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MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8 PDF Download

Q1: Find the volume of the given figure.
(a) 2400 cm³
(b) 1600 cm³
(c) 2200 cm³
(d) 1400 cm³

View Answer

Ans: (a)
Volume of a cuboid = l × b × h = 20 × 15 × 8 = 2400 cm³.

Q2: Find the area of the given rectangle.
(a) 16 cm²
(b) 100 cm²
(c) 625 cm²
(d) 50 cm²

View Answer

Ans: (b)
Area of rectangle = l × b = 25 × 4 = 100 cm².

Q3: Find the capacity of the cylinder. (π = 22/7)

(a) 1366 m³
(b) 1276 m³
(c) 1376 m³
(d) 1386 m³

View Answer

Ans: (d)

The capacity of a cylinder refers to the volume of space it can hold.
Hence, Volume = π × r²× h

Volume = 227 × 7 × 7 × 9

After simplifying, we get:

154 × 9 = 1386

Capacity / Volume of the cylinder = 1386 cm³

Q4: A cylindrical tank is having height 6m and radius 4 m. How much litres of water can be filled in the tank? (π = 3.14)
(a) 301430 litres
(b) 301460 litres
(c) 301440 litres
(d) 301450 litres

View Answer

Ans: (c)

The capacity of a cylinder refers to the volume of space it can hold.

Capacity of the tank = πr² h = 3.14 × 42 × 6 = 301.44 m³.
We know that, 1 m³ = 1000 litres
∴ 301.44 m³ = 301.44 × 1000 litres
= 301440 litres.

Q5: Find the height of the cylinder whose volume is 14.08 m³ and radius is 4 m.
(a) 0.54 m
(b) 0.56 m
(c) 0.14 m
(d) 0.28 m

View Answer

Ans: (d)
Volume of cylinder = πr² h

14.08 = 227 × 4² × x

x = 0.28 m

Q6: What is the volume of a cube with a side of 14 cm?
(a) 2642 cm³
(b) 2644 cm³
(c) 2744 cm³
(d) 2742 cm³

View Answer

Ans: (c)
Volume of cube = a³ = 14³ = 2744 cm³

Q7: Find the area of the given figure.

(a) 20cm²
(b) 50cm²
(c) 15cm²
(d) 25cm²

View Answer

Ans: (d)
Area of triangle = 12 × b × h = 12 × 10 × 5 = 25 cm²

Q8: Find the area of the given parallelogram.
(a) 142cm²
(b) 284cm²
(c) 144cm²
(d) 288cm²

View Answer

Ans: (d)
Area of parallelogram = b × h = 12 × 24 = 288cm².

Q9: Which of the following option is correct if a,b and c are the areas of the given figures (i), (ii) and (iii) respectively? (π = 22/7)

(a) (c) > (b) > (a)
(b) (a) > (b) > (c)
(c) (a) < (c) > (b)
(d) (b) < (a) > (c)

View Answer

Ans: (i) Area of triangle = 12 × b × h = 12 × 2 × 5 = 5 cm²

(ii) Area of rectangle = l × b = 5 × 2 = 10 cm²

(ii) Area of circle = π(r)² = 227 × (5)² = 5507 cm²

⇒ Area of Circle > Area of Rectangle > Area of Triangle

⇒ Option (a) is correct i.e. (c) > (b) > (a)

Q10: Find the area of the Lawn if the inner rectangle represents the house.

(a) 500m²
(b) 101m²
(c) 505m²
(d) 504m²

View Answer

Ans: (c)
Area of lawn can be found by subtracting the area of inner rectangle from square.
Hence, Area of lawn = Area of square – Area of rectangle
Area of lawn = (25)² – (15)(8)

Area of Lawn = 625 m² - 120 m²= 505 m²

Q11: Find the surface area of the given cuboid.

(a) 44 cm²
(b) 22 cm²
(c) 40 cm²
(d) 88 cm²

View Answer

Ans: (d)
Surface area cuboid = 2(lb + bh + lh) = 2(6 × 4 + 4 × 2 + 2 × 6) = 88 cm².

Q12: Find the surface area of the given cylinder.

(a) 113.14 cm²
(b) 113.16 cm²
(c) 112.16 cm²
(d) 112.14 cm²

View Answer

Ans: (a)

Total Surface Area = 2πr(h + r)

Total Surface Area = 2 × 3.14 × 2 × (7 + 2)

= 113.14 cm².

Q13: The internal measurement of a cuboidal room 15m × 6m × 4m. The room has to be painted along with the ceiling. If cost of painting is Rs 17 per m² . Find the total cost to be paid ?
(a) Rs 4916
(b) Rs 3916
(c) Rs 4686
(d) Rs 4386

View Answer

Ans: (d)
Surface area cuboid = 2(lb + bh + lh)
The floor of the room will not be painted.
∴ Surface area to be painted = 2(lb + bh + lh) – lb
= 2(15 × 6 + 4 × 6 + 4 × 15) – 15 × 6 = 258 m²
Total cost to be paid = 258 × 17 = Rs 4386.

Q14: Find the side of the cube whose surface area is 384m².
(a) 5 m
(b) 6 m
(c) 8 m
(d) 7 m

View Answer

Ans: (c)
Surface area cube = 6 a²
⇒ 384 = 6 (a²)

⇒ 3846 = 64 = a²

⇒ a = √64
⇒ a = 8 m.

Q15:The curved surface of the cylinder is 88 m². The height of the cylinder is 5 m, what is the radius of the cylinder?
(a) 6.8 cm
(b) 4.8 cm
(c) 1.8 cm
(d) 2.8 cm

View Answer

Ans: (b)
Curved Surface area of cylinder = 2πrh

88 = 2πr × 5

88 = 10πr

r = 8810π

r = 8.8π

r ≈ 8.83.1416 ≈ 2.8 meters

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FAQs on MCQ (with Solutions): Mensuration - Mathematics (Maths) Class 8

1. What is mensuration in mathematics?

Ans. Mensuration is a branch of mathematics that deals with the measurement of geometric figures and their parameters, such as length, area, volume, and surface area. It involves calculations related to two-dimensional and three-dimensional shapes.

2. How do you calculate the area of a rectangle?

Ans. The area of a rectangle can be calculated using the formula: Area = length × width. Simply multiply the length of the rectangle by its width to find the total area.

3. What is the formula for finding the volume of a cylinder?

Ans. The volume of a cylinder can be calculated using the formula: Volume = π × r² × h, where r is the radius of the base and h is the height of the cylinder. Here, π (pi) is approximately 3.14.

4. How do you find the circumference of a circle?

Ans. The circumference of a circle can be found using the formula: Circumference = 2 × π × r, where r is the radius of the circle. Alternatively, it can also be calculated using the diameter with the formula: Circumference = π × d, where d is the diameter.

5. What is the difference between perimeter and area?

Ans. Perimeter is the total distance around a two-dimensional shape, calculated by adding the lengths of all sides. Area, on the other hand, measures the space contained within a shape and is calculated using specific formulas based on the shape's dimensions.

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