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Class 7 Maths Chapter 4 Question Answers - Expressions using Letters and Numbers

Class 7 Maths Chapter 4 Question Answers - Expressions using Letters and Numbers

Q1: If Priya is 5 years older than Rahul, and Priya’s age is 30 years, what is Rahul’s age?

Ans: Rahul’s age = 30 – 5 = 25 years.

Q2: Simplify the expression 3x + 5x - 2x.

Ans:
Combine like terms:
= (3x + 5x - 2x) 
= (8x - 2x)
= 6x

Q3: A shop sells pencils for "c" each and erasers for "d" each. If a customer buys 4 pencils and 3 erasers, write an expression for the total cost.

Ans:
Total cost = Cost of pencils + Cost of erasers
Cost of pencils = 4 x c 
Cost of erasers =  3 x d
Total cost = 4 x c + 3 x d = 4c + 3d

Q4: If the side length of a square is "q", write the simplified algebraic expression for its perimeter.

Ans:
Perimeter = 4 x q = 4q.

Q5: If a machine takes 15 seconds to start and 5 seconds per kg to process flour, how long does it take to process 3 kg?

Ans:

Time taken by machiene= 15 + 5 × 3 
= 15 + 15 
= 30 seconds.

Q6: A rectangle has length "l" and breadth "b". Write the simplified expression for its perimeter.

Ans:
Perimeter = 2 x (l + b) 
= 2l + 2b.

Q7: Simplify Tp - p + 5q - 2q.

Ans:
Combine like terms:
(Tp - p) + (5q - 2q) 
= (Tp - p)+ 3q 

Q8: If a number machine follows the rule "3a - b", find the output when a = 5 and b = 2.

Ans: In the expression 3a - b, Put a = 5 and b = 2
Output = 3 x 5 - 2 
= 15 - 2 
= 13

Q9: A snail climbs "u" cm during the day and slips back "d" cm at night. Write an expression for its net progress after 5 days and 5 nights.

Ans:
Net progress = 5 x (u - d).

Q10: A train stops for 2 minutes at each of 3 stations. If the travel time between stations is "t" minutes, write an expression for the total journey time.

Class 7 Maths Chapter 4 Question Answers - Expressions using Letters and Numbers

Ans:
Total time = Travel time + Stop time = 3 x t + 6 minutes.

Q11: Simplify 4(x + y) - y.

Ans:
Distribute and combine like terms:
4x + 4y - y = 4x + 3y.

Q12: If 10y - 3 and 10(y - 3) are two expressions, compare their values when y = 4.

Ans:
10y - 3 = 10 x 4 - 3 = 37.
10(y - 3) = 10 x (4 - 3) = 10.
They are not equal.

Q13: Subtract 9a - 6b + 14 from 6a + 9b - 18.

Ans:
(6a + 9b - 18) - (9a - 6b + 14) = -3a + 15b - 32.

The document Class 7 Maths Chapter 4 Question Answers - Expressions using Letters and Numbers is a part of the Class 7 Course Mathematics (Ganita Prakash) Class 7 - New NCERT.
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FAQs on Class 7 Maths Chapter 4 Question Answers - Expressions using Letters and Numbers

1. What are expressions using letters and numbers in mathematics?
Ans. Expressions using letters and numbers combine numerical values and variables (letters) to represent mathematical relationships. For example, in the expression 3x + 5, 'x' is a variable that can take different values, while 3 and 5 are constants.
2. How do you evaluate an expression with variables?
Ans. To evaluate an expression with variables, you substitute the variable with a specific numerical value. For instance, if you have the expression 2x + 3 and x = 4, you would replace x with 4 to get 2(4) + 3 = 8 + 3 = 11.
3. What is the difference between an expression and an equation?
Ans. An expression is a combination of numbers, variables, and operations without an equality sign, while an equation states that two expressions are equal and includes an equality sign. For example, 2x + 3 is an expression, but 2x + 3 = 7 is an equation.
4. Can you give examples of algebraic expressions?
Ans. Yes! Examples of algebraic expressions include: 1. 5y - 2 2. 3a + 4b - 6 3. 7 - 2x + x² These expressions involve variables (like x, y, a, b) and constants.
5. How can we simplify algebraic expressions?
Ans. To simplify algebraic expressions, combine like terms (terms that have the same variable raised to the same power) and perform basic arithmetic operations. For example, the expression 3x + 4x can be simplified to 7x by adding the coefficients of like terms.
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