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Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation PDF Download

Funky Pizzeria was required to supply pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which were to be delivered to Party 3 and the rest equally divided between Party 1 and Party 2.

Pizzas could be of Thin Crust (T) or Deep Dish (D) variety and come in either Normal Cheese (NC) or Extra Cheese (EC) versions. Hence, there are four types of pizzas: T-NC, T-EC, D-NC and D-EC. Partial information about proportions of T and NC pizzas ordered by the three parties is given below:

Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Q1: How many Thin Crust pizzas were to be delivered to Party 3?
(a) 398
(b) 162
(c) 96
(d) 364

Practice Question - 65 (Tables) | 100 DILR Questions for CAT PreparationView Answer  Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Ans: (b)
We are given that Party 3 received 70% of total pizzas,therefore, number of pizzas received by Party Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Remaining 240 pizzas are equally divided among party 1 and party 2 hence we can say that each of Party 1 and Party 2 received 120 pizzas.  

We know that all of the pizza can be classified into a total of 4 types. Hence, on drawing a table which can accommodate all of the cases: 

Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Total number of Thin Crust pizzas = 0.375*800 = 300. Therefore, total number of Deep Dish pizzas = 800 - 300 = 500.
Out of 120 pizzas that Party 1 received, 60% were of Thin Crust type hence, total number of Thin Crust pizza received by Party 1 = 0.6*120 = 72. Consequently Party 1, must have received 42 Deep Dish type pizzas. 
Out of 120 pizzas that Party 2 received, 55% were of Thin Crust type hence, total number of Thin Crust pizza received by Party 2 = 0.55*120 = 66. Consequently Party 1, must have received 54 Deep Dish type pizzas. 
Therefore, total number of Thin Crust pizzas ordered by Party 3 = Total Thin Crust pizzas ordered - Thin Crust pizzas ordered by Party 1 - Thin Crust pizzas ordered by Party 2
300 - 72 - 66 = 162
Hence number of Deep Dish type of pizzas order by Party 3 = 560 - 162 = 398  

Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

No, of Thin Crust Pizzas delivered to party 3 is 162. Hence, option (b) is the correct answer.

Q2: How many Normal Cheese pizzas were required to be delivered to Party 1?
(a) 104
(b) 84
(c) 16
(d) 196

Practice Question - 65 (Tables) | 100 DILR Questions for CAT PreparationView Answer  Practice Question - 65 (Tables) | 100 DILR Questions for CAT PreparationAns: (c) 
We are given that Party 3 received 70% of total pizzas,therefore, number of pizzas received by Party Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Remaining 240 pizzas are equally divided among party 1 and party 2 hence we can say that each of Party 1 and Party 2 received 120 pizzas.  
We know that all of the pizza can be classified into a total of 4 types. Hence, on drawing a table which can accommodate all of the cases: 

Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Total number of Thin Crust pizzas = 0.375*800 = 300. Therefore, total number of Deep Dish pizzas = 800 - 300 = 500.
Out of 120 pizzas that Party 1 received, 60% were of Thin Crust type hence, total number of Thin Crust pizza received by Party 1 = 0.6*120 = 72. Consequently Party 1, must have received 42 Deep Dish type pizzas. 
Out of 120 pizzas that Party 2 received, 55% were of Thin Crust type hence, total number of Thin Crust pizza received by Party 2 = 0.55*120 = 66. Consequently Party 1, must have received 54 Deep Dish type pizzas. 
Therefore, total number of Thin Crust pizzas ordered by Party 3 = Total Thin Crust pizzas ordered - Thin Crust pizzas ordered by Party 1 - Thin Crust pizzas ordered by Party 2
300 - 72 - 66 = 162
Hence number of Deep Dish type of pizzas order by Party 3 = 560 - 162 = 398  

Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Total number of Normal Cheese pizzas require to be delivered = 0.52*800 = 416
Number of  Normal Cheese pizzas require to be delivered to Party 2 = 0.3*120 = 36
Number of  Normal Cheese pizzas require to be delivered to Party 3 = 0.65*560 = 364
Therefore, total number of Normal Cheese pizzas  require to be delivered to Party 1 = Total Normal Cheese pizzas to be delivered - Normal Cheese pizzas require to be delivered to Party 2 - Normal Cheese pizzas require to be delivered to Party 3
416 - 36 - 364 = 16 
Hence, option (c) is the correct answer. 

Q3: For Party 2, if 50% of the Normal Cheese pizzas were of Thin Crust variety, what was the difference between the numbers of T-EC and D-EC pizzas to be delivered to Party 2?
(a) 18
(b) 12
(c) 30
(d) 24

Practice Question - 65 (Tables) | 100 DILR Questions for CAT PreparationView Answer  Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Ans: (b)
We are given that Party 3 received 70% of total pizzas,therefore, number of pizzas received by Party Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Remaining 240 pizzas are equally divided among party 1 and party 2 hence we can say that each of Party 1 and Party 2 received 120 pizzas.  
We know that all of the pizza can be classified into a total of 4 types. Hence, on drawing a table which can accommodate all of the cases: 

Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Total number of Thin Crust pizzas = 0.375*800 = 300. Therefore, total number of Deep Dish pizzas = 800 - 300 = 500.
Out of 120 pizzas that Party 1 received, 60% were of Thin Crust type hence, total number of Thin Crust pizza received by Party 1 = 0.6*120 = 72. Consequently Party 1, must have received 42 Deep Dish type pizzas. 
Out of 120 pizzas that Party 2 received, 55% were of Thin Crust type hence, total number of Thin Crust pizza received by Party 2 = 0.55*120 = 66. Consequently Party 1, must have received 54 Deep Dish type pizzas. 
Therefore, total number of Thin Crust pizzas ordered by Party 3 = Total Thin Crust pizzas ordered - Thin Crust pizzas ordered by Party 1 - Thin Crust pizzas ordered by Party 2
300 - 72 - 66 = 162
Hence number of Deep Dish type of pizzas order by Party 3 = 560 - 162 = 398  

Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Number of  Normal Cheese pizzas require to be delivered to Party 2 = 0.3*120 = 36
It is given that 50% of these Normal Cheese pizzas were of Thin Crust variety, then We can say that remaining 50% were of Deep Dish variety. We can find out each of 4 types of pizzas require to be delivered to Party 2.

Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Hence, the difference between the numbers of T-EC and D-EC pizzas to be delivered to Party 2 = 48 - 36 = 12 
Therefore, option (b) is the correct answer. 

Q4: Suppose that a T-NC pizza cost as much as a D-NC pizza, but 3/5th of the price of a D-EC pizza.A D-EC pizza costs Rs. 50 more than a T-EC pizza, and the latter costs Rs. 500.
If 25% of the Normal Cheese pizzas delivered to Party 1 were of Deep Dish variety, what was the total bill for Party 1?
(a) Rs. 59480
(b) Rs. 59840
(c) Rs. 42520
(d) Rs. 45240

Practice Question - 65 (Tables) | 100 DILR Questions for CAT PreparationView Answer  Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Ans: (a)
We are given that Party 3 received 70% of total pizzas,therefore, number of pizzas received by Party Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Remaining 240 pizzas are equally divided among party 1 and party 2 hence we can say that each of Party 1 and Party 2 received 120 pizzas.  
We know that all of the pizza can be classified into a total of 4 types. Hence, on drawing a table which can accommodate all of the cases: 

Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Total number of Thin Crust pizzas = 0.375*800 = 300. Therefore, total number of Deep Dish pizzas = 800 - 300 = 500.
Out of 120 pizzas that Party 1 received, 60% were of Thin Crust type hence, total number of Thin Crust pizza received by Party 1 = 0.6*120 = 72. Consequently Party 1, must have received 42 Deep Dish type pizzas. 
Out of 120 pizzas that Party 2 received, 55% were of Thin Crust type hence, total number of Thin Crust pizza received by Party 2 = 0.55*120 = 66. Consequently Party 1, must have received 54 Deep Dish type pizzas. 
Therefore, total number of Thin Crust pizzas ordered by Party 3 = Total Thin Crust pizzas ordered - Thin Crust pizzas ordered by Party 1 - Thin Crust pizzas ordered by Party 2

300 - 72 - 66 = 162
Hence number of Deep Dish type of pizzas order by Party 3 = 560 - 162 = 398  

Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Total number of Normal Cheese pizzas require to be delivered = 0.52*800 = 416 
Number of  Normal Cheese pizzas require to be delivered to Party 2 = 0.3*120 = 36
Number of  Normal Cheese pizzas require to be delivered to Party 3 = 0.65*560 = 364
Therefore, total number of Normal Cheese pizzas  require to be delivered to Party 1 = Total Normal Cheese pizzas to be delivered - Normal Cheese pizzas require to be delivered to Party 2 - Normal Cheese pizzas require to be delivered to Party 3
416 - 36 - 364 = 16 
It is given that 25% of these 16 Normal Cheese pizzas were of Deep Dish type, hence the number of D- NC type pizza require to be delivered to Party 1 = 0.25*16 = 4
Consequently, the number of T- NC type pizza require to be delivered to Party 1 = 16 - 4 = 12 
We can find out each type of pizza that is required to be delivered to Party 1. 

Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Cost Price of a T-EC pizza = Rs. 500
Cost Price of a D-EC pizza = Rs. 550
Cost Price of a T-NC pizza Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Cost Price of a D-NC pizza Practice Question - 65 (Tables) | 100 DILR Questions for CAT Preparation

Therefore the total bill amount for Party 1 = 12*330 + 60*500 + 4*330 + 44*550  = Rs. 59480
Therefore, option (a) is the correct answer. 

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FAQs on Practice Question - 65 (Tables) - 100 DILR Questions for CAT Preparation

1. What is the significance of tables in data representation?
Ans.Tables serve as an effective means of organizing and presenting data in a structured format. They allow for easy comparison of different data points, highlighting relationships and patterns that may not be immediately evident in textual data. This clarity aids in analysis, decision-making, and communication of information.
2. How can I prepare for the Tables section of competitive exams?
Ans.Preparation for the Tables section requires practice in interpreting and analyzing data presented in tabular form. Familiarize yourself with common types of tables, such as frequency tables and comparative tables. Work on practice questions, solve previous years’ papers, and focus on understanding how to extract relevant information efficiently.
3. What common mistakes should I avoid when solving questions related to tables?
Ans.Common mistakes include misreading data, overlooking units of measurement, and making calculation errors. Always double-check the data entries and ensure that you understand the context of the question. Additionally, take care to maintain accuracy in your calculations to avoid discrepancies in your answers.
4. Are there specific strategies to quickly analyze tables during exams?
Ans.Yes, effective strategies include scanning the table for key figures, summarizing the data in your mind, and making quick notes of relationships or trends you observe. Practice mental math to enhance your speed in calculations, and familiarize yourself with common patterns or formats used in tables to improve your response time.
5. How important is it to understand the context of data presented in tables?
Ans.Understanding the context is crucial as it provides insight into the significance of the data. It helps in interpreting what the numbers represent and how they relate to the question being asked. Contextual knowledge aids in making informed assumptions and drawing accurate conclusions from the data presented in tables.
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