Important Formulas: Harmonic Progressions

# Important Formulas: Harmonic Progressions | Quantitative Aptitude for SSC CGL PDF Download

## Definition of HP

A Harmonic Progression, also known as a Harmonic Sequence, is a series of real numbers generated by taking the reciprocals of an Arithmetic Progression or Arithmetic Sequence.

A Harmonic Progression is a sequence of values where the reciprocals of these values form an Arithmetic Progression. There are specific formulas for finite Harmonic Progressions. In this sequence, each term is the Harmonic Mean of its adjacent terms, making it a series of real numbers derived by taking the reciprocals of an Arithmetic Progression and calculating the mean of its neighboring terms.
HP is Represented in the form of

In this Page Harmonic Progression Formulas is given that is useful to Solve many Problems in different Competitive Examinations.

## Formulas of Harmonic Progression (HP)

• How to find nth term of an HP

where an  = nth term,
a/1  = the first term,
d = common difference taken from AP,
n = number of terms in the sequence
• Harmonic Mean (HM)
Harmonic Mean is type of numerical average, which is calculated by dividing the number of observation by the reciprocal of each  number in series.
If a, b are in HP, then there HM is

Where, n = Total number of numbers or terms, a1, a2,…..an = Individual terms or individual values.
Harmonic Mean of two numbers a and b is
Harmonic Mean of three numbers a, b and c is

### Examples

Example 1: In a harmonic progression, the sum of the first 5 terms is 6, and the sum of their cubes is 405. What is the first term of this progression?
(a) (1/3)
(b) (1/4)
(c) (1/5)
(d) (1/6)
Ans:
(a)
Let a be the first term and d be the common difference of the harmonic progression. The sum of the first 5 terms is given by ((S5) = 5a + 10d = 6). The sum of their cubes is given by (Scubes) = a3 + (a + d) 3 + (a + 2d)3 + (a + 3d)3 + (a + 4d)3 = 405). Using the value of ((S5)), we can solve for d, and then using ((Scubes )), we can solve for a, which turns out to be (1/3).

Example 2: In a harmonic progression, the sum of the first 6 terms is 3 times the sum of their reciprocals. What is the sum of the first 12 terms of this progression?
(a) 2
(b) 3
(c) 4
(d) 5
Ans:
(c)
Let (Sn) be the sum of the first n terms and (Sn′) be the sum of the reciprocals of the first n terms. The given condition can be written as ((S6) = (3S6′)). Using the formula for the sum of the first n terms of a harmonic progression, we have

Example 3: The sum of an infinite harmonic progression is (5/3). What is the sum of the squares of the terms in this progression?
(a) (10/3)
(b) (25/9)
(c) (15/4)
(d) (9/5)
Ans:
(a)
The sum of the squares of the terms in a harmonic progression is given by  where a1  is the first term. Given the sum of the infinite harmonic progression as (5/3), we can use the result

Example 4: In a harmonic progression, . What is the sum of the first 10 terms of this progression?
(a) (185/99)
(b) (99/185)
(c) (135/70)
(d) (70/135)
Ans:
(a)
The sum of the first n terms of a harmonic progression is given by Sn = a1
where a1  is the first term. Substituting the given  ℎnth  term, we get

Example 5: The sum of the first n terms of a harmonic progression is given by What is the common difference between the terms of this progression?
(a) (1/3)
(b) (2/3)
(c) (3/4)
(d) (4/5)
Ans: (a)
The sum of the first n terms of a harmonic progression is given by  where a is the common difference. Comparing this with the given formula, we have

The document Important Formulas: Harmonic Progressions | Quantitative Aptitude for SSC CGL is a part of the SSC CGL Course Quantitative Aptitude for SSC CGL.
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## Quantitative Aptitude for SSC CGL

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## Quantitative Aptitude for SSC CGL

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