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Introduction

A major goal in chemical kinetics is to determine the sequence of elementary reactions, or the reaction mechanism, that comprise complex reactions. For example, Sherwood Rowland and Mario Molina won the Nobel Prize in Chemistry in 1995 for proposing the elementary reactions involving chlorine radicals that contribute to the overall reaction of O3 → O2 in the troposphere. In the following sections, we will derive rate laws for complex reaction mechanisms, including reversible, parallel and consecutive reactions.

Parallel Reactions

Consider the reaction in which chemical species  A undergoes one of two irreversible first order reactions to form either species  B or species  C:
More Complex Reactions | Chemistry Optional Notes for UPSC
The overall reaction rate for the consumption of A can be written as:
More Complex Reactions | Chemistry Optional Notes for UPSC
Integrating [A] with respect to t, we obtain the following equation:
More Complex Reactions | Chemistry Optional Notes for UPSC
Plugging this expression into the equation forMore Complex Reactions | Chemistry Optional Notes for UPSC
More Complex Reactions | Chemistry Optional Notes for UPSC
Integrating [B] with respect to t, we obtain:
More Complex Reactions | Chemistry Optional Notes for UPSC
At t = 0, [B] = 0. Therefore,
More Complex Reactions | Chemistry Optional Notes for UPSC
Likewise,
More Complex Reactions | Chemistry Optional Notes for UPSC
The ratio of [B] to  [C] is simply:
More Complex Reactions | Chemistry Optional Notes for UPSC
An important parallel reaction in industry occurs in the production of ethylene oxide, a reagent in many chemical processes and also a major component in explosives. Ethylene oxide is formed through the partial oxidation of ethylene:
More Complex Reactions | Chemistry Optional Notes for UPSC
However, ethylene can also undergo a combustion reaction:
More Complex Reactions | Chemistry Optional Notes for UPSC
To select for the first reaction, the oxidation of ethylene takes place in the presence of a silver catalyst, which significantly increases k1 compared to k2. Figure 9.4.1 displays the concentration profiles for species A, B, and C in a parallel reaction in which k1 > k2.
More Complex Reactions | Chemistry Optional Notes for UPSC

Consecutive Reactions

Consider the following series of first-order irreversible reactions, where species A reacts to form an intermediate species, I, which then reacts to form the product, P:
More Complex Reactions | Chemistry Optional Notes for UPSC
We can write the reaction rates of species A, I and P as follows:
More Complex Reactions | Chemistry Optional Notes for UPSC
As before, integrating  [A] with respect to t leads to:
More Complex Reactions | Chemistry Optional Notes for UPSC
The concentration of species I can be written as
More Complex Reactions | Chemistry Optional Notes for UPSC
Then, solving for  [P], we find that:
More Complex Reactions | Chemistry Optional Notes for UPSC
Figure  9.4.2 displays the concentration profiles for species  A,  I, and  P in a consecutive reaction in which  k1 = k2. As can be seen from the figure, the concentration of species  I reaches a maximum at some time,  tmax. Oftentimes, species  I is the desired product. Returning to the oxidation of ethylene into ethylene oxide, it is important to note another reaction in which ethylene oxide can decompose into carbon dioxide and water through the following reaction
More Complex Reactions | Chemistry Optional Notes for UPSC
Thus, to maximize the concentration of ethylene oxide, the oxidation of ethylene is only allowed proceed to partial completion before the reaction is stopped.
Finally, in the limiting case when  k≫ k1, we can write the concentration of  P as
More Complex Reactions | Chemistry Optional Notes for UPSC
Thus, when k2 ≫ k1, the reaction can be approximated as A → P and the apparent rate law follows 1st order kinetics.
More Complex Reactions | Chemistry Optional Notes for UPSC

Consecutive Reactions With an Equilibrium

Consider the reactions
More Complex Reactions | Chemistry Optional Notes for UPSC
We can write the reaction rates as:
More Complex Reactions | Chemistry Optional Notes for UPSC
The exact solutions of these is straightforward, in principle, but rather involved, so we will just state the exact solutions, which are
More Complex Reactions | Chemistry Optional Notes for UPSC
where
More Complex Reactions | Chemistry Optional Notes for UPSC

Steady-State Approximations

Consider the following consecutive reaction in which the first step is reversible:
More Complex Reactions | Chemistry Optional Notes for UPSC
We can write the reaction rates as:
More Complex Reactions | Chemistry Optional Notes for UPSC
These equations can be solved explicitly in terms of [A], [I], and [P], but the math becomes very complicated quickly. If, however, k2 + k−1 ≫ k1 (in other words, the rate of consumption of I is much faster than the rate of production of I ), we can make the approximation that the concentration of the intermediate species, I, is small and constant with time:
More Complex Reactions | Chemistry Optional Notes for UPSC
Equation 21.22 can now be written as
More Complex Reactions | Chemistry Optional Notes for UPSC
where [I]ss is a constant represents the steady state concentration of intermediate species, [I]. Solving for [I]ss,
More Complex Reactions | Chemistry Optional Notes for UPSC
We can then write the rate equation for species A as
More Complex Reactions | Chemistry Optional Notes for UPSC
Integrating,
More Complex Reactions | Chemistry Optional Notes for UPSC
Equation 21.28 is the same equation we would obtain for apparent 1st order kinetics of the following reaction:
More Complex Reactions | Chemistry Optional Notes for UPSC
where
More Complex Reactions | Chemistry Optional Notes for UPSC
Figure 9.4.3 displays the concentration profiles for species, A, I, and P with the condition that k2 + k−1 ≫ k1. These types of reaction kinetics appear when the intermediate species, I, is highly reactive.
More Complex Reactions | Chemistry Optional Notes for UPSC

Lindemann Mechanism

Consider the isomerization of methylisonitrile gas,  CH3NC, to acetonitrile gas,  CH3CN:
More Complex Reactions | Chemistry Optional Notes for UPSC
If the isomerization is a unimolecular elementary reaction, we should expect to see 1st order rate kinetics. Experimentally, however, 1st order rate kinetics are only observed at high pressures. At low pressures, the reaction kinetics follow a 2nd order rate law:
More Complex Reactions | Chemistry Optional Notes for UPSC
To explain this observation, J.A. Christiansen and F.A. Lindemann proposed that gas molecules first need to be energized via intermolecular collisions before undergoing an isomerization reaction. The reaction mechanism can be expressed as the following two elementary reactions
More Complex Reactions | Chemistry Optional Notes for UPSC
where M can be a reactant molecule, a product molecule or another inert molecule present in the reactor. Assuming that the concentration of A∗ is small, or k≪ k2 + k−1, we can use a steady-state approximation to solve for the concentration profile of species B with time:
More Complex Reactions | Chemistry Optional Notes for UPSC
Solving for [A],
More Complex Reactions | Chemistry Optional Notes for UPSC
The reaction rates of species  A and  B  can be written as
More Complex Reactions | Chemistry Optional Notes for UPSC

where
More Complex Reactions | Chemistry Optional Notes for UPSC
At high pressures, we can expect collisions to occur frequently, such that k−1[M] ≫ k2. Equation 21.33 then becomes
More Complex Reactions | Chemistry Optional Notes for UPSC
which follows  1st order rate kinetics.
At low pressures, we can expect collisions to occurs infrequently, such that  k−1[M] ≪ k2. In this scenario, equation 21.33 becomes
More Complex Reactions | Chemistry Optional Notes for UPSC
which follows second order rate kinetics, consistent with experimental observations.

Equilibrium Approximations 

Consider again the following consecutive reaction in which the first step is reversible:
More Complex Reactions | Chemistry Optional Notes for UPSC
Now let us consider the situation in which k≪ k1 and k−1. In other words, the conversion of I to P is slow and is the rate-limiting step. In this situation, we can assume that [A] and [I] are in equilibrium with each other. As we derived before for a reversible reaction in equilibrium,
More Complex Reactions | Chemistry Optional Notes for UPSC
or, in terms of [I],
More Complex Reactions | Chemistry Optional Notes for UPSC
These conditions also result from the exact solution when we set  k2 ≈ 0. When this is done, we have the approximate expressions from the exact solution:
More Complex Reactions | Chemistry Optional Notes for UPSC
and the approximate solutions become
More Complex Reactions | Chemistry Optional Notes for UPSC
In the long-time limit, when equilibrium is reached and transient behavior has decayed away, we find
More Complex Reactions | Chemistry Optional Notes for UPSC
Plugging the above equation into the expression for  d[P]/dt,
More Complex Reactions | Chemistry Optional Notes for UPSC
The reaction can thus be approximated as a 1st order reaction
More Complex Reactions | Chemistry Optional Notes for UPSC
with
More Complex Reactions | Chemistry Optional Notes for UPSC

Figure  9.4.4 displays the concentration profiles for species,  A,  I, and  P with the condition that  k≪ k1 = k−1. When  k1 = k−1, we expect  [A] = [I]. As can be seen from the figure, after a short initial startup time, the concentrations of species  A and  I are approximately equal during the reaction.

More Complex Reactions | Chemistry Optional Notes for UPSC

The document More Complex Reactions | Chemistry Optional Notes for UPSC is a part of the UPSC Course Chemistry Optional Notes for UPSC.
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