The product of two positive integers is equal to the product of their highest common factor and their least common multiple.
Relation: Product of two numbers = (HCF of the two numbers) × (LCM of the two numbers)
Highest Common Factor (HCF) of two or more integers is the largest integer that divides each of them exactly (without remainder).
Least Common Multiple (LCM) of two or more integers is the smallest positive integer that is exactly divisible by each of them.
Note: The formula product = HCF × LCM holds exactly for two integers. It does not generalise as a straightforward equality involving the product of more than two integers without adjustments.
You may find the HCF of integers by any of these standard methods:
Common methods to compute LCM are:

Procedure:
Example: Find HCF(100, 125, 180).
Prime factorisations:
\(100 = 2 \times 2 \times 5 \times 5 = 2^2 \times 5^2\)
\(125 = 5 \times 5 \times 5 = 5^3\)
\(180 = 2 \times 2 \times 3 \times 3 \times 5 = 2^2 \times 3^2 \times 5\)
Common primes: only 5 appears in all three. The minimum power of 5 present in all is \(5^1\).
Therefore, HCF(100, 125, 180) = 5.
Procedure for two numbers:
Example: Find HCF of 120 and 180 using the Euclidean algorithm.
\(180 = 120 \times 1 + 60\)
\(120 = 60 \times 2 + 0\)
Remainder becomes zero; the last non-zero divisor is 60.
Therefore, HCF(120, 180) = 60.
Procedure:
Example: Find LCM(25, 35).
Prime factorisations:
\(25 = 5 \times 5 = 5^2\)
\(35 = 5 \times 7 = 5^1 \times 7^1\)
Highest powers: \(5^2\) (from 25) and \(7^1\) (from 35).
Therefore, LCM = \(5^2 \times 7 = 25 \times 7 = 175\).
Procedure (for two or more numbers):
Example: Find LCM(25, 35) by the division method.
Divide by 5:
5 | 25, 35
Quotients: 5, 7
Divide by 5 again where applicable:
5 | 5, 7
Quotients: 1, 7
Divide by 7:
7 | 1, 7
Quotients: 1, 1
Multiply the divisors used: \(5 \times 5 \times 7 = 175\).
Therefore, LCM(25, 35) = 175.
Q1: Calculate the highest number that will divide 43, 91 and 183 and leaves the same remainder in each case
(a) 4
(b) 7
(c) 9
(d) 13
Ans: (a)
Here the trick is
Find the Differences between number
Get the HCF (that differences)
We have here 43, 91 and 183
So differences are
183 - 91 = 92,
183 - 43 = 140,
91 - 43 = 48.
Now, HCF (48, 92 and 140)
48 = 2 × 2 × 2 × 2 × 3
92 = 2 × 2 × 23
140 = 2 × 2 × 5 × 7
HCF = 2 × 2 = 4
And 4 is the required number.
Q2: The greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is:
(a) 25 cm
(b) 15 cm
(c) 35 cm
(d) 55 cm
Ans: (c)
Required length = H.C.F. of 700 cm, 385 cm and 1295 cm = 35 cm.
Q3: Which of the following is greatest number of four digits which is divisible by 15, 25, 40 and 75 is:
(a) 9700
(b) 9600
(c) 9800
(d) 9650
Ans: (b)
Greatest number of 4-digits is 9999.
Now , find the L.C.M. of 15, 25, 40 and 75 i.e. 600.
On dividing 9999 by 600, the remainder is 399.
Hence, Required number (9999 - 399) = 9600.
Alternatively,
9999/600 = 16.66500
Ignore the decimal points, required number would be 16 * 600 = 9600
Final remark: Use prime factorisation when factor sizes are small and transparent; use the Euclidean method for large numbers or when handling only two numbers. The division (ladder) method is convenient for three or more numbers to get the LCM quickly.
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| 2. How do you find the Highest Common Factor (HCF) using the Division Method? | ![]() |
| 3. How do you find the Lowest Common Multiple (LCM) using the Prime Factorization Method? | ![]() |
| 4. How do you find the Lowest Common Multiple (LCM) using the Division Method? | ![]() |
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