Q1: In the following reactions, P, Q, R, and S are the major products.
(a) P is a primary alcohol with four carbons.
(b) Q undergoes Kolbe's electrolysis to give an eight-carbon product.
(c) R has six carbons and it undergoes Cannizzaro reaction.
(d) S is a primary amine with six carbons. [JEE Advanced 2023 Paper 2]
Ans: (b)
Ans: 12
Alkene on treatment with ozone (O3) followed by treatment with Zn/H2O gives carbonyl compounds.
Carbonyl compounds react with NH2OH to give oximes.
There are four sp2-carbon atoms, four sp2-nitrogen atoms and four sp2-oxygen atoms as shown in structures I and II.
Therefore, total number of atoms having sp2-hybridisation are twelve (12).
Q2: The major product formed in the following reaction of
(a)
(b)
(c)
(d) [JEE Advanced 2021 Paper 1]
Ans: (b)
It is a case of Birch reduction. Alkynes on reaction with alkali metal in liq. NH3 gives trans-alkene. But terminal alkynes do not get reduced.
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1. What are haloalkanes and haloarenes? |
2. What is the significance of haloalkanes and haloarenes in JEE Advanced exam? |
3. What are some common reactions of haloalkanes and haloarenes? |
4. How can I differentiate between haloalkanes and haloarenes? |
5. What are some applications of haloalkanes and haloarenes in real life? |
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