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Practice Questions: Percentages

Definition

The term "Percentage" originates from the Latin word "per centum," signifying "by the hundred." It is symbolized by %. For instance, if we express 5%, it is equivalent to 5/100, which simplifies to 0.05.

Definition

Finding the Percentage of a Number

  • Explain how to calculate a percentage of a given number using the formula:
    Finding the Percentage of a Number
  • Provide examples and step-by-step explanations of solving percentage problems.

Percentage Increase and Decrease

  • Discuss how to determine the percentage increase or decrease between two values using the formula: Percentage Change =
    Percentage Increase and Decrease
  • Provide practical examples, such as price changes, population growth rates, or test score improvements.

Applications of Percentages in Real Life

  • Examine diverse situations where percentages find common application, including scenarios involving discounts and sales, interest rates, inflation, and fluctuations in the stock market. 
  • Elaborate on the significance of comprehending percentages in the realm of personal finance and decision-making.

Calculating Percentages in Statistics

  • Examine the involvement of percentages in statistics, encompassing tasks like determining proportions, relative frequencies, and percentages in surveys or data analysis.
  • Emphasize the importance of percentages in depicting data accurately and facilitating meaningful comparisons.

Solving Percentage Problems

  • Present a set of exercises that span various percentage scenarios, incorporating tasks such as calculating percentages, solving for original values, and determining percentage changes.
  • Furnish detailed solutions and explanations in a step-by-step manner to assist users in comprehending the problem-solving approach.

Fraction to Percentage Conversion

Fraction to Percentage Conversion

Examples on Percentages

Example1: Luaa spends her monthly salary in the following manner: 20% on house rent, 20% on food, 5 % on transportation, 10% on the education, and 20% on other household expenses. She saves the remaining amount of ₨. 5000 at the end of the month. Find out her monthly salary?
(a) Rs. 35000
(b) Rs. 25000
(c) Rs. 20000
(d) Rs. 30000

Ans: (c)
Sol: Let the monthly salary be x (this represents 100%).
Total expenditure = 20% + 20% + 5% + 10% + 20% = 75% of x = 0.75x.
Therefore savings = 100% - 75% = 25% of x = 0.25x.
Given that 0.25x = 5000.
So x = 5000 ÷ 0.25 = 20,000.
Therefore, her monthly salary = Rs. 20,000.

Examples on Percentages

Example 2:  Aman spends 60% of his income. Suppose his income is increased by 21% and his expenditure increases by 5%, then what is the increase in his savings (in percentage)?
(a) 60%
(b) 18%
(c) 40%
(d) 45%

Ans: (d)
Sol: Assume Aman's original income = 100 units.
Original expenditure = 60 ⇒ original savings = 100 - 60 = 40 units.
New income = 100 × 1.21 = 121 units.
New expenditure = 60 × 1.05 = 63 units.
New savings = 121 - 63 = 58 units.
Increase in savings = 58 - 40 = 18 units.
Percentage increase in savings = (Increase ÷ Original savings) × 100 = (18 ÷ 40) × 100 = 45%.
Hence the increase in savings is 45% (option d).

Questions based on Percentages

Q1: A man made a contribution of 7% of his income to a needy person and saved 25% of the balance. If he now has, Rs. 2100 left, then find his actual income?
(a) 9626.26
(b) 9727.27
(c) 3010.75
(d) 10000

Ans: (c)
Sol: Let actual income = X.
Amount contributed = 7% of X = 0.07X. Remaining = X - 0.07X = 0.93X.
He saves 25% of the remaining balance, so amount saved = 0.25 × 0.93X = 0.2325X.
Amount left after saving = Remaining - Saved = 0.93X - 0.2325X = 0.6975X.
Given that this remaining amount is Rs. 2,100, so 0.6975X = 2,100.
Therefore X = 2,100 ÷ 0.6975 ≈ 3,010.752688... ≈ Rs. 3,010.75.
Thus the actual income ≈ Rs. 3,010.75, option (c).

Q2: In an examination, 40% are passing percentage. If a person gets 41 marks and fails by 3 marks, what are the maximum marks?
(a) 110
(b) 100
(c) 120
(d) 150
Ans: (a)
Sol: The passing marks = 41 + 3 = 44.
If maximum marks are m, then 40% of m = 44 ⇒ 0.40m = 44.
So m = 44 ÷ 0.40 = 110.
Therefore maximum marks = 110 (option a).

Q3: Reema saves 51% of his total income of Rs. 15000 per month. Calculate his total spending.
(a) 7350
(b) 7550
(c) 6500
(d) 8560
Ans: (a)
Sol: Money spent = (100% - 51%) of 15,000 = 49% of 15,000.
Amount = (49 ÷ 100) × 15,000 = 0.49 × 15,000 = 7,350.
Therefore money spent = Rs. 7,350 (option a).

Q4: If Jenny's income is 30% more than that of Nikita, how much percent of Nikita's income is less than that of Jenny?
(a) 23.08%
(b) 25.5%
(c) 27.60%
(d) 29%
Ans: (a)
Sol: Let Nikita's income = 100 units. Then Jenny's income = 100 + 30 = 130 units.
Percentage by which Nikita's income is less than Jenny's = [(130 - 100) ÷ 130] × 100 = (30 ÷ 130) × 100 = 23.0769% ≈ 23.08%.
Hence option (a).

Q5: If the price of an article is increased by 18%, determine by how much percent must a user reduce the use, so that expenditure on it remains unchanged?
(a) 13.24%
(b) 16%
(c) 25%
(d) 15.3%

Ans: (d)
Sol:
Let original price = P and original quantity used = Q so original expenditure = P×Q.
New price = P × 1.18. To keep expenditure constant, new quantity Q' must satisfy P×Q = (P×1.18)×Q' ⇒ Q' = Q ÷ 1.18.
Fractional reduction in quantity = 1 - (1 ÷ 1.18) = (1.18 - 1) ÷ 1.18 = 0.18 ÷ 1.18.
Percentage reduction = (0.18 ÷ 1.18) × 100 = (18 ÷ 118) × 100 ≈ 15.2542% ≈ 15.3%.
Therefore the user must reduce use by approximately 15.3% (option d).

The document Practice Questions: Percentages is a part of the SSC CGL Course Quantitative Aptitude for SSC CGL.
All you need of SSC CGL at this link: SSC CGL

FAQs on Practice Questions: Percentages

1. How do I solve percentage increase and decrease problems quickly for SSC CGL?
Ans. Use the formula: New Value = Original Value × (1 ± Percentage/100). For increases, add the percentage; for decreases, subtract it. Practice identifying what the question asks-whether it's the final amount, the change itself, or the original value-before calculating. This method eliminates calculation errors in competitive exams.
2. What's the difference between percentage and percentile in quantitative aptitude questions?
Ans. Percentage represents a part of 100 from a whole quantity, while percentile indicates a ranking position (e.g., 90th percentile means scoring better than 90% of candidates). In SSC CGL problems, percentage typically involves calculating proportions of amounts, whereas percentile rarely appears in quantitative aptitude sections but matters in score interpretation.
3. Why do I keep getting wrong answers on compound percentage problems?
Ans. Common mistake: applying percentages sequentially without compounding correctly. If a value increases by 20% then 10%, multiply by 1.20 then 1.10, not add percentages (which gives 30% instead of 32%). Always use successive multiplication for multiple percentage changes-this avoids the additive error that costs marks in percentage practice questions.
4. How should I approach percentage word problems involving profit, loss, and discounts?
Ans. Break word problems into three steps: identify the base value (cost price, marked price), note what percentage applies, then calculate using Profit% = (Profit/Cost Price) × 100 or Discount% = (Discount/Marked Price) × 100. Clearly label each component before solving-this systematic approach prevents confusion in real-world application scenarios common in SSC exams.
5. What percentage formula tricks help solve questions involving populations or ratios faster?
Ans. Convert ratios to percentages by dividing each part by the total sum, then multiplying by 100. For population changes, use: Percentage Change = [(New Population - Old Population) / Old Population] × 100. Flashcards and mind maps on EduRev help memorise these conversion shortcuts for quick recall during percentage practice under timed conditions.
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