Class 6 Exam  >  Class 6 Notes  >  Maths Olympiad Class 6  >  Olympiad Notes: Whole Numbers

Olympiad Notes: Whole Numbers | Maths Olympiad Class 6 PDF Download

Introduction

  • Numbers play an important role in our life. 
  • We use numbers in our day to day life to count things. 
  • While counting we use numbers to represent any quantity, to measure any distance or length.                                              

Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

                        3 apples and 3 pepper                                  Discount                          City distance                                             Length of the table 

  • The counting numbers starting from 1, 2, 3, 4, 5, ……… are termed as  natural numbers. 
  • The set of counting numbers and zero are known as whole numbers.
  •  Whole numbers are 0, 1, 2, 3, 4, 5, 6, 7,…….. and so on.Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Example: Write the next three natural numbers after 10999. 
Solution: 10999 + 1 = 11000
11000 + 1= 11001
11001 + 2 = 11002.
Thus, 11000, 11001, 11002 are the next three natural numbers after 10999.

Whole numbers on a number line 

Number Line 

A pictorial representations of numbers evenly marked on a straight line is known as a number line. 

  • To mark whole numbers on a number line draw a horizontal line and mark a point on it as 0.
  •  Extend this line towards right direction. 
  • Starting from 0, mark points 1, 2, 3, 4, 5, 6, 7, 8, 9….on a line at equal distance towards right side.
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6
  • There is no whole number on the left of zero. Therefore zero is the smallest whole number.

Comparison using Number Line

The number line also helps us to compare two whole numbers. i.e., to decide which of the two given whole numbers is greater or smaller.

  • A whole number is greater than all the whole numbers which lie to the left of it on the number line. 
  • A whole number is less than all the whole numbers which lie to the right of it on the number line
    Example:  We can say that 5 is less than 9 and write 5 < 9.
    We can also say that 5 is greater than 4 and write 5 > 4.Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Example: Identify which whole number comes first on the number line in each pair and write the appropriate sign (> or <) between them:
(a) 507 and 503
(b) 338 and 342

Sol:  (a) 503 is on the left side of 507 on the number line. So, 507 > 503.

Olympiad Notes: Whole Numbers | Maths Olympiad Class 6(b) 338 is on the left side of 342 on the number line. So, 342 > 338.Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Operations on a number line

Addition 

For eg: Add 2 and 5. i.e 2 + 5.

  • Start from 0, 2 jumps towards right. You reach at 2. 
  • Start from 2, 5 jumps towards right. You reach at 7. 
  • Therefore, 2 + 5 = 7.Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Subtraction 

For eg: Subtract 4 from 7.  i.e 7 - 4.

  • Start from 0, jump directly to 7. 
  • Start from 7,  4 jumps towards left. You reach at 3.
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Multiplication 

For eg:  Multiply 3 and 2 i.e. 3 x 2 

  • Multiplication means repeated addition. Thereofore 3 x 2 means 3 added twice.
  • Start from 0. Make 2 jumps (each jump of 3 units).You reach at 6.
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Division

For eg: 6 ÷ 3 = 2. 

  • Start from 6 and subtract 3 for a number of times till 0 is reached. 
  • The number of times 3 is subtracted gives the quotient.Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Ques: Using the number line, determine the following products:
(a) 3 x 3
(b) 4 x 2

Sol: (a)

  • Start from 0. Make 1 jump of 3 steps towards right. You reach at 3.     
  • Start from 3.  Make 1 jump of 3 steps towards right. You reach at 6.     
  • Start from 6. Make 1 jump of 3 steps towards right. You reach at 9.
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Therefore, 3 x 3 = 9

(b) 

  • Start from 0.  Make 1 jump of 4 steps towards right. You reach at 4.      
  • Start from 4.  Make 1 jump of 4 steps towards right. You reach at 8.
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Therefore, 4 x 2 = 8.

Predecessor and Successor

Predecessor

  • The number which comes right before a given number is called its predecessor.
  • The predecessor of a whole number found by subtracting 1 from it.

Number - 1 = Predecessor

Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Successor

  • The number which comes right after a given number is called its successor.
  • The successor of a whole number found by adding 1 to it.

Number + 1 = Successor.

Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Properties of addition 

Closure property 

  • For any two whole numbers a and b, their sum  a + b is always a whole number.
  • For eg:  12 + 45 = 57. Here, 12, 45 and 57 all are whole numbers.
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Commutative property

  • For any two whole numbers a and b, a +b = b + a. 
  • We can add any two whole numbers in any order.
     For eg:  12 + 45 = 45 + 12
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Associative property

  • For any three whole numbers a, b and c, (a + b) + c = a + (b + c). 
  • This means the sum is regardless of how grouping is done.
    For eg:  31 + (24 + 38) = (31 + 24) + 38
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6 

 Additive identity property

  • For every whole number a, a + 0 = a.
  • Therefore ‘0’ is called the Additive identity.
    E.g. 19 + 0 = 19
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Example: Find the sum of 435, 216 and 165
Sol: 435 + 216 + 165
Now, 5 + 5 = 10. So, we add 435 + 165 first.
= (435 + 165) + 216
= 600 + 216 = 816

Example: Find the sum by suitable arrangement:
(a) 837 + 208 + 363            
(b) 1962 + 453 + 1538 + 647      

Sol: (a) 837 + 208 + 363
Now, 7 + 3 = 10.
So, we add 837 + 363 first.
= (837 + 363) + 208
= 1200 + 208 = 1408

(b) 1962 + 453 + 1538 + 647
Now, 2 + 8 = 10 .So, we make one group of (1962 + 1538)
3 + 7 = 10.  Next we make another group of (453 + 647)
= (1962 + 1538) + (453 + 647)
=3500 + 1100 = 4600

Properties of subtraction 

Closure property

  • For any two whole numbers, a and b, if a  > b then a – b is a whole number.
  • If a < b then a – b is never a whole number.
  •  Closure property is not always applicable to subtraction.
    E.g. 150 – 100 = 50, is a whole number but 100 – 150 = -50 is not a whole number.
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Commutative property

  • For any two whole numbers a and b, a – b ≠  b – a . 
  • Hence subtraction of whole number is not commutative.
    E.g  16 – 7 = 9 but  7 – 16 ≠ 9
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Associative property

  • For any three whole numbers a, b and c, (a – b) – c ≠ a – (b – c). 
  • Hence  subtraction of whole numbers is not associative.
    E.g.  25 – (10 – 4) = 25 – 6 = 19  
    Also,  (25 – 10) – 4 = 15 – 4 = 11. This means that 25 – (10 – 4) ≠ (25 – 10) – 4
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

(iv) If 𝒂 is any whole number other than zero, then 𝒂 – 𝟎 = 𝒂 but 𝟎 − 𝒂 is not defined.

For eg: 
(i) 18 – 5 = 13 but 5 – 18 is not defined in whole numbers. 
(ii) 30 – 12 = 18 but 12 – 30 is not defined in whole numbers 

(v) If 𝒂, 𝒃 and 𝒄 are whole numbers such that 𝒂 – 𝒃 = 𝒄, then 𝒃 + 𝒄 = 𝒂Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

For eg:
(i) If 25 – 16 = 9 then 25 = 9 + 16,
(ii) If 46 – 8 = 38 then 46 = 38 + 8 

Example: Solve the following:

(i) 367 – 99
= 367 + (– 100 + 1)
= 367 – 100 + 1
= (367 + 1) – 100
= 368 – 100
= 268

(ii) 5689 – 99
= 5689 + (- 100 +1)
= 5689 – 100 + 1
= (5689 + 1) – 100
= 5690 – 100
= 5590

Properties of multiplication

Closure property

  • For any two whole numbers a and b,their product  a x b is always a whole number. 
  • E.g. 12 x 7 =  84. Here,  12, 7 and 84 all are whole numbers.
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Commutative property

  • For any two whole numbers a and b, a x b = b x a.
  • Order of multiplication is not important.
    E.g  11 x 6 =  66 and   6 x 11 = 66 Therefore, 11 x 6 = 6 x 11.
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Associative property

  • For any three whole numbers a, b and c, (a x b) x c = a x (b x c). 
  • This means the product is regardless of how grouping is done.
     E.g   8 x (4 x 5) = 8 x 20 = 160;   (8 x 4) x 5 = 32 x 5 = 160 Therefore,  8 x (4 x 5) = (8 x 4) x 5
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6
  • We can explain the associative property with the help of following example 
  • Count the number of dots in figure (a) and figure (b)
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6
  •  In figure (a), there are 2 rows and 2 columns which means 2 x 2 dots in each box. So the total number of dots are (2 x 2) x 3 = 12 
  • In figure (b), there are 3 rows and 2 columns which means 3 x 2 dots in each box. So the total number of dots are 2 x (3 x 2) = 12
  • This explain the associative property of multiplication.

Multiplicative identity

  • For any whole number a, a x 1 = a.
  • Since any number multiplied by 1 doesn’t change its identity 
  • Hence 1 is called as multiplicative identity of a whole number.
    E.g. 21 x 1 = 21
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Multiplication by zero

  • For any whole number a, a x 0 = 0,
  •  E.g 25 x 0 = 0
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Distributive property of multiplication over Addition

  • This property is used when we have to multiply a number by the sum.
  • If 𝒂, 𝒃&𝒄 are any three whole numbers, then 𝒂 × (𝒃 + 𝒄) = 𝒂 × 𝒃 + 𝒂 × 𝒄.

Example: Find the product by suitable rearrangement:
(i) 4 × 1768 × 25
(ii) 2 × 166 × 50
(iii) 285 × 4 × 75
(iv) 625 × 279 × 16

Sol: 
(i) 4 × 1768 × 25= (4 × 25) × 1768 (by commutative property)
= 100 × 1768 = 176800
(ii) 2 × 166 × 50= (2 × 50) × 166 (by commutative property)
= 100 × 166 = 16600
(iii) 285 × 4 × 75= 285 × (4 × 75) (by commutative property)
= 285 × 300 = 85500
(iv) 625 × 279 × 16= (625 × 16) × 279 (by commutative property)
= 10000 × 279 = 2790000

Properties of division 

Closure property

  • For any two whole numbers a and b, a ÷ b is not always a whole number. 
  • Hence closure property is not applicable to division. 
    For eg:  68 and 5 are whole numbers but 68 ÷ 5 is not a whole number.

    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Commutative property

  • For any two whole numbers a and b, a ÷ b ≠ b ÷ a. 
  • This means division of whole number is not commutative. 
    For eg: 16 ÷ 4 ≠ 4 ÷ 16  
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Associative property

  • For any 3 whole numbers a, b and c,(a ÷ b)  ÷ c ≠ a ÷ (b ÷ c)  
  •  For eg: consider (80 ÷ 10) ÷ 2 = 8 ÷ 2 = 4 80 ÷ (10 ÷2) = 80 ÷ 5 = 16 (80 ÷ 10) ÷ 2 ≠80 ÷ (10 ÷2) 
  • Hence division does not follow associative property. 
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Division by 1

  • For any whole number a, a ÷ 1 = a.
  • This means any whole number divided by 1 gives the quotient as the number itself. 
    For eg: 14 ÷ 1 = 14;                 
     26 ÷ 1 = 26  
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Division of 0 by any whole number

  • For any whole number, a ≠ 0, 0 ÷ a = 0, 
  • This shows zero divided by any whole number (other than zero) gives the quotient as zero.
      For eg: (i) 0 ÷ 1 = 0;                    
    (ii) 0 ÷ 25 = 0;         
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6
                  

Division by 0

  • To divide any number, say 7 by 0, we first have to find  out a whole number which when multiplied by 0 gives us 7. This is not possible. 
  • Therefore, division by 0 is not defined.
    Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

Example: Solve the following
(i) 636 ÷ 1

(ii) 0 ÷ 253
(iii) 246 – (121 ÷ 121)
(iv) (45÷ 5) – (9÷ 3)
Sol: (i) 636 ÷ 1 = 636 (∵ a ÷1 = a )
(ii) 0 ÷ 253 = 0 (∵ 0 ÷ a = 0)
(iii) 246 – (121 ÷ 121)
= 246 – (1)
= 246 – 1
= 245
(iv) (45÷ 5) – (9 ÷ 3)
= 9 – 3 = 6

The document Olympiad Notes: Whole Numbers | Maths Olympiad Class 6 is a part of the Class 6 Course Maths Olympiad Class 6.
All you need of Class 6 at this link: Class 6
8 videos|98 docs|60 tests

Top Courses for Class 6

FAQs on Olympiad Notes: Whole Numbers - Maths Olympiad Class 6

1. What are whole numbers and how are they represented on a number line?
Ans. Whole numbers are numbers without any fractions or decimals, starting from zero and counting upwards (0, 1, 2, 3, ...). They can be represented on a number line by marking each whole number at equal intervals, starting from zero.
2. What are the basic operations that can be performed on a number line using whole numbers?
Ans. The basic operations that can be performed on a number line using whole numbers are addition, subtraction, multiplication, and division. These operations involve moving left or right on the number line to perform the calculations.
3. How do you find the predecessor and successor of a whole number on a number line?
Ans. The predecessor of a whole number is the number that comes before it on the number line, while the successor is the number that comes after it. To find the predecessor, you move one step to the left on the number line, and to find the successor, you move one step to the right.
4. What are the properties of subtraction when working with whole numbers on a number line?
Ans. When subtracting whole numbers on a number line, the distance between the subtrahend and the minuend represents the difference between the two numbers. Subtraction is essentially the reverse of addition, and the properties of subtraction include the commutative property (changing the order of subtraction does not change the result) and the associative property (grouping numbers in different ways does not change the result).
5. How can whole numbers be applied in Olympiad exams and what are some key concepts to remember?
Ans. Whole numbers play a crucial role in Olympiad exams, where students are tested on their understanding of basic arithmetic operations, number properties, and problem-solving skills. It is important to remember concepts such as place value, addition, subtraction, multiplication, division, and number patterns when dealing with whole numbers in Olympiad exams. Practice and familiarity with whole numbers on a number line can help students excel in these exams.
8 videos|98 docs|60 tests
Download as PDF
Explore Courses for Class 6 exam

Top Courses for Class 6

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

Sample Paper

,

Semester Notes

,

Exam

,

shortcuts and tricks

,

Free

,

practice quizzes

,

Objective type Questions

,

Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

,

Viva Questions

,

Important questions

,

mock tests for examination

,

study material

,

Extra Questions

,

Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

,

Previous Year Questions with Solutions

,

video lectures

,

Summary

,

Olympiad Notes: Whole Numbers | Maths Olympiad Class 6

,

pdf

,

past year papers

,

ppt

,

MCQs

;