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Practice Question - 71 (Maxima Minima) | 100 DILR Questions for CAT Preparation PDF Download

The local office of the APP-CAB company evaluates the performance of five cab drivers, Arun, Barun, Chandan, Damodaran, and Eman for their monthly payment based on ratings in five different parameters (P1 to P5) as given below:

P1: timely arrival
P2: behaviour
P3: comfortable ride
P4: driver's familiarity with the route
P5: value for money

Based on feedback from the customers, the office assigns a rating from 1 to 5 in each of these parameters. Each rating is an integer from a low value of 1 to a high value of 5. The final rating of a driver is the average of his ratings in these five parameters. The monthly payment of the drivers has two parts - a fixed payment and final rating-based bonus. If a driver gets a rating of 1 in any of the parameters, he is not eligible to get bonus. To be eligible for bonus a driver also needs to get a rating of five in at least one of the parameters. The partial information related to the ratings of the drivers in different parameters and the monthly payment structure (in rupees) is given in the table below:
Practice Question - 71 (Maxima Minima) | 100 DILR Questions for CAT PreparationThe following additional facts are known.

  1. Arun and Barun have got a rating of 5 in exactly one of the parameters. Chandan has got a rating of 5 in exactly two parameters.
  2. None of drivers has got the same rating in three parameters.

Q1: If Damodaran does not get a bonus, what is the maximum possible value of his final rating?
(a) 3.4
(b) 3.2
(c) 3.6
(d) 3.8

Practice Question - 71 (Maxima Minima) | 100 DILR Questions for CAT PreparationView Answer  Practice Question - 71 (Maxima Minima) | 100 DILR Questions for CAT Preparation

Ans: (c)
Based on the given conditions, Damodaran misses out on the bonus if he gets a rating of 1 in any of the five parameters. He additionally needs to obtain a rating of 5 in at least one of the parameters. Thus, the maximum value of the range of ratings that he can acquire would be 1 + 3 (given) + 5 + 5 + 5. However, based on condition 2, he can have similar ratings in only two of the parameters. Thus, the maximum value of the final rating would be (1 + 3 + 5 + 5 + 4) / 5 = 18 / 5 = 3.6. Hence, Option C is the correct answer. 

Q2: If Eman gets a bonus, what is the minimum possible value of his final rating?
(a) 3.2
(b) 2.8
(c) 3.4
(d) 3.0

Practice Question - 71 (Maxima Minima) | 100 DILR Questions for CAT PreparationView Answer  Practice Question - 71 (Maxima Minima) | 100 DILR Questions for CAT Preparation

Ans: (d)
Since Eman got a bonus, he must have obtained a rating of 5 in at least one of the parameters. To minimize his final rating we need to consider the following range of values: 5 (mandatory) + 2(given) + 2 + 3 + 3 = 15. The least value of his final rating is, therefore, 15 / 5 = 3. Hence, Option D is the correct answer. 

Q3:  If all five drivers get bonus, what is the minimum possible value of the monthly payment (in rupees) that a driver gets?
(a) 1750
(b) 1600
(c) 1740
(d) 1700

Practice Question - 71 (Maxima Minima) | 100 DILR Questions for CAT PreparationView Answer  Practice Question - 71 (Maxima Minima) | 100 DILR Questions for CAT Preparation

Ans: (d)
Our objective here is to minimize the final ratings in order to find the minimum value of the monthly payment. We cannot have a rating of 1 in any of the parameters since all the drives got the bonus and we need to have at least one parameter with a rating of 5. With this understanding, we obtain the following:
Arun:
Final rating = (5 + 4 + 2 + 2 + 3) / 5 = 16 / 5 = 3.2; Fixed payment = Rs.1000
Variable payment = 3.2 * Rs. 250 = Rs.800 ; Total = Rs. (1000 + 800) = Rs. 1800 
Barun:
Final rating = (5 + 3 + 2 + 2 + 3) / 5 = 15 / 5 = 3; Fixed payment = Rs.1200
Variable payment = 3 * Rs. 200 = Rs.600 ; Total = Rs.(1200 + 600) = Rs. 1800
Chandan: {rating of 5 in exactly two parameters based on condition 1}
Final rating = (5 + 5 + 2 + 2 + 3)/5 = 17/5 = 3.4; Fixed payment = Rs.1400
Variable payment = 3.4 * Rs. 100 = Rs.340 ; Total = Rs.(1400 + 340) = Rs. 1740
Damodaran:
Final rating = (5 + 3 + 2 + 2 + 3) / 5 = 15 / 5 = 3; Fixed payment = Rs.1300
Variable payment = 3 * Rs. 150 = Rs.450 ; Total = Rs.(1300 + 450) = Rs. 1750
Eman:
Final rating = (5 + 3 + 2 + 2 + 3 ) / 5 = 15 / 5 = 3; Fixed payment = Rs.1100
Variable payment = 3 * Rs. 200 = Rs.600 ; Total = Rs. (1100 + 600) = Rs. 1700

Hence, we observe that the minimum value of the monthly payment is Rs. 1700. Option D is the correct answer.

Q4: If all five drivers get bonus, what is the maximum possible value of the monthly payment (in rupees) that a driver gets?
(a) 1960
(b) 2050
(c) 1950
(d) 1900

Practice Question - 71 (Maxima Minima) | 100 DILR Questions for CAT PreparationView Answer  Practice Question - 71 (Maxima Minima) | 100 DILR Questions for CAT Preparation

Ans: (a)
Our objective here is to maximize the final ratings in order to find the maximum possible value of the monthly payment. We cannot have a rating of 1 in any of the parameters since all the drives got the bonus and we need to have at least one parameter with a rating of 5. With this understanding, we obtain the following:

Arun: {can have only one rating of 5 based on condition 1}

Final rating = (5 + 4 + 4 + 3 + 3) / 5 = 19 / 5 = 3.8; Fixed payment = Rs.1000

Variable payment = 3.8 * Rs. 250 = Rs.950 ; Total = Rs.(1000 + 950) = Rs. 1950

Barun: {can have only one rating of 5 based on condition 1}

Final rating = (5 + 4 + 4 + 3 + 3) /5 = 19 / 5 = 3.8; Fixed payment = Rs.1200

Variable payment = 3.8 * Rs. 200 = Rs.760 ; Total = Rs.(1200 + 760) = Rs. 1960

Chandan:

Final rating = (5 + 5 + 2 + 4 + 4)/ 5 = 20 / 5 = 4; Fixed payment = Rs.1400

Variable payment = 4 * Rs. 100 = Rs. 400 ; Total = Rs. (1400 + 400) = Rs. 1800

Damodaran:

Final rating = (5 + 5 + 4 + 4 + 3) / 5 = 21 / 5 = 4.2; Fixed payment = Rs.1300

Variable payment = 4.2 * Rs. 150 = Rs.630 ; Total = Rs.(1300+630) = Rs. 1930

Eman:

Final rating = (5 + 5 + 2 + 4 + 4) / 5 = 20 /5 = 4; Fixed payment = Rs.1100

Variable payment = 4 * Rs. 200 = Rs.800 ; Total = Rs.(1100 + 800) = Rs. 1900

Hence, we observe that the maximum possible value of the monthly payment is Rs. 1960. Option (a) is the correct answer.

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FAQs on Practice Question - 71 (Maxima Minima) - 100 DILR Questions for CAT Preparation

1. What are maxima and minima in the context of calculus?
Ans. Maxima and minima refer to the highest and lowest points, respectively, on a curve described by a function. A maximum point is where the function value is greater than the values at surrounding points, while a minimum point is where the function value is less than those around it. These points are crucial for optimization problems and can be found using techniques from differential calculus.
2. How can one find the maxima and minima of a function?
Ans. To find maxima and minima of a function, one typically follows these steps: 1. Take the derivative of the function and set it equal to zero to find critical points. 2. Determine whether each critical point is a maximum, minimum, or neither by using the second derivative test or the first derivative test. 3. Analyze the endpoints of the interval if the function is defined on a closed interval, as these can also be potential maxima or minima.
3. What is the significance of the first and second derivative tests in finding maxima and minima?
Ans. The first derivative test helps identify whether a critical point is a maximum or minimum by examining the sign of the derivative before and after the critical point. If the derivative changes from positive to negative, it indicates a maximum; if it changes from negative to positive, it indicates a minimum. The second derivative test provides additional confirmation: if the second derivative at a critical point is positive, it indicates a local minimum; if negative, a local maximum.
4. Can maxima and minima occur at endpoints of an interval?
Ans. Yes, maxima and minima can occur at the endpoints of an interval, especially in closed intervals. When analyzing a function defined on a closed interval, it is important to evaluate the function at the endpoints as well as at any critical points found within the interval to ensure all potential maxima and minima are considered.
5. How are maxima and minima used in real-world applications?
Ans. Maxima and minima play a critical role in various real-world applications, such as in economics for profit maximization or cost minimization, in engineering for optimizing design parameters, and in physics for determining stable equilibrium points. Understanding these concepts allows for better decision-making in resource allocation, design optimization, and efficiency improvements across different fields.
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