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Numerical Problems Based on Newton's Second Law of Motion(1) - Force & Laws of Motion - Class 9 PDF Download

Force and Laws of Motion

Newton's Second Law of Motion

Numerical Problems Based on Newton's Second Law of Motion - 1

Type – 1 :-

Question – 1 – Calculate the force needed to speed up a car with a rate of 5ms-2, if the mass of the car is 1000 kg.

Solution:

According to questions:

Acceleration (a) = 5m/s2 and Mass (m) = 1000 kg, therefore, Force (F) =?

We know that, F = m x a

                            = 1000 kg x 5m/s2

                            = 5000 kg m/s2

Therefore, required Force = 5000 m/s2 or 5000 N

Question – 2- If the mass of a moving object is 50 kg, what force will be required to speed up the object at a rate of 2ms-2?

Solution:-

According to the question,

Acceleration (a) = 2ms-2 and Mass (m) = 50 kg, therefore, Force (F) =?

We know that, F = m x a

                            = 50 kg x 2m/s2

                            = 100 kg m/s2

Therefore, required Force = 100 m/s2 or 100 N

Question – 3 – To accelerate a vehicle to 3m/s2 what force will be needed if the mass of the vehicle is equal to 100 kg?

Solution:

According to the question,

Acceleration (a) = 3m/s2 and Mass (m) = 100 kg, therefore, Force (F) =?

We know that, F = m x a

= 100 kg x 3m/s2

= 300 kg m/s2

Therefore, required Force = 300 m/s2 or 300 N

Type -II

Question -1 – To accelerate an object to a rate of 2m/s2, 10 N force is required. Find the mass of object.

Solution:

According to the question:

Acceleration (a) = 2m/s2, Force (F) = 10N, therefore, Mass (m) = ?

We know that, F = m x a

Numerical Problems Based on Newton`s Second Law of Motion(1) - Force & Laws of Motion - Class 9

Thus, the mass of the object = 5 kg

Question – 2 – If 1000 N force is required to accelerate an object to the rate of 5m/s2, what will be the weight of the object?

Solution:

According to the question,

Acceleration (a) = 2m/s2, Force (F) = 1000N, therefore, Mass (m) = ?

We know that, F = m x a

Numerical Problems Based on Newton`s Second Law of Motion(1) - Force & Laws of Motion - Class 9

Thus, the mass of the object = 200 kg

Question – 3 – A vehicle accelerate at the rate of 10m/s2 after the applying of force equal to 50000 N. Find the mass of the vehicle.

Solution:

According to the question,

Acceleration (a) = 10 m/s2, Force (F) = 50000N, therefore, Mass (m) = ?

We know that, F = m x a

Numerical Problems Based on Newton`s Second Law of Motion(1) - Force & Laws of Motion - Class 9

Thus, the mass of the vehicle = 5000 kg

Type - III

Question – 1 - What the acceleration a vehicle having 1000 kg of mass will get after applying a force of 5000N?

Solution:

According to question:

Mass (m) = 1000 kg, Force (F) = 5000N, Acceleration (a) =?

We know that, Force = Mass x Acceleration or F = m x a

Therefore,

Numerical Problems Based on Newton`s Second Law of Motion(1) - Force & Laws of Motion - Class 9

Thus acceleration of the vehicle = 5 ms-2

Question – 2 – After applying a force of 1000 N an object of mass 2000 kg will achieve what acceleration?

Solution:

According to the question,

Mass (m) = 2000 kg, Force (F) = 1000N, Acceleration (a) =?

We know that, Force = Mass x Acceleration or F = m x a

Therefore,

Numerical Problems Based on Newton`s Second Law of Motion(1) - Force & Laws of Motion - Class 9

Thus acceleration of the vehicle = 0.5 ms-2

Question – 3 – An object requires the force of 100N to achieve the acceleration ‘a’. If the mass of the object is 500 kg what will be the value of ‘a’?

Solution:

According to the question,

Mass (m) = 500 kg, Force (F) = 100N, Acceleration (a) =?

We know that, Force = Mass x Acceleration or F = m x a

Therefore,

Numerical Problems Based on Newton`s Second Law of Motion(1) - Force & Laws of Motion - Class 9

Thus acceleration of the vehicle = 0.2 ms-2

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FAQs on Numerical Problems Based on Newton's Second Law of Motion(1) - Force & Laws of Motion - Class 9

1. What is Newton's second law of motion?
Ans. Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In mathematical terms, it can be written as F = ma, where F is the net force, m is the mass of the object, and a is the acceleration.
2. How can Newton's second law of motion be applied to solve numerical problems?
Ans. To solve numerical problems based on Newton's second law of motion, we need to identify the net force acting on the object and the mass of the object. We can then use the formula F = ma to calculate the acceleration. Once the acceleration is known, we can use other kinematic equations to find additional information such as velocity, distance, or time.
3. What are some examples of numerical problems that can be solved using Newton's second law of motion?
Ans. Some examples of numerical problems that can be solved using Newton's second law of motion include calculating the force required to accelerate an object, finding the acceleration of an object given the applied force and mass, determining the mass of an object based on its acceleration and the applied force, and calculating the net force acting on an object given its mass and acceleration.
4. How does Newton's second law of motion relate to real-life situations?
Ans. Newton's second law of motion is applicable to a wide range of real-life situations. It helps explain how objects accelerate when a force is applied to them, such as when a car speeds up or slows down. It also explains why it is easier to push a lighter object compared to a heavier one with the same amount of force. By understanding this law, we can analyze and predict the motion of objects in various scenarios.
5. What are the units of force, mass, and acceleration in the context of Newton's second law of motion?
Ans. In the context of Newton's second law of motion, the SI unit of force is the Newton (N), the unit of mass is the kilogram (kg), and the unit of acceleration is meters per second squared (m/s^2). It is important to use consistent units when applying the formula F = ma to ensure accurate calculations.
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