = n(n + 1).

Formulas for Geometric Progression (GP)

Common ratio

A geometric progression (GP) is a sequence in which each term after the first is obtained by multiplying the previous term by a fixed non-zero number called the common ratio.

If successive terms are a1, a2, a3, ..., then the common ratio r is

r = a2 / a1 = a3 / a2 = ...

Common ratio

nth term of a GP

  • Formula: an = a1 · rn-1
  • where a1 = first term, r = common ratio, and n = term index.

Sum of first n terms in a GP

For r ≠ 1, the sum of the first n terms is

Sn = a1 (1 - rn)/(1 - r)

Sum of first n terms in a GP
Sum of first n terms in a GP

Note: the algebraic form is the same for r > 1 and for |r| < 1; the displayed placeholders correspond to the original presentation. When r = 1, every term equals a1 and Sn = n·a1.

Sum of an infinite GP

If |r| < 1, an infinite GP has a finite sum. The sum to infinity is

S∞ = a1 / (1 - r)

Sum of an infinite GP

If |r| ≥ 1, the sum to infinity does not exist (it diverges).

Geometric Mean (GM)

  • If two non-zero numbers a and b are in GP, then their geometric mean is GM = √(ab).
  • If three non-zero numbers a, b, c are in GP, then their geometric mean is GM = (abc)1/3.

Worked examples and short applications

Example 1: Find the 10th term of the AP 4, 8, 12, ...

Solution:

First term a = 4

Common difference d = 4

Use Tn = a + (n - 1)d

T10 = 4 + (10 - 1) × 4

T10 = 4 + 9 × 4

T10 = 4 + 36

T10 = 40

Example 2: Sum of first 20 terms of the AP 3, 7, 11, ...

Solution:

First term a = 3

Common difference d = 4

Number of terms n = 20

Use Sn = n/2 [2a + (n - 1)d]

S20 = 20/2 [2 × 3 + (20 - 1) × 4]

S20 = 10 [6 + 19 × 4]

S20 = 10 [6 + 76]

S20 = 10 × 82

S20 = 820

Example 3: Sum to infinity of GP 5, 5/2, 5/4, ...

Solution:

First term a1 = 5

Common ratio r = (5/2)/5 = 1/2

Since |r| < 1, S∞ = a1/(1 - r)

S∞ = 5/(1 - 1/2)

S∞ = 5/(1/2)

S∞ = 10

The document Important Formulas: Arithmetic Progression and Geometric Progression - Quantitative Reasoning for GMAT is a part of the GMAT Course Quantitative Reasoning for GMAT.
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FAQs on Important Formulas: Arithmetic Progression and Geometric Progression - Quantitative Reasoning for GMAT

1. What is an arithmetic progression?
Ans. An arithmetic progression is a sequence of numbers in which the difference between any two consecutive terms is constant. For example, 2, 5, 8, 11, 14 is an arithmetic progression with a common difference of 3.
2. What is the formula to find the nth term of an arithmetic progression?
Ans. The formula to find the nth term of an arithmetic progression is given by: nth term = first term + (n-1) * common difference. This formula helps in determining any term in the arithmetic progression by substituting the values of the first term, common difference, and the desired position of the term.
3. How can we find the sum of the first n terms of an arithmetic progression?
Ans. The sum of the first n terms of an arithmetic progression can be found using the formula: sum = (n/2) * (2a + (n-1)d), where n is the number of terms, a is the first term, and d is the common difference. This formula provides a quick way to calculate the sum without manually adding each term.
4. Can an arithmetic progression have a negative common difference?
Ans. Yes, an arithmetic progression can have a negative common difference. In such cases, the terms of the progression will be decreasing. For example, -3, -7, -11, -15 is an arithmetic progression with a common difference of -4.
5. How can we determine the number of terms in an arithmetic progression?
Ans. The number of terms in an arithmetic progression can be determined using the formula: number of terms = (last term - first term + common difference) / common difference. This formula calculates the difference between the last term and the first term, and then divides it by the common difference to obtain the total number of terms.
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