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Class 4 Exam  >  Class 4 Notes  >  Mathematics Olympiad Class 4  >  Maths Olympiad Previous Year Paper -1

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4 PDF Download

Note: The questions provided in this document are similar to the questions that were asked in the actual Olympiad exam. So, we recommend you study these for your Olympiad preparation

Logical Reasoning

Q1: Veer is in a line. If he is 6th from the front and 12th from the back, how many people are there in total in the line?
(a) 20
(b) 17
(c) 19
(d) 18

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)

  • To find the total number of people in the queue, we can add Veer's position from the front and his position from the back, then subtract 1 (since Veer is counted in both positions).
  • So, the calculation is: 6 (from the front) + 12 (from the back) - 1 = 17.
  • This means there are a total of 17 people in the queue.
  • Thus, the correct answer is 17.

Q2: Find the combination of numbers so that the given letters are arranged accordingly to form a meaningful English word. 
K A T R M E
(a) 5, 2, 4, 1, 6, 3
(b) 5, 2, 1, 4, 6, 3
(c) 3, 4, 6, 2, 1, 5
(d) 4, 2, 3, 1, 6, 5

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (a)

  • The letters K, A, T, R, M, E can be rearranged to form the word "MARKET".
  • Using the combination 5, 2, 4, 1, 6, 3 corresponds to the letters M, A, R, K, E, T respectively.
  • This arrangement gives us a meaningful English word, which is "MARKET".
  • Other combinations do not yield a valid English word when the letters are rearranged.

Q3: Observe the pattern of numbers given:
Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4

Which pair of the given Roman numerals  must fill the blank spaces?  
(a) C, M 
(b) C, X 
(c) D, C
(d) C, L 

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)
120 = 100 + 10 + 10 = C, X 

Q4: Four of the following five are alike in a certain way and so form a group. 
Which is the one that does not belong to that group? 
(a) QO2 
(b) PN2 
(c) TR2 
(d) HF2

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (a)
Only option (a) has vowel.

Q5: In the following question, select the missing number from the given series. 
23, 11, 34, 45, 79, ? 
(a) 121 
(b) 124
(c) 163 
(d) 169

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)
23+11=34
11+34=45
34+45=79
45+79=124.

Q6: Which word will appear first when arranged in order of dictionary? 
(a) Ankle 
(b) Anger
(c) Antique
(d) Aster

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (c)
Except Air all are fuel.

Q7: In a certain code language, "RUN" is written as "28" and "BUS" is written as "39”. How is "GUN" written in that code language? 
(a)  37
(b)  38 
(c)  39 
(d)  42

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (c)
Add the ranking of opposite letters of the word „ GUN’ RUN = 9 + 6 + 13 = 28
BUS=25+6+8=39
GUN=20+6+13=39

Q8: Suman walks 15 km towards north. She turns right and walks another 15 km. She turns right and walks another 15 km. In which direction is she from her starting point? 
(a) North 
(b) South 
(c) East 
(d) West

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (c)
Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4

Q9: If the given clock is 45 minutes slow, then the CORRECT time after half an hour will be ______
Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4(a) 6 O'clock
(b) 6: 30  
(c) 7 O'clock 
(d) 5: 30

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)
Time shown on the clock is 5: 15 Since, clock is 45 minutes slow, so the correct time will be 6'Oclock. Time after half an hour will be 6 : 30.

Q10: A series is given with one term missing. Select the correct alternative from the given ones that will complete the series. 
AB, CD, EF, GH,  ? 
(A) HJ 
(B) HK 
(C) IJ 
(D) JI

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (c)
English Alphabet series Next two letters after H.

Mathematical Reasoning

Q11: Aman went on a 15-day journey. He stayed for 7 days in Manali and the remaining days in Shimla. What portion of his trip did he spend in Shimla?
(a) 8/7
(b) 7/8
(c) 8/15
(d) 7/15

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (c)

  • Aman's total trip duration = 15 days.
  • He spent 7 days in Manali.
  • Days spent in Shimla = 15 - 7 = 8 days.
  • The fraction of the trip spent in Shimla = 8 days out of 15 days = 8/15.

So, the correct answer is 8/15.

Q12: A string is 40 m long. A piece measuring 800 cm is cut from it. The remaining piece is then cut into 10 equal pieces. Find the length of each piece.
(a) 320 cm
(b) 350 cm
(c) 400 cm
(d) 410 cm

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (a)

  • First, convert the total length of the string from meters to centimeters: 
    40 m = 4000 cm.
  • Next, subtract the length of the piece cut from the string: 
    4000 cm - 800 cm = 3200 cm remaining.
  • Now, divide the remaining length by the number of equal pieces: 
    3200 cm ÷ 10 = 320 cm.
  • Thus, the length of each piece is 320 cm.

Q13: Priya had 500 stickers. After giving 150 stickers to her brother, what fraction of the total stickers remains with her?
(a) 5/7
(b) 3/10
(c) 7/10
(d) 7/9

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (c)

  • Initial number of stickers: Priya had 500 stickers.
  • Stickers given away: She gave away 150 stickers.
  • Remaining stickers: 500−150 = 350 stickers500 - 150 = 350 \text{ stickers} stickers
  • Fraction of stickers left: 350/500
  • Simplifying the fraction:Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4

Thus, the fraction of stickers left is 7/10.

Q14: In January, 4105 children went to the zoo, and in February, 2534 children visited. What is the total number of children who visited the zoo in these two months?
(a) 6548
(b) 6639
(c) 6670
(d) 6234

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)

  • Add the number of children from both months:
    Children in January: 4105
    Children in February: 2534
  • Calculate the total: 4105 + 2534 = 6639

Thus, the total number of children who visited the zoo in January and February is 6639.

Q15: Preeti purchased a piece of cloth that has four equal sides. What shape could this cloth be?
(a) Square
(b) Rectangle
(c) Triangle
(d) None of these

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (a)

  • The cloth has four equal sides, which means it is a square.
  • A rectangle has opposite sides that are equal, but not all four sides are equal.
  • A triangle has only three sides, so it cannot be the shape of the cloth.

Therefore, the correct shape of the cloth is a square.

Q16: Shreya purchased 86 kg 475 g of sugar, while Puneet acquired 79 kg 825 g of sugar. Who purchased a smaller amount of sugar and by what margin?
(a) Shreya, 6 kg 650 g
(b) Puneet, 6 kg 650 g
(c) Shreya, 7 kg 350 g
(d) Puneet, 7 kg 350 g

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)

  • To determine who bought less sugar, we need to compare the total amounts.
  • Shreya's sugar: 86 kg 475 g = 86475 g
  • Puneet's sugar: 79 kg 825 g = 79825 g
  • Puneet bought less sugar. The difference is 86475 g - 79825 g = 6650 g, which is 6 kg 650 g.

Q17: In which of the following options is 7 not in the hundreds place?
(a) 2790
(b) 3578
(c) 4789
(d) 5785

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)
The hundreds place is the third digit from the right in a number.

  • In 2790, the hundreds place is 2.
  • In 3578, the hundreds place is 5, so 7 is not in the hundreds place.
  • In 4789, the hundreds place is 4.
  • In 5785, the hundreds place is 5.

Thus, the only option where 7 is not in the hundreds place is 3578.

Q18: A city has a population of 92582. Round off the population to the nearest hundreds.
(a) 92500
(b) 92600
(c) 93500
(d) 92580

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)
To round 92582 to the nearest hundred:

  • Look at the tens digit (which is 8).
  • Since 8 is 5 or more, we round the hundreds digit 5 up to 6.
  • Therefore, 92582 rounds up to 92600.

The correct rounded number is 92600.

Q19: Kanika has 4 photo albums. In each album, there are 10 pages. If there are 5 photos on each page, then how many total photos are there in all albums?
(a) 200
(b) 150
(c) 100
(d) 180

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (a)

  • To find the total number of photos, first calculate the total number of pages across all albums: 
    4 albums × 10 pages = 40 pages.
  • Next, determine the total number of photos by multiplying the total pages by the number of photos per page: 
    40 pages × 5 photos = 200 photos.
  • Thus, the total number of photos in all albums is 200.

Q20: Which Roman numeral is greatest?  
(a) DCLX 
(b) CDXL  
(c) DCXL 
(d) CDXX

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (a)
DCLX = 500 + 100 + 50 + 10 = 660
CDXL =(500-100) + (50-10) = 440
DCXL = 500 + 100 + (50- 10) = 640
CDXX =(500-100) + 10 + 10 = 420

Everyday Mathematics

Q21: Smallest 6-digit number is ............... 
(a) 1,11,111 
(b) 1,00,001  
(c) 1,10,010 
(d) 1,00,000  

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (d)
Smallest 6-digit number is  1,00,000. 

Q22: Which of the following is equivalent to  “five lakhs one hundred nine”?  
(a) 50109 
(b) 501009  
(c) 500109 
(d) 510090 

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (c)
Five lakh one hundred nine = 5,00,109.

Q23: From which Roman numeral, apart from  V, can I be subtracted?  
(a) I 
(b) X 
(c) L 
(d) C 

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)
As, = 10 – 1 = 9  
Therefore,  
I can be subtracted from X. 

Q24: 10 less than 100 is written as:  
(a) XV 
(b) XC  
(c) CX 
(d) LX 

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)
XC = 100 - 10 = 90

Q25: Compare and fill the box with appropriate  symbol.  
Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4 (a) > 
(b) <  
(c) = 
(d) None of these

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans:  (a)  
VI = 6 and IV = 4  So, 6 > 4 

Q26: Compare and fill the box with appropriate  symbol.  
Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4(a) > 
(b) <  
(c) = 
(d) None of these

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)  
CCCXXIV + CCLXIX = 324 + 269 = 593  and DCCLII – CLVI = 752 – 156 = 596  
So, 593 < 596

Q27: Number 75 is written as:  
(a) LXV 
(b) LXXV  
(c) CXV 
(d) LVV

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)
75 = 50 + 10 + 10 + 5 = LXXV

Q28: Which Roman numeral represents the  greatest three digit number?  
(a) IXIXIX 
(b) CMIXIX  
(c) CMXCIX 
(d) CMIIC

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (c)
The greatest 3-digit number is 999.
999 = 900 + 90 + 9 = (1000 - 100) + (100 - 10) + (10 - 1) = CMXCIX

Q29: Write the expanded notation for 3,00,123:  
(a) 300000 + 100 + 20 + 3  
(b) 300000 + 00000 + 0000 + 20 + 3  
(c) 300000 + 000 + 100 + 20 + 3  
(d) 300000 + 00 + 100 + 20 + 3

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (a)
Expanded form of 3,00,123  
= 3 × 100000 + 0 × 10000 + 0 × 1000 + 1 ×  100 + 2 × 10 + 3  
= 300000 + 0 + 0 + 100 + 20 + 3  
= 300000 + 100 + 20 + 3

Q30: What number is 1000 more than 69,090?  
(a) 79,000 
(b) 70,900  
(c) 70,090 
(d) 70,009

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (c)  
1000 more than 69,090  = 69,090 + 1000 = 70,090

Achievers Section

Q31: Sandhya’s user ID is a 5-digit number. In  which, ‘9’ is in the ten thousands place, ‘0’  is in the ones place, ‘8’ is in the thousands  place, ‘4’ is in the tens place and ‘2’ is in  the hundreds place. What is her user ID?  
(a) 90,842 
(b) 98,240  
(c) 89,204 
(d) 98,420 

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)
9 at (Ten Thousands Place)  
0 at (Ones Place) 
8 at (Ten Thousands Place)  
2 at (Hundreds Place)  
4 at (Tens Place)  
So, required 5-digit number is 98240. 

Q32: How many beads should be removed  from the tens place and hundreds place  in the abacus shown here if it has to  represent number 28 tens less than the  number shown in the abacus?  
(a) 2, 2
(b) 8, 2 
(c) 2, 1 
(d) 3, 0

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (b)
Abacus shows the number  = 686  
28 tens (280) less than the number shown  on abacus = 686 – 280 = 406  
So, we need to remove 8 beads from tens place and two beads from hundreds  place. 

Q33: What is the difference between the  greatest and the least three digit numbers  formed by using X, L, C and D? 
(a) DCXL 
(b) DCLX  
(c) CDXL 
(d) CCXX  

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (d)
The greatest number  = DCLX = 660  
The least number = CDXL = 440  
Difference = 660 – 440 = 220  = CCXX 

Q34: Choose the correct option from the  following.  
(a) 516 < DCVI 
(b) 256 = CCLVII  
(c) 408 ≠ CDVIII 
(d) 1005 > MD 

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (a)
(a) DCVI = 500 + 100 + 5 + 1  = 606 > 516  
(b) CCLVII = 100 + 100 + 50 + 5 + 1 + 1 = 257  ≠ 256  
(c) CDVIII = (500 – 100) + 5+ 1 + 1 + 1 = 408 =  408.  
(d) MD = 1000 + 500 = 1500 > 1005

Q35: If the second smallest 5-digit even number is formed by using all the digits 9, 2, 0, 4 and 3, then the digit in the ten thousands place stands for .................. hundreds. 
Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4(a) 204 
(b) 240  
(c) 200 
(d) 203

Maths Olympiad Previous Year Paper -1 | Mathematics Olympiad Class 4  View Answer

Ans: (c)
Smallest 5-digit even number formed by 9,  2, 0, 4, 3 = 20394
Second smallest 5-digit even number  formed by 9, 2, 0, 4, 3 = 20934  
So, the digit in the ten thousands place  stands for 200 hundreds.

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FAQs on Maths Olympiad Previous Year Paper -1 - Mathematics Olympiad Class 4

1. What topics are generally covered in the Maths Olympiad for Class 4?
Ans. The Maths Olympiad for Class 4 typically covers topics such as logical reasoning, mathematical reasoning, everyday mathematics, number operations, geometry, patterns, and simple problem-solving techniques. Students are tested on their ability to think critically and apply mathematical concepts in various scenarios.
2. How can I prepare effectively for the Class 4 Maths Olympiad?
Ans. To prepare effectively for the Class 4 Maths Olympiad, students should practice a variety of problems from previous year papers, focus on understanding concepts rather than rote memorization, use online resources, engage in group study sessions, and take mock tests to build confidence and improve time management skills.
3. What is the format of the Maths Olympiad exam for Class 4?
Ans. The Maths Olympiad exam for Class 4 usually consists of multiple-choice questions (MCQs) and problem-solving questions. The number of questions can vary, but the exam typically lasts for about 60 minutes. Students need to demonstrate their understanding of mathematical concepts and their ability to solve problems quickly and accurately.
4. Are there any specific books or resources recommended for Class 4 Maths Olympiad preparation?
Ans. Yes, there are several recommended books and resources for Class 4 Maths Olympiad preparation, including 'Mathematics Olympiad Class 4' by various publishers, workbooks that focus on logical reasoning and mathematical problem-solving, and online platforms that offer practice tests and interactive quizzes tailored to the syllabus of the Olympiad.
5. What are the benefits of participating in the Maths Olympiad for Class 4 students?
Ans. Participating in the Maths Olympiad offers several benefits for Class 4 students, including enhancing their problem-solving skills, boosting their confidence in mathematics, fostering a competitive spirit, and encouraging logical thinking. Additionally, it helps students identify their strengths and weaknesses in mathematics, which can guide their future learning.
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