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JEE Advanced Previous Year Questions (2018 - 2023): Alternating Current | Physics for JEE Main & Advanced PDF Download

2023

Q1: A series LCR circuit is connected to a 45sin⁡(ωt) Volt source. The resonant angular frequency of the circuit is   105 rad s−1 and current amplitude at resonance is I0. When the angular frequency of the source is   ω = 8 × 104 rad s−1, the current amplitude in the circuit is 0.05I0. If  L = 50 mH, match each entry in List-I with an appropriate value from List-II and choose the correct option.JEE Advanced Previous Year Questions (2018 - 2023): Alternating Current | Physics for JEE Main & Advanced

(a) P→2,Q→3,R→5,S→1
(b) P→3,Q→1,R→4,S→2
(c) P→4,Q→5,R→3,S→1
(d) P→4,Q→2,R→1,S→5                [JEE Advanced 2023 Paper 1]
Ans:
(b)

JEE Advanced Previous Year Questions (2018 - 2023): Alternating Current | Physics for JEE Main & Advanced

JEE Advanced Previous Year Questions (2018 - 2023): Alternating Current | Physics for JEE Main & Advanced

At, ω = 8 × 104 rad s−1 
JEE Advanced Previous Year Questions (2018 - 2023): Alternating Current | Physics for JEE Main & Advanced

From (i) and (ii), we get

JEE Advanced Previous Year Questions (2018 - 2023): Alternating Current | Physics for JEE Main & Advanced

= 400 mA

JEE Advanced Previous Year Questions (2018 - 2023): Alternating Current | Physics for JEE Main & Advanced

JEE Advanced Previous Year Questions (2018 - 2023): Alternating Current | Physics for JEE Main & Advanced

JEE Advanced Previous Year Questions (2018 - 2023): Alternating Current | Physics for JEE Main & Advanced

The document JEE Advanced Previous Year Questions (2018 - 2023): Alternating Current | Physics for JEE Main & Advanced is a part of the JEE Course Physics for JEE Main & Advanced.
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