Q1: If PQ = 5 and PR = 12, find QR.
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Q2: Find x
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Q3: An isosceles triangle has a vertex angle whose degree measure is 48°. Find the degree measure of each base angle.
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Let x represent the number of degrees in angles B and C
Therefore, ∠B measures 66 and ∠C measures 66°.
Q4: l || m and m ∠a = 100°. Find the number of degrees in angles b, c, d, e, f, g, and h.
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Ans: Because ∠a and ∠d are vertical angles, ∠d measures 100°. Using supplementary angles, m ∠b = 180° – 100° = 80° and m ∠c = 180° – 100° = 80°; therefore m ∠b = m∠c = 80°. Use either property of parallel lines— corresponding angles or alternate interior angles—to obtain the remainder of the answers. For example, m ∠b = m ∠f by corresponding angles or m ∠c = m ∠f by alternate interior angles. Thus, m ∠b = m ∠c = m ∠g = m ∠f = 80° and m ∠e = m ∠h = m ∠d = 100°.
Q5: AB || ED, ∠B = 70° and ∠ACB = 65°. Find the number of degrees in x.
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Ans: Knowing two angles of ∆ ABC, ∠A = 45°. Angles A and E are alternate interior angles. Therefore, ∠A = ∠E, since AB || DE. Thus ∠x = 45°
Q6: Find x, y, and z
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Ans: Since vertical angles are equal, ∠ y = 105°. The same is true for x and z: x = z. Any two adjacent angles such as z and 105° are supplementary. Therefore,
Q7: If BA ⊥ AC, find the number of degrees in angle x.
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Ans: Since BA ⊥ AC, ∠BAC = 90°. Therefore, x° + x° + x° + 45° = 90°
Q8: If PQ is a straight line, express y in terms of x.
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Ans: A straight line forms a straight angle. Therefore y in terms of x
Q9: If LN ⊥ NM, express the number of degrees in x in terms of y.
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Ans: Since LN ⊥ MN, ∠LNM measures 90°.
Q10: Find the distance between the points (7, 9) and (1, 1).
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Also important is the formula for finding the midpoint of a line segment.
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