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DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12 PDF Download

DIRECTIONS (Q.1-Q.18) : There are 18 multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE choice is correct.

Q1: A total charge Q is broken in two parts Q1 and Q2 and they are placed at a distance R from each other. The maximum force of repulsion between them will occur, when
(a)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(b)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(c)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(d)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12

Q2: Two small balls each having the charge + Q are suspended by insulating threads of length L from a hook. This arrangement is taken in space where there is no gravitational effect, then the angle between the two suspensions and the tension in each thread will be
(a)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(b)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(c)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(d)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12


Q3: Electric charges of 1mC , -1mC and 2mC are placed in air at the corners A,B and C respectively of an equilateral triangle ABC having length of each side 10 cm. The resultant force on the charge at C is
(a) 0.9 N
(b) 1.8N
(c) 2.7 N
(d) 3.6 N

Q4: An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius r. The coulomb forceDPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12between the two is DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(a)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(b)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12

(c)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(d)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12
Q5: Equal charges q are placed at the four corners A, B, C,D of a square of length a . The magnitude of the force on the charge at B will be
(a) DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(b) DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(c)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(d)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12
Q6: Electric lines of force about negative point charge are
(a) Circular, anticlockwise
(b) Circular, clockwise
(c) Radial, inward
(d) Radial, outward

Q7: The magnitude of electric field intensity E is such that, an electron placed in it would experience an electrical force equal to its weight is given by
(a) mge
(b) mg/e
(c) e/mg
(d)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12
Q8: Two point charges Q and –3Q are placed at some distance apart. If the electric field at the location of Q is E then at the locality of –3Q, it is
(a) –E
(b) E/3
(c) –3E
(d) –E/3

Q9: Charges q, 2q, 3q and 4q are placed at the corners A, B, C and D of a square as shown in the following figure. The direction of electric field at the centre of the square is parallel to side.
DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(a) AB
(b) CB
(c) BD
(d) AC

Q10: Three infinitely long non-conducting charge sheets are placed as shown in figure. The electric field at point P is
DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(a) DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(b)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(c)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(d)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12

Q11: The electric intensity due to an infinite cylinder of radius R and having charge q per unit length at a distance r(r > R) from its axis is
(a) Directly proprotional to r2
(b) Directly proprotional to r3
(c) Inversely proprotional to r
(d) Inversely proprotional to r2

Q12: A sphere of radius R has a uniform distribution of electric charge in its volume. At a distance x from its centre, for x < R, the eletric field is directly proportional to
(a) 1/x2
(b) 1/x
(c) x
(d) x2

Q13: A charged ball B hangs from a silk thread S, which makes an angle q with a large charged conducting sheet P, as shown in the figure. The surface charge density s of the sheet is proportional to
DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(a) sin q
(b) tan q
(c) cos q
(d) cot q

Q14: A charge q is placed at the centre of a cube. Then the flux passing through one face of cube will be
(a)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(b) DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(c)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(d)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12


DIRECTIONS (Q.15) : In the following question, more than one of the answers  given are correct. Select the correct answers and mark it according to the following codes:
Q15: A solid sphere S1 is connected to a charge reservoir through a heater H as shown in figure.
DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12
Flux through a closed spherical surface around S1 given by Φ = α t2 where u is a constant and t is time in seconds. If resistance of heater is R then select correct statements
(1) Power consumed by heater will be 4 α2ε02 Rt2.
(2) Electric flux through a closed spherical surface around S2 will be— αt2.
(3) Rate of change of electric flux through a closed spherical surface around S2 will be —2α t
(4) All of the above are correct
Codes :
(a) 1, 2 and 3 are correct
(b) 1 and 2 are correct
(c) 2 and 4 are correct
(d) 1 and 3 are correct


DIRECTIONS (Q.16-Q.18) : Read the passage given below and answer the questions that follows :
A sphere of radius R contains charge density r (r ) = A( R-r ), for 0 < r<R. The total electric charge inside the sphere is Q.

Q16: The value of A in terms of Q and R is
(a)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(b)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(c) DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(d) DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12


Q17: The electric field inside the sphere is
(a) DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12
(b)DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12
(c) DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12
(d) DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12


Q18: The electric field outside the sphere is
DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12(a) kQ/r
(b) kQ/r2
(c) kQ/r3
(d) kQ2/r2

DIRECTIONS (Q.19 -Q.20 ) : Each of these questi ons contains two statements: Statement-1 (Assertion) and Statement-2 (Reason). Each of these questions has four alternative choices, only one of which is the correct answer.
You have to select the correct choice.

Q19: Statement-1 : Electric lines of force cross each other.
Statement-2 : Electric field at a point superimpose to give one resultant electric field.
(a) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for  Statement-1.
(b) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.
(c) Statement -1 is False, Statement-2 is True.
(d) Statement -1 is True, Statement-2 is False.

Q20: Statement-1 : A point charge is brought in an electric field. The field at a nearby point will increase, whatever be the nature of the charge.
Statement-2 : The electric field is dependent on the nature of charge.
(a) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for  Statement-1.
(b) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.
(c) Statement -1 is False, Statement-2 is True.
(d) Statement -1 is True, Statement-2 is False.

The document DPP for NEET: Daily Practice Problems: Electrostatics- 1 | Physics Class 12 is a part of the NEET Course Physics Class 12.
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FAQs on DPP for NEET: Daily Practice Problems: Electrostatics- 1 - Physics Class 12

1. What is the principle of superposition in electrostatics?
Ans. The principle of superposition states that the total electric field created by multiple charges is the vector sum of the electric fields produced by each charge individually. This means that if you have several point charges, you can calculate the electric field at a point in space by adding up the electric fields due to each charge as if the other charges were not present.
2. How do you calculate the electric force between two point charges?
Ans. The electric force between two point charges can be calculated using Coulomb's Law, which states that the force \( F \) between two charges \( q_1 \) and \( q_2 \) separated by a distance \( r \) is given by the formula: \[ F = k \frac{|q_1 \cdot q_2|}{r^2} \] where \( k \) is Coulomb's constant, approximately \( 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \). The force is attractive if the charges are of opposite signs and repulsive if they are of the same sign.
3. What is the difference between electric field and electric potential?
Ans. The electric field is a vector quantity that represents the force experienced by a unit positive charge placed in the field. It is defined as the force per unit charge. Electric potential, on the other hand, is a scalar quantity that represents the potential energy per unit charge at a point in the field. While the electric field gives information about the direction and magnitude of forces, electric potential indicates how much work is needed to move a charge within the field.
4. What is the significance of equipotential surfaces in electrostatics?
Ans. Equipotential surfaces are surfaces where the electric potential is the same at every point. The significance of these surfaces is that no work is required to move a charge along an equipotential surface, as the potential difference between any two points on the surface is zero. This concept simplifies calculations in electrostatics since the electric field is always perpendicular to equipotential surfaces.
5. How does the concept of electric dipole relate to electrostatics?
Ans. An electric dipole consists of two equal and opposite charges separated by a small distance. In electrostatics, the dipole moment is a vector quantity defined as the product of the charge and the distance between the charges. The behavior of electric dipoles in an electric field, such as the torque experienced and the potential energy, is a key concept in electrostatics, helping to explain phenomena like molecular polarity and the behavior of materials in electric fields.
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