Word Problem: Decimals - 3 | Mathematics for Class 5 PDF Download

Q1: Each batch of cookie mix need 0.4 cups of sugar, and each batch can make 16 cookies. If Ashley is making 4 batches of cookies, how much sugar does she need?
Ans: 0.4 x 4 = 1.6
She needs 1.6 cups of sugar.

Q2: Ashley measured 1.43 cups of sugar. How much more sugar does she need?
Ans: 1.6 – 1.43 = 0.17
She needs 0.17 of a cup more sugar.

Q3: After she finished making the cookies, Ashley had 0.945 kg of flour left. How much flour did she use?
Ans: 2.64 – 0.945 = 1.695
She used 1.695 kg of flour.

Q4: Ashley found 2 boxes of sugar in the kitchen. The green box is 1.26 kg, and the red box is 1.026 kg. Which box contains more sugar?
Ans: 1.26 > 1.026
The green box contains more sugar.

Q5: She has 3 bags of flour. She has two smaller bags with 0.75 kg of flour each and a bigger bag which has 1.14 kg. How much flour does she have in total?
Ans: 0.75 + 0.75 + 1.14 = 2.64
She has 2.64 kg of flour in total.

Q6: Each batch of cookies is 8.9 oz. What is the weight of 2.5 batches of cookies?
Ans: 8.9 x 2.5 = 22.25
The weight of 2.5 batches of cookies is 22.25 oz.

Q7: Write the smallest and greatest 6 digit numbers formed by using digits 1,0,5,7 with repetition.
Ans: consider the given 4 digits 1,0,5,7 and with repetition allowed form the greatest and smallest 6 digit numbers. For the 6 digit, the greatest number 7 is the first digit, whereas for the smallest number 1 will be the first digit.
Greatest 6 digit number with repetition =777,510
Smallest 6 digit number with repetition =100,057

Q8: The difference between the two numbers is 3856749 . If the smaller number is 2565638 . Find the greater number.
Ans: we know that difference is obtained by subtracting subtrahend from  minuend.
Minuend − Subtrahend = Difference
In the problem it is given that, the difference between two numbers is 3856749 and the smaller number is 2565638 That means Subtrahend.
Hence, minuend = Difference + Subtrahend
⇒ 38,56,749+25,65,638=64,22,387
∴ the greatest number is 64,22,387.

Q9: A thread of length 20m has been divided into 5 pieces. What is the length of each piece?
Ans: In the problem it is given that, A thread of length 20m has been divided into 5 pieces.
Total length of the thread = 20m
Number of thread pieces = 5
Hence length of each thread piece 20/5 = 4m

Q10: Arrange in Descending order 4123676,71204381,176489,3240973
Ans: From the given numbers it’s clear that each number differs in their digit count so first count the digits.
4123673=7 digits
71204381=8 digits
176489=6 digits
3240973=7 digits
Now considering this digit counts, write the given numbers in ascending order. From the greatest number to the smallest number.
Descending order: 71204381,4123676,3240973,176489.

Q11: The mass of a bag is 2kg890g . What is the mass of 14 such bags?
Ans: in the problem it is given that,
Mass of a bag = 2kg 890g.
So, to find a mass of 14 such bags multiply 14 with one bag weight .
∴ Mass of 14 bags =(2kg 890g)×14
= 40kg 460g

Q12: A man had Rs. 2,08,78,560 amounts in his bank. He withdrew Rs. 48,36,980 in the month of January, Rs. 3,95,648 in the month of February and Rs. 45,000 in the month of march. What is the amount remaining in his bank account by the end of march?
Ans: In the problem it is given that,
Total amount in bank = Rs. 2,08,78,560
Amount withdrawn in January = Rs. 48,36,980
Amount withdrawn in February = Rs. 3,95,648
Amount withdrawn in March = Rs. 45,000
Amount remaining in bank account by end of march
= 2,08,78,560−48,36,980−3,95,648−45000
= 1,56,00,932
Amount remaining in bank account by end of march Rs. 1,56,00,932.