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MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8 PDF Download

Q1: Find the volume of the given figure.
MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8(a) 2400 cm3
(b) 1600 cm3
(c) 2200 cm3
(d) 1400 cm3

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (a)
Volume of a cuboid = l × b × h = 20 × 15 × 8 = 2400 cm3.

Q2:  Find the area of the given rectangle.
MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8
(a) 16 cm2
(b) 100 cm2
(c) 625 cm2
(d) 50 cm2

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (b)
Area of rectangle = l × b = 25 × 4 = 100 cm2.

Q3: Find the capacity of the cylinder. (π = 22/7)
MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8

(a) 1366 m3
(b) 1276 m3
(c) 1376 m3
(d) 1386 m3

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (d)
Volume of cylinder MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8

Q4: A cylindrical tank is having height 6m and radius 4 m. How much litres of water can be filled in the tank? (π = 3.14)
(a) 301430 litres
(b) 301460 litres
(c) 301440 litres
(d) 301450 litres

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (c)
Capacity of the tank = πr2 h = 3.14 × 42 × 6 = 301.44 m3.
We know that, 1 m3 = 1000 litres
∴ 301.44 m3 = 301.44 × 1000 litres
= 301440 litres.

Q5: Find the height of the cylinder whose volume is 14.08 m3 and radius is 4 m.
(a) 0.54 m
(b) 0.56 m
(c) 0.14 m
(d) 0.28 m

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (d)
Volume of cylinder = πr2 h
MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8

Q6: What is the volume of the given figure?
(a) 2642 cm3
(b) 2644 cm3
(c) 2744 cm3
(d) 2742 cm3

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: Volume of cube = a3 = 143 = 2744 cm3   

Q7: Find the area of the given figure.
MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8

(a) 20cm2
(b) 50cm2
(c) 15cm2
(d) 25cm2

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (d)
Area of triangle MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8

Q8: Find the area of the given parallelogram.
MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8(a) 142cm2
(b) 284cm2
(c) 144cm2
(d) 288cm2

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (d)
Area of parallelogram = b × h = 12 × 24 = 288cm2.

Q9: Which of the following option is correct if a,b and c are the areas of the given figures (i), (ii) and (iii) respectively? (π = 22/7)
MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8

(a) a < b < c
(b) a > b > c
(c) a < b > c
(d) b < c > a

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (a)
MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8
Area of rectangle = l × b = 5 × 2 = 10cm
MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8

Q10:  Find the area of the Lawn.
MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8

(a) 500m2
(b) 101m2
(c) 505m2
(d) 504m2

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (c)
Area of lawn can be found by subtracting the area of inner rectangle from square.
Hence, Area of lawn = Area of square – Area of rectangle = (25)2 – (15)(8) = 505m2.

Q11: Find the surface area of the given cuboid.
MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8

(a) 44 cm2
(b) 22 cm2
(c) 40 cm2
(d) 88 cm2

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (d)
Surface area cuboid = 2(lb + bh + lh) = 2(6 × 4 + 4 × 2 + 2 × 6) = 88 cm2.

Q12: Find the surface area of the given cylinder.
MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8

(a) 113.14 cm2
(b) 113.16 cm2
(c) 112.16 cm2
(d) 112.14 cm2 

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (a)
Curved Surface area of cylinder = 2πrh + 2πr2 MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8
= 113.14 cm2.

Q13: The internal measurement of a cuboidal room 15m × 6m × 4m.The room has to be painted along with the ceiling. If cost of painting is Rs 17 per m2, Find the total cost to be paid.
(a) Rs 4916
(b) Rs 3916
(c) Rs 4686
(d) Rs 4386

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (d)
Surface area cuboid = 2(lb + bh + lh)
The floor of the room will not be painted.
∴ Surface area to be painted = 2(lb + bh + lh) – lb
= 2(15 × 6 + 4 × 6 + 4 × 15) – 15 × 6 = 258 m2
Total cost to be paid = 258 × 17 = Rs 4386.

Q14: Find the side of the cube whose surface area is 384m2.
(a) 5 m
(b) 6 m
(c) 8 m
(d) 7 m

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (c)
Surface area cube = 6 a2
⇒ 384 = 6 (a2)
⇒ a = 8 m.

Q15: The curved surface of the cylinder is 88 cm2. The height of the cylinder is 5 m, what is the radius of the cylinder?
(a) 6 cm
(b) 4 cm
(c) 1 cm
(d) 2 cm

MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8  View Answer

Ans: (b)
Curved Surface area of cylinder = 2πrh + 2πr2 = 2πr(r + h)
MCQ (with Solutions): Mensuration | Mathematics (Maths) Class 8

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FAQs on MCQ (with Solutions): Mensuration - Mathematics (Maths) Class 8

1. What is mensuration?
Ans. Mensuration is the branch of mathematics that deals with the measurement of geometric figures and their parameters such as area, perimeter, volume, etc.
2. How can we calculate the area of a circle?
Ans. The area of a circle can be calculated using the formula A = πr^2, where A is the area and r is the radius of the circle.
3. What is the difference between perimeter and area?
Ans. Perimeter is the distance around a two-dimensional shape, while area is the space enclosed by the shape. Perimeter is measured in linear units, while area is measured in square units.
4. How do we find the volume of a sphere?
Ans. The volume of a sphere can be calculated using the formula V = (4/3)πr^3, where V is the volume and r is the radius of the sphere.
5. What is the formula for calculating the perimeter of a rectangle?
Ans. The perimeter of a rectangle can be calculated using the formula P = 2(l + w), where P is the perimeter, l is the length, and w is the width of the rectangle.
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