Compound Interest (Using Formula) - Class 9 Mathematics ICSEIntroduction
Imagine you have some money saved up, and instead of keeping it under your mattress, you decide to invest it in a bank that promises to grow your money over time. This growth doesn't just add a fixed amount each year but builds on itself, like a snowball rolling down a hill, getting bigger and bigger. This is the magic of compound interest! In this chapter, we'll explore how to calculate compound interest using simple formulas, making it easier to find out how much your money can grow over time or solve related problems. Whether it's figuring out the future value of an investment or determining how long it takes for money to double, these notes will guide you through the concepts step-by-step, making them clear and exciting to learn!

- Compound interest is the interest calculated on the initial principal and the accumulated interest from previous periods.
- It differs from simple interest, where interest is calculated only on the initial amount.
- The principal grows each period as interest is added, making future interest calculations larger.
- Calculating compound interest manually for many periods can be time-consuming.
- Formulas simplify the process, allowing quick and accurate calculations for amount and interest.
Example: If ₹7,500 is invested for 2 years at 6% per annum compounded annually, the amount can be tedious to calculate manually. Using a formula simplifies this process.

- Formulas make calculating compound interest faster and easier, especially for multiple periods.
- The main formula is used when interest is compounded annually.
Steps to use the formula:
- Identify the principal (P), rate of interest (r), and time period (n).
- Apply the formula to find the amount (A).
- Subtract the principal from the amount to find the compound interest (C.I.).
Example: Calculate the amount on ₹7,500 in 2 years at 6% compounded annually.
- Given: P = ₹7,500, n = 2 years, r = 6%.
- Formula: A = P(1 + r/100)n.
- Substitute: A = ₹7,500 × (1 + 6/100)2 = ₹7,500 × (106/100)2.
- Calculate: A = ₹7,500 × (1.06)2 = ₹7,500 × 1.1236 = ₹8,427.
- Compound Interest = A - P = ₹8,427 - ₹7,500 = ₹927.
When the Rates for Successive Years are Different
- If interest rates change each year, the formula adjusts to multiply factors for each year's rate.
- Formula:

- where r1, r2, r3 are rates for successive years.
Steps:
- Identify the principal and the rates for each year.
- Multiply the principal by each year's factor (1 + r/100).
- Calculate the final amount and subtract the principal for compound interest.
Example: Calculate the amount on ₹12,000 in 3 years with rates 8%, 10%, and 15% for successive years.
- Given: P = ₹12,000, r1 = 8%, r2 = 10%, r3 = 15%.
- Formula: A = P(1 + r1/100)(1 + r2/100)(1 + r3/100).
- Substitute: A = ₹12,000 × (1 + 8/100)(1 + 10/100)(1 + 15/100).
- Calculate: A = ₹12,000 × (108/100) × (110/100) × (115/100) = ₹12,000 × 1.08 × 1.1 × 1.15 = ₹16,394.40.
- Compound Interest = ₹16,394.40 - ₹12,000 = ₹4,394.40.
Inverse Problems
- Inverse problems involve finding the principal, rate, or time given the amount or interest.
- Use the compound interest formula and rearrange it to solve for the unknown variable.
To Find the Principal
Use the formula A = P(1 + r/100)n and solve for P.
Steps:
- Rearrange: P = A / (1 + r/100)n.
- Substitute known values of A, r, and n.
- Simplify to find P.
Example: What sum amounts to ₹3,630 in 2 years at 10% per annum compound interest?
- Given: A = ₹3,630, r = 10%, n = 2 years.
- Formula: P = A / (1 + r/100)n.
- Substitute: P = ₹3,630 / (1 + 10/100)2 = ₹3,630 / (11/10)2.
- Calculate: P = ₹3,630 × (10/11) × (10/11) = ₹3,630 × 100/121 = ₹3,000.
To Find the Rate Percent
Use A = P(1 + r/100)n and solve for r.
Steps:
- Rearrange: (1 + r/100)n = A/P.
- Take the n-th root: 1 + r/100 = (A/P)1/n.
- Solve for r: r = [(A/P)1/n - 1] × 100.
Example: At what rate does ₹2,000 amount to ₹2,315.25 in 3 years?
- Given: P = ₹2,000, A = ₹2,315.25, n = 3 years.
- Formula: A = P(1 + r/100)n.
- Rearrange: (1 + r/100)3 = 2,315.25 / 2,000 = 1.157625.
- Take cube root: 1 + r/100 = (1.157625)1/3 = 21/20.
- Solve: r/100 = 21/20 - 1 = 1/20, so r = 5%.
To Find the Number of Years (i.e., Time)
Use A = P(1 + r/100)n and solve for n.
Steps:
- Rearrange: (A/P) = (1 + r/100)n.
- Compare powers to find n, often by trial or simplification.
Example: In how many years will ₹2,000 amount to ₹2,662 at 10% compound interest?
- Given: P = ₹2,000, A = ₹2,662, r = 10%.
- Formula: A = P(1 + r/100)n.
- Rearrange: 2,662/2,000 = (1 + 10/100)n = (11/10)n.
- Simplify: 1.331 = (11/10)n.
- Since (11/10)3 = 1.331, n = 3 years.
When the Interest is Compounded Half-Yearly (Two Times in a Year)
- When interest is compounded half-yearly, the rate is halved, and the number of periods is doubled.
- Formula: A = P(1 + r/(2 × 100))n × 2.
Steps:
- Divide the annual rate by 2.
- Multiply the number of years by 2 for the number of periods.
- Calculate the amount and subtract principal for compound interest.
Example: Calculate the compound interest on ₹4,000 in 1.5 years at 10% per annum compounded half-yearly.
- Given: P = ₹4,000, r = 10%, n = 1.5 years.
- Formula: A = P(1 + r/(2 × 100))n × 2.
- Substitute: A = ₹4,000 × (1 + 10/(2 × 100))1.5 × 2 = ₹4,000 × (1 + 0.05)3.
- Calculate: A = ₹4,000 × (1.05)3 = ₹4,630.50.
- Compound Interest = ₹4,630.50 - ₹4,000 = ₹630.50.
When the Time is Not an Exact Number of Years and the Interest is Compounded Yearly
- For non-integer years (e.g., 2.5 years), calculate for whole years, then treat the remaining fraction as a half-year period.
- Formula for 2.5 years: A = P(1 + r/100)2(1 + r/(2 × 100))1.
Steps:
- Calculate amount for whole years using A = P(1 + r/100)n.
- Use the result as principal for the remaining half-year with half-yearly formula.
- Combine to find the total amount.
Example: Find the amount when ₹10,000 is invested for 2.5 years at 10% interest compounded yearly.
- Given: P = ₹10,000, r = 10%, n = 2.5 years.
- Step 1: For 2 years, A = ₹10,000 × (1 + 10/100)2 = ₹10,000 × (1.1)2 = ₹12,100.
- Step 2: For remaining 0.5 years, use P = ₹12,100, A = ₹12,100 × (1 + 10/(2 × 100))1 = ₹12,100 × 1.05 = ₹12,705.
- Total Amount = ₹12,705.
- The compound interest formula can be applied to growth and depreciation scenarios.
- It is used for problems involving population growth, industrial growth, or asset depreciation.
Growth
The formula A = P(1 + r/100)n is used for growth in industries, population, or inflation.
Steps:
- Identify initial value (P), growth rate (r), and time (n).
- Apply the formula to find the final value (A).
Example: If 1,600 industries grow by 20% annually, find the number after 2 years.
- Given: P = 1,600, r = 20%, n = 2 years.
- Formula: A = P(1 + r/100)n.
- Substitute: A = 1,600 × (1 + 20/100)2 = 1,600 × (1.2)2.
- Calculate: A = 1,600 × 1.44 = 2,304 industries.
Depreciation
- Depreciation reduces an asset's value annually at a fixed rate.
- Formula: Value after n years = P(1 - r/100)n.
Steps:
- Identify initial value (P), depreciation rate (r), and time (n).
- Apply the formula to find the final value.
Example: A machine worth ₹2,50,000 depreciates at 20% per year. Its scrap value is ₹1,28,000. Find the years used.
- Given: Initial value = ₹2,50,000, final value = ₹1,28,000, r = 20%.
- Formula: A = P(1 - r/100)n.
- Substitute: 1,28,000 = 2,50,000 × (1 - 20/100)n = 2,50,000 × (0.8)n.
- Simplify: (0.8)n = 1,28,000 / 2,50,000 = 0.512.
- Since (0.8)3 = 0.512, n = 3 years.
Population Problems
Use A = P(1 + r/100)n for population growth, where P is the initial population.
Steps:
- Identify initial population (P), growth rate (r), and time (n).
- Calculate future or past population using the formula.
Example: A town's population is 2,16,000, growing at 20% per year. Find its population after 2 years.
- Given: P = 2,16,000, r = 20%, n = 2 years.
- Formula: A = P(1 + r/100)n.
- Substitute: A = 2,16,000 × (1 + 20/100)2 = 2,16,000 × (1.2)2.
- Calculate: A = 2,16,000 × 1.44 = 3,11,040.