Maths Olympiad Previous Year Paper - 1 | Math Olympiad for Class 5 PDF Download

Ans: (a)

• The sequence starts at 144 and decreases by 8 each time: 144 - 8 = 136, 136 - 8 = 128.
• Continuing this pattern, the next number should be 128 - 8, which equals 120.
• After 120, the sequence continues with 112 (120 - 8 = 112), confirming the pattern.
• Thus, the missing number is 120, making option (a) the correct answer.

Ans: (d)

• The question asks to find the odd one out among the options.
• Looking at the options, JJ20, RR36, and MM26 all have a pattern where the letters are repeated and the numbers are even.
• However, KK22 does not fit the pattern as it is not consistent with the others in terms of the number sequence.
• Thus, KK22 is the correct answer as it stands out from the rest.

Ans: (d)

• The word TUNNEL cannot be formed from the letters in INSTITUTIONALA because it requires two N's, but there is only one N available in the original word.
• In contrast, the words UNION, INSULT, and NATION can all be constructed using the available letters.
• Thus, the correct answer is TUNNEL as it is the only option that cannot be formed.

Ans: (b)

The new arrangement becomes : % 4 K M $ E 8 A C So, $ will be at the middle.

Ans: (a)
The order from eldest to youngest is M, N or R, Q So, M is the eldest.

Ans: (c)
Except Computer, all others are made up of wood.

Ans: (c)
The arrangement is: Priya, Megha, Beena, Garima, Latika

Ans: (a)
The pattern is x: (x × x + 8)

Ans: (c)

Ans: There is only one line of symmetry.

Ans: (d)
The arrangement of six friends according to their heights in ascending order is as follows: Surbhi < Tanya < Rukul < Anusha < Raag < Ankit So, it is clear from the above arrangement that Rukul is the third smallest.

Ans: (b)
The new word formed is, OMISECOMPR So, seventh letter from the right end is S.

Ans: (c)
Number of boys in the class = (16 + 1 + 16) = 33.

Ans: (d)
Eraser is used to erase something and here, eraser is called book. 

Ans: (d)
S indicates those students who play all three games.

Ans: (d)

• The fraction 3/8 can be converted to an equivalent fraction by multiplying both the numerator and denominator by the same number.
• If we multiply 3 by 4, we get 12, and if we multiply 8 by 4, we get 32.
• Thus, 12/32 is equivalent to 3/8.
• The other options do not maintain the same ratio as 3/8.

Ans: (b)

• The statement 6 m 8 cm = 6.80 m is incorrect because 8 cm is equal to 0.08 m, making the total 6.08 m, not 6.80 m.
• In contrast, the other options correctly convert the measurements into their decimal forms.
• For example, 4 L 360 mL is indeed 4.36 L, and 7 kg 40 g equals 7.040 kg when converted.
• Lastly, 8 km 738 m correctly converts to 8.738 km.

Ans: (b)

• To find the greatest 4-digit number, we should start with the highest digits available.
• The digits we have are 5, 7, 0, and 8. The largest digit is 8, so we place it first.
• Next, we choose the next largest digit, which is 7, followed by 5 and then 0.
• Arranging these gives us 8750, which is the largest possible number we can form with the given digits.

Ans: (b)

• The number is a 3-digit number with different digits.
• The sum of the digits equals 15.
• The tens digit is three times the ones digit.
• By checking the options, only 762 meets all these criteria: 7 + 6 + 2 = 15, and 6 is three times 2.

Ans: (a)

• The number 967 in Roman numerals is represented as CMLXVII.
• This is broken down as follows: 900 (CM) + 60 (LX) + 7 (VII).
• Each part corresponds to a specific value, and when combined, they give the total of 967.
• Understanding Roman numerals involves knowing the values of letters like C, M, L, X, and V.

Ans: (c)

• To find out how much milk 10 containers can hold, first convert 14 3/5 litres into an improper fraction. This equals 73/5 litres.
• Next, multiply this amount by 10: (73/5) * 10 = 730/5 litres.
• Now, divide 730 by 5 to get 146 litres.
• Thus, 10 containers can hold a total of 146 litres of milk.

Ans: (d)

• To find the 3rd multiple of 3, we calculate 3 x 3 = 9.
• For the 5th multiple of 5, we calculate 5 x 5 = 25.
• The sum of these two multiples is 9 + 25 = 34.
• Now, we check if 34 is divisible by 2. Since 34 is an even number, it is divisible by 2.

Ans: (c)

• First, calculate the sum: 825.23 + 425.68 = 1250.91.
• Next, to round to the nearest tenth, look at the hundredths place, which is 1.
• Since 1 is less than 5, we round down, resulting in 1250.9.
• Thus, the final answer is 1250.9.

Ans: (b)

• The red portion of the pole is 1.8 m long.
• The white portion is three times the length of the red portion, which means it is 1.8 m x 3 = 5.4 m long.
• To find the total length of the pole, add the lengths of the red and white portions: 1.8 m + 5.4 m = 7.2 m.
• Thus, the total length of the pole is 7.2 m.

Ans: (a)

• The number sixty million fifty-seven thousand four hundred three can be broken down into its components: 60 million, 57 thousand, and 403.
• When written in numerical form, 60 million is 60,000,000, 57 thousand is 57,000, and 403 remains 403.
• Combining these parts gives us 60,057,403.
• Thus, the correct representation is 60,057,403.

Ans: (c) 
Product = 20000 × 20 = 400000 

Ans: (c)
3, 13, 23, 30, 31, 32, 33, 34, 35, 36, 37,  38, 39, 43, 53, 63, 73, 83, 93.  
So “3” appears 20 times. 

Ans: (d)
1, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 21, 31,  41, 51, 61, 71, 81, 91, 100  
So “1” appears 21 times.

Ans: (b) 
Successor = 301999 + 1 = 302000

Ans: (c)

Ans: (b)

Ans: (c)
Forty six thousand eight hundred forty two  is written in numerals as 46842. 

Ans: (d)

Ans: (b) 
According to International System of  numeration, the commas are placed after every third place from the right.  
So, option (b) is correct.  

Ans: (d)
Place value of 4 at ten's = 4 × 10 = 40.  
Place value of 4 at ten thousand's.  
= 4 × 10000 = 40,000  
Difference of place values of 4 in the number = 40000 – 40 = 39960

Ans: (a)

• To find out how many notebooks can be bought, we need to divide the total amount of money, which is ₹200, by the cost of one notebook, which is ₹12.
• So, we calculate: 200 ÷ 12 = 16.66. Since we can only buy whole notebooks, we take the maximum whole number, which is 16.
• This means with ₹200, you can purchase a maximum of 16 notebooks.
• Thus, the correct answer is option (a).

Ans: (c)

• To find the number of boys, first calculate the number of girls. Since girls are 3/4 of the total students, we find the number of girls by multiplying 320 by 3/4.
• This gives us 240 girls (320 * 3/4 = 240).
• Next, subtract the number of girls from the total number of students to find the number of boys: 320 - 240 = 80.
• Thus, the number of boys in the school is 80.

Ans: (d)

• To find the length of the rectangular plot, we use the formula for the area of a rectangle: Area = Length × Breadth.
• Given that the area is 266 sq. m and the breadth is 14 m, we can rearrange the formula to find the length: Length = Area / Breadth.
• Substituting the values: Length = 266 / 14, which equals 19 m.
• Thus, the length of the plot is 19 m.

Ans: (a)

• To find the total earnings in 5 days, first calculate the daily earnings by multiplying the number of rasgullas sold (248) by the cost of one rasgulla (₹12).
• Daily earnings = 248 × 12 = ₹2,976.
• Now, multiply the daily earnings by 5 to find the total for 5 days: ₹2,976 × 5 = ₹14,880.
• Thus, the shop will earn a total of ₹14,880 in 5 days.

Ans: (b)

• Rehan's dance class began at 5:30 a.m..
• He spent 45 minutes in the class.
• To find the return time, add 45 minutes to 5:30 a.m..
• This results in 6:15 a.m., which is when he got back home.

Ans: (b)

• To find out which NGO collected more books, we compare the total numbers.
• NGO P collected 72,53,052 books, while NGO Q collected 45,56,759 books.
• Since 72,53,052 is greater than 45,56,759, NGO P collected more books.
• Thus, the correct answer is NGO P.

Ans: (d)

• The perimeter of a square is calculated by the formula: 4 × side.
• For a square park with a side of 50 m, the perimeter is 4 × 50 = 200 m.
• If Karan walked around the park 6 times, the total distance is 200 m × 6 = 1200 m.
• Thus, the total distance Karan walked that day is 1200 m.

Ans: (c)

• To find out how much weight Aarohi needs to lose, we first calculate the difference in their weights.
• Aarohi's weight is 67.50 kg and Shreya's weight is 54.85 kg.
• The difference is 67.50 kg - 54.85 kg = 12.65 kg.
• Thus, Aarohi should lose 12.65 kg to match Shreya's weight.

Ans: (a)

• First, calculate the total amount Puneet has: ₹760.65 + ₹432.85 = ₹1193.50.
• Next, subtract this total from the shirt's price: ₹2000 - ₹1193.50 = ₹806.50.
• Thus, Puneet still needs ₹806.50 to purchase the shirt.
• This amount is essential for him to complete the purchase.

Ans: (d)

• To find out how many bricks were used for each chamber, we need to divide the total number of bricks by the number of chambers.
• So, we calculate: 7695940 bricks ÷ 70 chambers = 109942 bricks per chamber.
• This means that each chamber received an equal share of 109942 bricks.
• Thus, the correct answer is (d) 109942.

Ans: (a)
In 10 lakhs, there are six zeroes, it is written  as 10,00,000.

Ans: (a)

Ans: (b)
The successor of 871929 is 871929 + 1 = 871930

Ans: (b)

Ans: (a)