Word Problems: Time & Temperature | Mathematics for Class 5 PDF Download

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Q1: Rahul took his breakfast at 8:00 a.m. He finished his meal in 25 minutes. What time did he finish his breakfast?

Sol:

Start time = 8:00 a.m.

Duration of breakfast = 25 minutes

Adding 25 minutes to 8:00 a.m.:

$a.m.8:00\; +\; 25\; \backslash text\{\; minutes\}\; =\; 8:25\; \backslash text\{\; a.m.\}$8:00+25 minutes=8:25 a.m.

Thus, Rahul finished his breakfast at 8:25 a.m.

Q2: An event started at 3:45 p.m. and lasted for 2 hours and 30 minutes. What time did the event end?

Sol:

Start time = 3:45 p.m.

Duration = 2 hours 30 minutes

First, add 2 hours:

$p.m.3:45\; +\; 2\; \backslash text\{\; hours\}\; =\; 5:45\; \backslash text\{\; p.m.\}$3:45+2 hours=5:45 p.m.

Now, add 30 minutes:

$p.m.5:45\; +\; 30\; \backslash text\{\; minutes\}\; =\; 6:15\; \backslash text\{\; p.m.\}$5:45+30 minutes=6:15 p.m.

Thus, the event ended at 6:15 p.m.

Q3: Add 4 hours 15 minutes and 2 hours 50 minutes.

Sol: 

Given time periods: 4 hours 15 minutes, 2 hours 50 minutes

Step-by-step addition:

Add the minutes:

$minutes15\; +\; 50\; =\; 65\; \backslash text\{\; minutes\}\; =\; 1\; \backslash text\{\; hour\}\; 5\; \backslash text\{\; minutes\}$15+50=65 minutes=1 hour 5 minutes

Add the hours:

4+2=6 hours

Add the extra hour from minutes:

$hours6\; +\; 1\; =\; 7\; \backslash text\{\; hours\}$6+1=7 hours

Final result:

$minutes7\; \backslash text\{\; hours\; \}\; 5\; \backslash text\{\; minutes\}$7 hours 5 minutes

Thus, 4 hours 15 minutes + 2 hours 50 minutes = 7 hours 5 minutes.

Q4: Subtract 1 hour 40 minutes from 3 hours 25 minutes.

Sol:

Given time periods: 3 hours 25 minutes, 1 hour 40 minutes

Step-by-step subtraction:

Subtract minutes:

25−40 (not possible, so borrow 1 hour from 3 hours
$(3\; -\; 1\; =\; 2)\; \backslash Rightarrow\; 1\; hour\; is\; borrowed\; =\; 60\; minutes$(3−1=2)⇒1 hour is borrowed= 60minutes
(25+60)−40
=85−40
=45 minutes

Subtract hours:

2−1=1 hour

Final result:

$minutes1\; \backslash text\{\; hour\; \}\; 45\; \backslash text\{\; minutes\}$1 hour 45 minutes

Thus, 3 hours 25 minutes – 1 hour 40 minutes = 1 hour 45 minutes.

Q5: Mary studied for 1 hour 30 minutes on Monday, 2 hours 15 minutes on Tuesday, and 1 hour 50 minutes on Wednesday. How much time did she spend studying in total?

Sol: 

Monday: 1 hour 30 minutes

Tuesday: 2 hours 15 minutes

Wednesday: 1 hour 50 minutes

Step-by-step addition:

Add the minutes:

$30+15+50=95minutes=1hour35minutes30\; +\; 15\; +\; 50\; =\; 95\; \backslash text\{\; minutes\}\; =\; 1\; \backslash text\{\; hour\; \}\; 35\; \backslash text\{\; minutes\}$30+15+50=95 minutes=1 hour 35 minutes

Add the hours:

$1+2+1=4hours1\; +\; 2\; +\; 1\; =\; 4\; \backslash text\{\; hours\}$1+2+1=4 hours

Add the extra hour from minutes:

$hours4\; +\; 1\; =\; 5\; \backslash text\{\; hours\}$4+1=5 hours

Final result:

5 hours 35 minutes

Thus, Mary spent a total of 5 hours 35 minutes studying.

Q6: On a rainy day, the temperature was 27.5°C. On the next day, it increased by 1.5°C. What was the temperature on the next day?

Sol:

Temperature on the rainy day = 27.5°C

Increase in temperature = 1.5°C

Temperature on the next day = 27.5°C + 1.5°C

=29.0°C

Thus, the temperature on the next day was 29.0°C.

Q7: The maximum temperature of a city on a particular day was 33.2°C while the minimum was 17.8°C. What was the difference in temperature?

Sol:

Maximum temperature = 33.2°C

Minimum temperature = 17.8°C

Difference in temperature = Maximum temperature - Minimum temperature

$33.2°C\; -\; 17.8°C\; =\; 15.4°C$33.2°C−17.8°C=15.4°C

Thus, the difference in temperature was 15.4°C.

Q8: The temperature of water kept for boiling has reached 78°C. How many degrees more does it need to start boiling? (Boiling point of water = 100°C)

Sol:

Boiling point of water = 100°C

Current temperature of water = 78°C

Temperature increase required = 100°C - 78°C

=22°C

Thus, the water needs 22°C more to start boiling.

Q9: Anand was suffering from fever, and his body temperature was 1.6°C above normal body temperature. What was his body temperature during his illness? (Normal body temperature = 37°C)

Sol:

Normal body temperature = 37°C

Increase in temperature = 1.6°C

Anand’s body temperature = 37°C + 1.6°C

$=\; 38.6°C$=38.6°C

Thus, Anand’s body temperature during his illness was 38.6°C.

Q10: The temperature at midnight was 16.4°C. By morning, it dropped by 2.8°C. What was the temperature in the morning?

Sol:

Midnight temperature = 16.4°C

Decrease in temperature = 2.8°C

Morning temperature = 16.4°C - 2.8°C

$=\; 13.6°C$=13.6°C

Thus, the temperature in the morning was 13.6°C.