UPSC Exam  >  UPSC Notes  >  Chemistry Optional Notes for UPSC  >  Radio Active Decay: Fluorescence & Phosphorescence

Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSC PDF Download

Fluorescence

  • Fluorescence, a type of luminescence, occurs in gas, liquid or solid chemical systems. Fluorescence is brought about by absorption of photons in the singlet ground state promoted to a singlet excited state. The spin of the electron is still paired with the ground state electron, unlike phosphorescence. As the excited molecule returns to ground state, it involves the emission of a photon of lower energy, which corresponds to a longer wavelength, than the absorbed photon.
  • The energy loss is due to vibrational relaxation while in the excited state. Fluorescent bands center at wavelengths longer than the resonance line. This shift toward longer wavelengths is called a Stokes shift. Excited states are short-lived with a lifetime at about 10-8 seconds. Molecular structure and chemical environment affect whether or not a substance luminesces. When luminescence does occur, molecular structure and chemical environment determine the intensity of emission. Generally molecules that fluoresce are conjugated systems. Fluorescence occurs when an atom or molecules relaxes through vibrational relaxation to its ground state after being electrically excited. The specific frequencies of excitation and emission are dependent on the molecule or atom.
    Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSC
    where 
    • hν is a photon energy with 
    • h is Planck's constant and 
    • ν is the frequency of light, 
    • Sis the ground state of the fluorophore and 
    • S1 is its first electronically excited state.

Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSCFigure 1: Jablonski diagram of absorbance, non-radiative decay, and fluorescence.

  • Figure 1 is a Jablonski energy diagram representing fluorescence. The purple arrow represents the absorption of light. The green arrow represents vibrational relaxation from singlet excited state, S2 to S1. This process is a non-radiative relaxation in which the excitation energy is dispersed as vibrations or heat to the solvent, and no photon is emitted. The yellow arrow represents fluorescence to the singlet ground state, So.
    The fluorescence quantum yield gives the efficiency of the fluorescence process. It is the ratio of photons emitted to photons absorbed.
    Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSC
    If every photon absorbed results in a photon emitted. The maximum fluorescence quantum yield is 1.0, and compounds with quantum yields of 0.10 are still considered fluorescent. Another way to define the fluorescence quantum yield is by the excited state decay rates:
    Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSC
    where kf is the rate of spontaneous emission of radiation and the denominator is the sum of all rates of excited state decay for each deactivation process (ie phosphorescence, intersystem crossing, internal conversion…). The fluorescence lifetime is the average time the molecule remains in its excited state before emitting a photon. Fluorescence typically follows first-order kinetics:
    Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSC
    where 
    • [S1] is the concentration of excited state molecules at time t, 
    • [S1]0 is the initial concentration and τ is the decay rate. 
  • Various radiative and non-radiative processes can de-populate the excited state so the total decay rate is the sum over all rates:
    Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSC
    where  τtot is the total decay rate,  τrad the radiative decay rate and  τnrad the non-radiative decay rate. If the rate of spontaneous emission or any of the other rates are fast, the lifetime is short. The average lifetime of fluorescent compounds that emit photons with energies from the UV to near infrared are within the range of 0.5 to 20 nanoseconds.
    The fluorescence intensity,  IF is proportional to the amount of light absorbed and the fluorescence quantum yield,  Φ
    Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSC
    where 
    • k is a proportionality constant attributed to the instrument 
    • Io is the incident light intensity 
    • ϵ is the molar absorptivity, b is the path length, and 
    • c is the concentration of the substrate.
      If dilute solutions are used so that less than 2% of the excitation energy is absorbed, then an approximation can be made so that
      Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSC
  • This relationship shows that fluorescence intensity is proportional to concentration.
    Fluorescence rarely results from absorption of UV-radiation of wavelengths shorter than 250 nm because this type of radiation is sufficiently energetic to cause deactivation of the excited state by predissociation or dissociation. Most organic molecules have at least some bonds that can be ruptured by energies of this strength. Consequently, fluorescence due to  sigma∗→σ transitions is rarely observed. Instead such emission is confined to the less energetic  π∗→π and  π∗→n processes. Fluorescence commonly occurs from a transition from the lowest vibrational level of the first excited electronic state to the one of the vibrational levels of the electronic ground state. Quantum yield ( Φ ) is greater for  π∗→π transition because these excited states show short average lifetimes (larger kf ) and because deactivation processes that compete with fluorescence is not as likely to happen. Molar absorptivity of π → π* transitions is 100-1000 fold greater. The average lifetime is 10-7 to 10-9 seconds for ?, ?* states and 10-5 to 10-7 seconds for n, π* states.
    Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSC

Figure 2: Schematic representation of a fluorescence spectrometer.

  • Figure 2 is a schematic of a typical filter fluorometer that uses a source beam for fluorescence excitation and a pair of photomultiplier tubes as transducers. The source beam is split near the source into a reference beam and a sample beam. The reference beam is attenuated by the aperture disk so that its intensity is roughly the same as the fluorescence intensity. Both beams pass through the primary filter, with the reference beam being reflected to the reference photomultiplier tube. The sample beam is focused on the sample by a pair of lenses and causes fluorescence emission. The emitted radiation passes through a second filter and then is focused on the sample photomultiplier tube. The electrical outputs from the two transducers are then processed by an analog to digital converter to compute the ratio of the sample to reference intensities, which can then be used for qualitative and quantitative analysis. To obtain an emission spectrum, the excitation monochromator is fixed and the emission monochromator varies. To obtain an excitation spectrum, the excitation monochromator varies while the emission monochromator is fixed.
  • Fluorescence spectroscopy can be used to measure the concentration of a compound because the fluorescence intensity is linearly proportional to the concentration of the fluorescent molecule. Fluorescent molecules can also be used as tags. For example, fluorescence in situ hybridization (FISH) is a method of determining what genes are present in an organism's genome. Single stranded DNA encoding a gene of interest is covalently bonded to a fluorescent molecule and washed over the organism's chromosome, binding to its complementary sequence. The presence and placement of the gene in the organism then fluoresces when shined with ultraviolet light. Green fluorescence protein (GFP) is used in molecular biology to monitor the activity of proteins. The gene encoding GFP can be inserted next to a gene encoding a protein that will be studied. When the genes are expressed, the protein will be attached to GFP and can be identified in the cell by its fluorescence.

Question for Radio Active Decay: Fluorescence & Phosphorescence
Try yourself:
What is the main difference between phosphorescence and fluorescence?
View Solution
 

Phosphorescence

Unlike florescence, phosphorescence does not re-emit the light immediately. Instead, phosphorescence releases light very slowly in the dark due to its energy transition state. When light such as ultraviolet light is shined upon a glow in dark object, the object emits light, creating phosphorescence.

Similarity between the phosphorescent and the fluorescent materials

  • There is a similarity between the phosphorescent and the fluorescent materials. They both contain substances with identical atoms. It is very important to understand the impurity state energy band, which is located between the conduction and valence energy bands. In a phosphorescence event, the absorbed energy usually goes through a high energy state which happens to be triplet state. The energy gets trapped in the triplet state because its physical situation forbids the transition to return to lower energy state, also as known from impurity to valence band. 
  • In order to change the energy of valence band, electrons must regain the energy they had lost during the impurity band transitional process. If the quantum yield of the phosphorescence is high enough, a great amount of light will be released and thus making the object glow in the dark.
  • Most compounds have the ground state of singlet S0. When it absorbs light, the electrons in the molecule may move to excited state of S1, S2, Sn and so on. There are also triplet states T1 and T2. The energy of the T1 state is typically below the S1 state, while T2 is between S2 and S1 state. 
  • The wavelength of the radiation can determine which state the electron will move to. It is possible for the electron to return from excited state back to the ground state. An example is phosphorescence, where the emitting of radiation demotes the electrons from the excited state of Tto ground state S0. The molecule of phosphorescence has long life time, it loses energy easily, so it is hard to observe phosphorescence.

Applications

  • Materials that can produce phosphorescence often contain zinc sulfide, sodium fluorescein, rhodamine, or strontium. The majority of phosphorescence is often used in drugs in pharmaceutical field. 
  • Some common drugs that have phosphorescence property include Aspirin, benzoic acid, morphine, and dopamine. Phosphorescence is also used to analyze water, air and chemical pollutions.

Question for Radio Active Decay: Fluorescence & Phosphorescence
Try yourself:
What is the main difference between fluorescence and phosphorescence?
View Solution
 

The document Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSC is a part of the UPSC Course Chemistry Optional Notes for UPSC.
All you need of UPSC at this link: UPSC
308 docs

Top Courses for UPSC

FAQs on Radio Active Decay: Fluorescence & Phosphorescence - Chemistry Optional Notes for UPSC

1. What is fluorescence?
Ans. Fluorescence is a phenomenon in which a substance absorbs light of one wavelength and re-emits light of a longer wavelength. This process occurs almost instantaneously and the emitted light stops as soon as the excitation source is removed.
2. How does fluorescence differ from phosphorescence?
Ans. Fluorescence and phosphorescence differ in their duration of light emission. In fluorescence, the emission of light stops as soon as the excitation source is removed, whereas in phosphorescence, the emission of light continues even after the excitation source is removed, for a certain period of time.
3. What is radioactive decay?
Ans. Radioactive decay is the process by which an unstable atomic nucleus loses energy by emitting radiation. This can occur through various types of radioactive decay, such as alpha decay, beta decay, or gamma decay. It is a random process, and the rate of decay is measured by the half-life of the radioactive substance.
4. How are fluorescence and phosphorescence related to radioactive decay?
Ans. Fluorescence and phosphorescence can be observed in certain materials that have been exposed to radiation. Radioactive decay can cause electrons in these materials to become excited, leading to the emission of light. This phenomenon is often utilized in the field of radiation detection and analysis.
5. What are some practical applications of fluorescence and phosphorescence?
Ans. Fluorescence and phosphorescence have numerous practical applications. They are widely used in fluorescence microscopy for biological imaging, in fluorescent dyes for labeling and tracking molecules, in fluorescent lighting, in forensics for detecting fingerprints, and in materials science for studying properties of materials. Additionally, they play a crucial role in the field of luminescent materials for various technological advancements.
308 docs
Download as PDF
Explore Courses for UPSC exam

Top Courses for UPSC

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSC

,

Sample Paper

,

shortcuts and tricks

,

Free

,

Semester Notes

,

study material

,

Previous Year Questions with Solutions

,

Important questions

,

pdf

,

ppt

,

Objective type Questions

,

Exam

,

video lectures

,

mock tests for examination

,

Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSC

,

Viva Questions

,

MCQs

,

Summary

,

Extra Questions

,

past year papers

,

practice quizzes

,

Radio Active Decay: Fluorescence & Phosphorescence | Chemistry Optional Notes for UPSC

;