Important Questions: Perimeter and Area | Mathematics (Maths) Class 7 PDF Download

Q1: A rectangular piece of land has a length of 500 m and a breadth of 300 m respectively. Find the area and the cost of the land. The condition given is 1 m² of the land cost Rs 10,000.
Ans: According to the given question, 
The length of the triangle = 500 m
The breadth of the triangle = 300 m
Since the formula for area = length × breadth = 500 × 300 m² = 150000 m²
If Rs 10,000 is the cost of land of 1m²
Then the cost of 150000 m² land = 10000 × 150000 = Rs 1500000000

Q2: The perimeter is given at 320 m. Calculate the area of the square park.
Ans: According to the given question,
the Perimeter of the square = 320 m
Length of the side of the park = 320/4 = 80 m
Since 4 × length of the side of the park = 320 m
Area of the square park = (length of the park side)2 = (80)2 = 6400 m².

Q3: Calculate the breadth and perimetre of the rectangular plot when the area given is 440 m² and the length given is 22 m.
Ans: 
According to the given question,
The Area of the given rectangular plot = 440 m²
Length of the plot = 22 m 
Applying the formula, area = length × breadth
Therefore, area/length = breadth
Breadth = 440/22 = 20 m
Perimeter of the rectangle will be calculated as = 2(length + Breadth) = 2(22 + 20) = 2 × 42 = 84 m.
So the rectangular plot has a perimetre of 84 m

Q4: Calculate the breadth when the perimetre and length of the rectangular sheet given are 100 cm and 35 cm respectively. Also, calculate the area.
Ans:  According to the given question, 
Perimetre given is 100 m
Length of the rectangular sheet given is 35 cm
Since perimetre = 2 ( length + breadth )
On applying the formula
100 = 2 (35 + breadth)
100/2 = 35 + breadth
50 = 35 + breadth
50 – 35 = breadth,
Therefore, breadth is calculated as 15 cm.
Since we know that the 
Area = length × breadth = 35 × 15 = 525 cm²
So, the area of the rectangular sheet is 525 cm²

Q5: The square park and the rectangular park have the same area. Calculate the breadth of the rectangular park when the side of the rectangular park is 60 m and the length of the rectangular park is 90 m.
Ans: 
According to the given question,
the Area of the square park = area of the rectangular park
Side of the square park is 60 m 
Length of the rectangular park is 90 m
We know the formula that,
Area of the square park = (one of the sides of the square )2 = (60)2 = 3600 m²
Area of the rectangular park = 3600 m²
On applying the formula
3600 = 90 × breadth
3600/90 = breadth
40 m = breadth

Q6: Suppose the shape of the wire is a rectangle. The length and breadth of the rectangle are 40 cm and 22 cm respectively. What is going to be the measurements of each side if the wire is bent in the shape of a square? Find out about the shape which encloses more area.
Ans: 
The perimetre of the square = perimetre of a rectangle, as given in the question
According to the given question, 
the Length of the rectangle = 40 cm
Breadth of the rectangle = 22 cm
Since the perimetre of square and rectangle are equal
2 (length + breadth) = 4 × side
2(40 + 22) = 4 × side
2 × 62 = 4 × side
124 = 4 × side
124/4 = side = 31 cm
Area of the rectangle = length × breadth = 40 × 22 = 880 cm²
Area of the square = side2 = 31 × 31 = 961 cm²
Based on the above values it could be said that the square shape enclosed more area.

Q7: The length of the door is 2 m and the breadth is 1 m and it is fitted in a wall. The wall has a length of 4.5 m and a breadth of 3.6 m, what is the cost required for whitewashing the wall when the rate is Rs 20 per m² for whitewashing.
Ans: According to the given question,
The Door has length = 2 m
Door has breadth = 1 m
Wall has length = 4.5 m
Wall has breadth = 3.6 m
Area of the door = length × breadth = 2 × 1 = 2 m²
Area of the wall = length × breadth = 4.5 × 3.6 = 16.2 m²
The area for whitewashing = 16.2 – 2 = 14.2 m²
The cost of the whitewashing 1 m² area = 20 Rs
Cost of whitewashing the area of 14.2 m² = 14.2 × 20 = 284 Rs

Q8: PQRS is a parallelogram, QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm then calculate the area of the parallelogram PQRS. Calculate QN when PS gave as 8 cm.
Ans: 
SR = 12 cm, QM = 7.6 cm
Area of the parallelogram = length × breadth = SR × QM = 12 × 7.6 = 91.2 cm²
For the second part of the question, calculating QN includes:
Area of the parallelogram = length × breadth 
91.2 = PS × QN
91.2 = 8 × QN
QN = 91.2/8 = 11.4 cm

Q9: DL and BM are the heights on sides AB and AD respectively of ABCE parallelogram. Let us suppose the area of the parallelogram is 1470 cm², AB = 35 cm and AD = 49 cm. Calculate the length of the BM and the DL.
Ans:  According to the question given above,
The Area of the parallelogram = 1470 cm²
AB = 35 cm
AD = 49 cm
Then
It is clear that
The Area of the parallelogram = base × height
1470 = AB × BM
1470 = 35 × DL
1470/35 = DL
DL = 42 cm
Area of the parallelogram = base × height
1470 = AD × BM
1470 = 49 × BM
BM = 1470/49
BM = 30 cm

Q10: The right-angled triangle is ABC given. This is right-angled at A. AD is perpendicular to BC. If AB = 5 cm and BC = 13 cm and AC = 12 cm. Calculate the area of the ABC. Also, calculate the length of the AD.
Ans: According to the given question,
AB = 5 cm
BC = 13 cm
AC = 12 cm
We know that
Area of the triangle ABC = ½ × Base × height
= ½ × AB × AC
=½ × 5 × 12 = 1 × 5 × 6 = 30 cm²
Now, 
Area of the triangle ABC = ½ × Base × height
30 = ½ × AD × BC
30 = ½ × AD × 13
30 × 2/13 = AD
AD = 60/13 = 4.6 cm

Q11: Find the circumference of the circle with a radius of 14 cm. take the value of =22/7
Ans: 
As per the question given, the radius of the circle = 14 cm
Circumference of the circle will be calculated by the formula = 2 r 
= 2 × 22/7 ×14 = 2 × 22 × 2 = 88 cm

Q12: The circumference of a circular sheet is 154 m. calculate the radius. Calculate the area of the sheet as well.
Ans:
As per the question, it is given that
The Circumference of the circle = 154 m 
We know the formula
Circumference of the circle will be calculated by the formula = 2 r 
154 = 2 × 22/7 × r 
154 = 44/7 × r
r = 154 × 7/ 44
r = 14 × 7/ 4
r = 7 × 7/ 2
r = 49/2 = 24.5 m
area of the circle = r2 = 22/7 × (24.5)2  = 22/7 × 600.25
= 22 × 85.75 = 1886.5 m²

Q13: Calculate the perimetre of the figure. The figure is a semicircle including its diameter.
Ans: As per the given question,
The Diameter of the semi-circle = 10 cm
Radius = r = d/2 = 10/2 = 5 cm
Circumference of the semi-circle = 22/7 × 5 = 110/7 = 15.71 cm
To calculate the perimeter of the above figure,
Perimeter of the semi-circle = semi-circle circumference + semicircle diameter
= 15.71 + 10 = 25.71 cm

Q14: The rate of polishing is Rs 15/m². Find the cost of polishing a circular table – top which has a diameter of 1.6 m.
Ans: As per the given question,
The diameter of the circular table – top = 1.6 m
As we know the
Radius = r = d/2 = 1.6 / 2 = 0.8 m
Area of the circular table top will be 3.14 × 0.8 × 0.8 = 2.0096 m²
The cost of polishing 1 m² area = Rs 15
So for calculating the 2.0096 m² area = Rs 15 × 2.0096 = 30.144
So in order to polish the area of 2.0096 m², the cost incurred is Rs 30.144

Q15: Fill in the blanks:

1. ________ is the distance around a closed figure.
2. _________ is the part of the plane which is occupied by the closed figure.
3. The formula to calculate the perimetre of the square will be presented as  _______
4. The formula to calculate the perimetre of the rectangle will be presented as _______
5. The area of the square is calculated as ________
6. The area of a rectangle is calculated as ________
7. The area of the parallelogram is calculated as _______
8. ___________ is the distance around a circular region.

Ans: 

1. Perimeter is the distance around a closed figure.
2. Area  is the part of the plane which is occupied by the closed figure.
3. The formula to calculate the perimetre of the square will be presented as  4 × side
4. The formula to calculate the perimetre of the rectangle will be presented as  2 × (length + breadth)
5. The area of the square is calculated as side × side
6. The area of a rectangle is calculated as length × breadth
7. The area of the parallelogram is calculated as base × height
8. Circumference is the distance around a circular region.