There are 6 refineries, 7 depots and 9 districts. The refineries are BB, BC, BD, BE, BF and BG. The depots are AA, AB, AC, AD, AE, AF and AG. The districts are AAA, AAB, AAC, AAD, AAE, AAF, AAG, AAH, and AAI. Table A gives the cost of transporting one unit from refinery to depot. Table B gives the cost of transporting one unit from depot to a district.
Q1: What is the least cost of sending one unit from any refinery to any district?
(a) 95.2
(b) 0
(c) 205.7
(d) 284.5
Ans: (b)
The least cost of sending one unit is from BC to AC and Then to AAC which is 0.
Hence option (b).
Q2: What is the least cost of sending one unit from any refinery to the district AAB?
(a) 0
(b) 284.5
(c) 95.2
(d) None of these
Ans: (a)
The least cost of sending one unit from any refinery to the district AAB is from BD to AE and then from AE to AAB. The whole cost is 0.
Hence option (a).
Q3: What is the least cost of sending one unit from refinery BB to any district?
(a) 284.5
(b) 311.8
(c) 451.1
(d) None of these
Ans: (b)
Route for least cost of sending one unit from refinery BB to any district, would be first from BB to AB and then from AB to AAC.
Hence total cost 311.8 + 0 = 311.8
Q4: What is the least cost of sending petrol from refinery BB to district AAA?
(a) 765.6
(b) 1137.3
(c) 1154.3
(d) None of these
Ans: (d)
From the table, we can observe that the minimum cost of sending oil fro BB to AAA is via AB. Hence the total cost is 311.8+205 = 516.8
Q5: How many possible ways are there for sending petrol from any refinery to any district?
(a) 63
(b) 42
(c) 54
(d) 378
Ans: (d)
1 refinery can be selected among 7 in 7 ways, depots can be further selected in 6 ways and any district ca be selected in 9 different ways.
So, answer is 7*6*9 = 378
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