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Revision Notes: Distance Formula | Mathematics Class 9 ICSE PDF Download

  • The distance between P(x1, y1) and Q(x2, y2) is Revision Notes: Distance Formula | Mathematics Class 9 ICSE
    This is known as the distance formula. 
  • The distance of a point P(x, y) from origin is Revision Notes: Distance Formula | Mathematics Class 9 ICSE
  • The points A, B and C are collinear if AB + BC = AC.
  • Three points A, B and C are the vertices of an equilateral triangle if AB = BC = CA. 
  • The points A, B and C are the vertices of an isosceles triangle if AB = BC or BC = CA or CA = AB. 
  • Three points A, B and C are the vertices of a right triangle if sum of squares of any two sides is equal to the square of the third side. 
  •  For the given four points A, B, C and D:
    (i) AB = BC = CD = DA; AC = BD ⇒ ABCD is a square. 
    (ii) AB = BC = CD = DA; AC ≠ BD ⇒ ABCD is a rhombus. 
    (iii) AB = CD, BC = DA; AC = BD ⇒ ABCD is a rectangle. 
    (iv) AB = CD, BC = DA; AC ≠ BD ⇒ ABCD is a parallelogram. 
  • Circumcentre is the point of intersection of the perpendicular bisectors of the sides of the triangle. 
    Revision Notes: Distance Formula | Mathematics Class 9 ICSEO is the circumcentre of the triangle ABC. 
The document Revision Notes: Distance Formula | Mathematics Class 9 ICSE is a part of the Class 9 Course Mathematics Class 9 ICSE.
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FAQs on Revision Notes: Distance Formula - Mathematics Class 9 ICSE

1. What is the distance formula in coordinate geometry?
Ans. The distance formula is used to determine the distance between two points in a coordinate plane. If you have two points, A(x₁, y₁) and B(x₂, y₂), the distance (d) between them can be calculated using the formula: \[ d = \sqrt{(x₂ - x₁)² + (y₂ - y₁)²} \]
2. How can the distance formula be derived using the Pythagorean theorem?
Ans. The distance formula can be derived from the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (d) is equal to the sum of the squares of the other two sides. When finding the distance between two points (x₁, y₁) and (x₂, y₂), the horizontal distance is (x₂ - x₁) and the vertical distance is (y₂ - y₁). Therefore, applying the theorem gives: \[ d² = (x₂ - x₁)² + (y₂ - y₁)² \] Taking the square root of both sides leads to the distance formula.
3. Can the distance formula be used in three-dimensional space?
Ans. Yes, the distance formula can be extended to three-dimensional space. For two points A(x₁, y₁, z₁) and B(x₂, y₂, z₂), the distance (d) is calculated using the formula: \[ d = \sqrt{(x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²} \]
4. How do you find the distance between points with negative coordinates using the distance formula?
Ans. The distance formula works the same way regardless of whether the coordinates are positive or negative. Simply plug the coordinates into the formula. For example, for points A(-3, -4) and B(1, 2), the distance is calculated as follows: \[ d = \sqrt{(1 - (-3))² + (2 - (-4))²} = \sqrt{(1 + 3)² + (2 + 4)²} = \sqrt{4² + 6²} = \sqrt{16 + 36} = \sqrt{52} = 2\sqrt{13} \]
5. What are some practical applications of the distance formula in real life?
Ans. The distance formula has various practical applications, such as in navigation systems for calculating distances between locations, in computer graphics for measuring distances between points in a digital image, and in physics for determining the displacement between two objects in motion. It is also used in fields such as architecture and engineering to calculate distances when designing structures.
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