Perimeter of Various Shapes and Area of Square and Rectangle | Math Olympiad for Class 5 PDF Download

Q1. Aditya wants to put a fence around a rectangular garden that is 12 m long and 8 m wide. How much fencing does he need?
(a) 32 m
(b) 40 m
(c) 48 m
(d) 20 mAns: (b) 40 m

Perimeter of a rectangle = 2 × (length + breadth) 
= 2 × (12 m + 8 m) = 2 × 20 m = 40 m. 
Aditya needs 40 meters of fencing to go around the garden.

Q2. A square photo frame has a side of 15 cm. What is the total length of the frame’s border?
(a) 45 cm
(b) 60 cm
(c) 30 cm
(d) 75 cmAns: (b) 60 cm

Perimeter of a square = 4 × side = 4 × 15 cm = 60 cm. 
The border of the photo frame is 60 cm long.

Q3. Mrs. Sharma stitches a lace around a square tablecloth with each side measuring 50 cm. If the lace costs Rs. 2 per cm, how much will she spend?
(a) Rs. 200
(b) Rs. 100
(c) Rs. 400
(d) Rs. 150
Ans: (a) Rs. 200

Perimeter of the square tablecloth = 4 × side = 4 × 50 cm = 200 cm.
 Cost = 200 cm × Rs. 2/cm = Rs. 200. 
Mrs. Sharma will spend Rs. 200.

Q4. A rectangular playground has a perimeter of 70 m. If its length is 20 m, what is its breadth?
(a) 15 m
(b) 25 m
(c) 10 m
(d) 35 m
Ans: (a) 15 m

Perimeter of a rectangle = 2 × (length + breadth). 
So, 70 m = 2 × (20 m + breadth). 
Solving: 70 ÷ 2 = 20 + breadth
⇒ 35 = 20 + breadth
⇒ breadth = 35 - 20 = 15 m. 
The breadth is 15 m.

Q5. A square park has a perimeter of 36 m. What is the length of one side of the park?
(a) 12 m
(b) 10 m
(c) 9 m
(d) 6 m
Ans: (c) 9 m

Perimeter of a square = 4 × side.
 So, 36 m = 4 × side
side = 36 ÷ 4 = 9 m. 
The length of one side is 9 m.

Q6. A rectangular room has a length of 6 m and a breadth of 4 m. How much carpet is needed to cover the floor?
(a) 24 m²
(b) 20 m²
(c) 10 m²
(d) 28 m²
Ans: (a) 24 m²

Area of a rectangle = length × breadth 
= 6 m × 4 m = 24 m². 
The carpet needed to cover the floor is 24 square meters.

Q7. A square mat has a side of 8 cm. What is the area of the mat?
(a) 16 cm²
(b) 64 cm²
(c) 32 cm²
(d) 48 cm²Ans: (b) 64 cm²

Area of a square = side × side 
= 8 cm × 8 cm = 64 cm². 
The area of the mat is 64 square centimeters.

Q8. A rectangular picture has an area of 48 cm² and a breadth of 6 cm. What is its length?
(a) 10 cm
(b) 8 cm
(c) 12 cm
(d) 6 cm
Ans: (b) 8 cm

Area of a rectangle = length × breadth. 
So, 48 cm² = length × 6 cm
length = 48 ÷ 6 = 8 cm. 
The length of the picture is 8 cm.

Q9. Ravi jogs around an equilateral triangle-shaped park with each side measuring 25 m. How far does he jog in one round?
(a) 50 m
(b) 75 m
(c) 100 m
(d) 60 m
Ans: (b) 75 m

Perimeter of an equilateral triangle = 3 × side 
= 3 × 25 m 
= 75 m. 
Ravi jogs 75 meters in one round.

Q10. A square tile has an area of 25 cm². What is the perimeter of the tile?
(a) 20 cm
(b) 15 cm
(c) 10 cm
(d) 25 cm
Ans: (a) 20 cm

Area of a square = side × side. 
So, 25 cm² = side²
 side = √25 = 5 cm. 
Perimeter = 4 × side 
= 4 × 5 cm = 20 cm.
 The perimeter of the tile is 20 cm.