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Unit Test (Solutions): Proportional Reasoning-1 | Mathematics Class 8- New NCERT (Ganita Prakash) PDF Download

Time: 1 hour
M.M.: 30

General Instructions:

  • Attempt all questions.

  • Question numbers 1 to 5 carry 1 mark each.

  • Question numbers 6 to 8 carry 2 marks each.

  • Question numbers 9 to 11 carry 3 marks each.

  • Question numbers 12 and 13 carry 5 marks each.

Q1. Simplify the ratio 84 : 126.
a) 4 : 5
b) 2 : 3
c) 6 : 9
d) 7 : 10

Answer: b) 2 : 3

Q2. If a : b = 3 : 4 and b : c = 2 : 5, then a : b : c = ?
a) 6 : 8 : 20
b) 3 : 4 : 5
c) 2 : 3 : 5
d) 5 : 10 : 8

Answer: a) 6 : 8 : 20

Q3. A sum of $720 is divided in the ratio 2 : 7. The smaller share is:
a) $160
b) $140
c) $200
d) $180

Answer: b) $160

Q4. If 8 notebooks cost $64, the cost of 5 notebooks is:
a) $30
b) $35
c) $40
d) $45

Answer: c) $40

Q5. The fourth proportion of 5, 10, and 15 is:
a) 20
b) 25
c) 30
d) 35

Answer: b) 25

Q6. Fill in the Blanks: 

(a) The ratio of 2.5 m to 75 cm is ___ : ___.
(b) If 7 pencils cost $21, then the cost of 12 pencils is ___.
(c) If 9 : x = 27 : 54, then x = ___.

Ans: (a) 10 : 3

(b) $36

(c) 18

Q7: The monthly incomes of P and Q are in the ratio 5 : 7. If Q’s income is ₹42,000, find P’s income.

Solution:
Ratio P : Q = 5 : 7
So, 5 : 7 :: x : 42000

Cross multiply:
5 × 42000 = 7 × x
210000 = 7x
x = 210000 ÷ 7 = 30000

Answer: P’s income = ₹30,000

Q8: A recipe needs oil and milk in the ratio 4 : 3. If you use 900 g of milk, how much oil is needed?

Solution:
Oil : Milk = 4 : 3
So, 4 : 3 :: x : 900

Cross multiply:
4 × 900 = 3 × x
3600 = 3x
x = 3600 ÷ 3 = 1200

Answer: Oil needed = 1200 g (1.2 kg)

Q9. Simplify the ratio 90 : 135.
Solution:
HCF of 90 and 135 = 45
90 ÷ 45 = 2, 135 ÷ 45 = 3
Simplified ratio = 2 : 3

Q10. A’s salary is 25% more than B’s salary. Find the ratio of A’s salary to B’s salary.
Solution:
Let B’s salary = 100
A’s salary = 100 + 25 = 125
Ratio A : B = 125 : 100 = 5 : 4

Q11. Divide $630 in the ratio 5 : 4.
Solution:
Total parts = 9
Value of 1 part = 630 ÷ 9 = 70
Shares: 5 × 70 = 350, 4 × 70 = 280
Answer: $350 and $280

Q12. A man distributes $5400 among three daughters in the ratio 3 : 2 : 1. Find the amount received by each.
Solution:
Total parts = 3 + 2 + 1 = 6
Value of 1 part = 5400 ÷ 6 = 900
Daughter 1 = 3 × 900 = 2700
Daughter 2 = 2 × 900 = 1800
Daughter 3 = 1 × 900 = 900
Answer: $2700, $1800, $900

Q13. If a : b = 4 : 5 and b : c = 10 : 7, find the ratio a : b : c.
Solution:
a : b = 4 : 5 → a = 4k, b = 5k
b : c = 10 : 7 → b = 10m, c = 7m
To combine, make b equal.
LCM of 5 and 10 = 10
So, let b = 10 → a = 8, c = 7
Ratio = 8 : 10 : 7

The document Unit Test (Solutions): Proportional Reasoning-1 | Mathematics Class 8- New NCERT (Ganita Prakash) is a part of the Class 8 Course Mathematics Class 8- New NCERT (Ganita Prakash).
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FAQs on Unit Test (Solutions): Proportional Reasoning-1 - Mathematics Class 8- New NCERT (Ganita Prakash)

1. What is proportional reasoning and why is it important in mathematics?
Ans. Proportional reasoning is a mathematical approach that involves understanding the relationship between quantities in terms of ratios and proportions. It is important because it helps students solve real-world problems involving scaling, comparisons, and predictions. Mastering proportional reasoning is essential for advanced topics in mathematics and applications in science, economics, and everyday decision-making.
2. How can I identify proportional relationships in word problems?
Ans. To identify proportional relationships in word problems, look for key phrases that indicate a comparison between two quantities, such as "for every," "per," or "in relation to." If the ratio between the quantities remains constant as one quantity changes, then the relationship is proportional. For instance, if a recipe calls for 2 cups of flour for every 3 cups of sugar, the relationship between flour and sugar is proportional.
3. What are some common mistakes students make when solving problems involving proportions?
Ans. Common mistakes include misreading the problem, incorrectly setting up the proportion, and failing to simplify ratios. Students may also confuse proportional relationships with additive relationships, leading to incorrect conclusions. It's crucial to carefully analyze the problem and double-check calculations to avoid these errors.
4. Can you provide an example of a real-world application of proportional reasoning?
Ans. A real-world application of proportional reasoning is in cooking or baking. For example, if a recipe requires 4 eggs to make 12 cookies, a cook can use proportional reasoning to determine how many eggs are needed for 24 cookies by setting up the proportion 4/12 = x/24. Solving this gives x = 8 eggs, demonstrating how proportional reasoning can help scale recipes.
5. How can I improve my skills in proportional reasoning?
Ans. To improve skills in proportional reasoning, practice regularly with a variety of problems, including word problems, ratio comparisons, and scaling scenarios. Utilize visual aids like graphs and tables to better understand relationships. Additionally, working with real-life examples, such as budgeting or cooking, can enhance comprehension and application of proportional reasoning concepts.
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