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Isolation of Elements, Class 12, Chemistry Detailed Chapter Notes PDF Download

Minerals, Ores and Concentration of Ores - Isolation of Elements, Class 12, Chemistry

Minerals : Naturally occuring chemical substance in which metal exist either in its free state or in combined state is called mineral.

Ore : Mineral from which metal can be conventionaly and economically extracted is called ore & impurities associated with it is called gangue or matrix

Types of Ores :

Sulphide Ores : 

Galena : PbS,                               Cinnabar : HgS,

Zinc bllend : Zns,                         Chalcopyrite : CuFeS2

Copper glance : Cu2S                    Fool's Gold : FeS2

Oxide Ores :

Bauxite : Al2O3. 2H2O                   Haematite : Fe2O3

Limonite : Fe2O3. 3H2O                Tin stone or Cassiterite : SnO2

Carbonate Ores : Siderite : FeCO3  Calamine ZnCO3

Malacite : Cu(OH)2CuCO3 Dolomite CaCO3. MgCO3. 2H2O

lime stone : CaCO3

 

Sulphate Ores : 

Gypsom : CaSO4.2H2O                                           Anylesite PbSO4

Glauber's salt : Na2SO4. 10 H2O                           Mohr's salt : FeSO4. (NH4)2SO4. 6H2O

 

Halide Ores : Rock salt : NaCl                   Cryolite : Na3AlF6

Fluorspar : CaF2                 Carnallite : KCl. MgCl2. 6H2O

 

Nitrate Ores : Chiele Saltpeter : NaNO3                       Indian Salt petre : KNO3

 

Native Ores : Those metals which are chemically less reactive. They occur in the earth crust in form of free state (lumbs)

e.g : Cu, Ag, Au, Hg, Pd, Pt, Bi

 

General principles and processes involved in the extraction of metal from its ore :

The extraction of metal from its ore is completed in five steps :

Step I : Pulverization : The crushing of ore to powdered state is called pulverisation.

Step II : concentration or Dressing or Beneficiation of ore

Step III : Conversion of Concentrated ore into oxide form

step IV : Reduction of oxide to the metal

Step V: Purification or refining of crude metal :

Step I : Pulverization : The crushing of ore to powdered state is called pulverisation

This process in stamp mill or ball mill

 

Step II : Concentration or Dressing or beneficiation of Ore

(a) By Gravity separation : Ore particles are heavier than the gangue particles. This is used for the separation of most of the gangue particles :

⇒ By Wilfley Table Method Class 12, Ores and Metallurgy,Question and Answer (Q & A)

⇒ By Hydraulic Classifier

 

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

(b) By Magnetic separator :

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Cassiterite or Tinstone contains impurities of wulframite or wulframates of Fe & Mn.

⇒ Tin stone : SnO2 → Diamagnetic

⇒ Wulframites or wulframates of

Fe & Mn : FeWO4, MnWO4 ⇒ Paramagnetic.

Ulframates of Fe & Mn from Tin stone by magnetic separator.

 

(c) By Froth Floatation Process : This method is used for the concentration of sulphide ores.

It is based on the concept that the sulphide ores are prefrentially wetted by pine oil, camphor oil while gangue particles are prefrentially by water.

This is based on the physical phenomenon of adsorption.

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

Frother : Pine oil, Camphor oil

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

Froth Stabilizers : They reduce surface tension of water e.g. cresols, amines.

Collector : Sodium or Potassium xanthates. It combines with sulphide ore & makes them water replent so that its affinity towards pine oil increases (Adsorption tendency increases)

KOH EtOH → Et O- K   H2O

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

Depressant : KCN or NaCN

ZnS is found to be an impurity with the lead sulphide. Therefore to separate out PbS from ZnS depressant KCN or NaCN added.

PbS NaCN → No complex formation due to very law Ksp of PbS.

ZnS 4NaCN → 4Na   [Zn (CN)4]2-  S- -

                                        (water soluble)

                                     Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Thus, ZnS becomes water soluble & it remains with gangue while PbS comes out with the froth.

 

Activator : CuSO4

From galena (PbS.ZnS) ZnS is removed

ZnS 4NaCN Class 12, Ores and Metallurgy,Question and Answer (Q & A) 4 Na  +  [Zn(CN)4]2- Class 12, Ores and Metallurgy,Question and Answer (Q & A) [Cu(CN)4]3-  ZnS ¯

                                   + S- -                              (water soluble)

                                                                           (more stable)

& ZnS is taken out by froth floatation second time.

 

(ii) Chemical Method of Concentration :

Leaching : It involves dissolution of metalic ore in a suitable reagent in which metallic ore is soluble and impurities are insoluble.

Leaching of alumina from bauxite :

Al2O3(s) 2NaOH(aq) 3H2O(I) → 2Na[Al(OH)4](aq)

Having F2O3 as important leachant.

The aluminate in solution is acidified by adding acid and hydrated Al2O3 is precipitated.

2Na[Al(OH)4](aq)  H (aq) Class 12, Ores and Metallurgy,Question and Answer (Q & A) Al(OH)3 ¯ H2O Na (aq).

                                                       (white ppt)

Hydrated alumina is filtered, dried and heated to give back pure Al2O3 :

Al(OH)3¯ Class 12, Ores and Metallurgy,Question and Answer (Q & A) Al2O3(s) 3H2O(g)

                         white (pure)

 

Other examples :

In the metallurgy of silver and gold, the respective metal/ore is leached with very dilute solution of NaCN or KCN in the presence of air (for O2) from which the metal is obtained by displacement reaction.

4M(s) 8CN-(aq) 2H2O(aq) O2(g) → 4[M(CN)2](aq) 4OH-(aq)

(M = Ag Or Au)

2[M(CN)2](aq) Zn(s) → [Zn(CN)4]2-(aq) 2M(s)¯

 

Step III : Conversion of Concentrated ore into oxide form :

It is done either by calcination or by roasting.

(i) Calcination :

Calcination is carried out for carbonate, hydrated metal oxide & metal hydroxide ores.

It is carried out in the absence of air i.e., heating in absence of air.

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Due to calcination ore becomes porous.

Volatile organic impurities get evaporated

Class 12, Ores and Metallurgy,Question and Answer (Q & A) Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

(ii) Roasting In the presence of air the sulphide are heated in free supply of air below m.p. Impurities of sulphur, phosphorus, arsenic & antimony are converted into their corresponding volatile oxide & thus get removed.

Moisture & Water of crystallisation are also removed.

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

Step IV : Reduction of oxide to the metal :

(b) Reduction of Metal oxide / conc. ore into free metal .

This can be carried out

(i) chemical reduction

(ii) By self reduction or auto reduction or Air Reduction

(iii) Metal - displacement method

(iv) By electrolytic Reduction

(v) By amulgamation.

(i) & (ii) method are collectively known as Pyrometallurgy

e.g. Sn, Pb, Fe, Hg, Cu, B, Zn, (Based on Ellinghum diagram)

(iii) step is called hydrometallurgy — Cu, Ag, Au are extracted

(iv) step is called Electrometallurgy, Alkali, Alkaline earth metals & Al & base electrolysis

(v) is used for Ag & Au

 

(i) Chemical Reduction :

1. Smelting i.e., carbon Reduction - Reduction of metal oxide by coke, coal & COReduction of the metal oxide usually involves heating it with some other Substance acting as a reducing agent, e.g., C or CO or even another metal. The reducing agent (e.g., carbon) combines with the oxygen of the metal oxide.

MxOy + yC → xM y + CO

Some metal oxides get reduced easily while others are very difficult to be reduced. To understand the variation in the temperature requirement for thermal reductions and to predict which element will suit as the reducing agent for a given metal oxide (MxOy), Gibbs energy interpretations are done, which is explained by ellingham diagram.

ΔG = ΔH - TΔS

If ΔH is greater than zero then reduction will be feasible on increasing temprature i.e., |TΔS| > |ΔH|

 

Ellingham diagram -

M(s) +  Class 12, Ores and Metallurgy,Question and Answer (Q & A) O2(g) Class 12, Ores and Metallurgy,Question and Answer (Q & A) M2Ox(s)

ΔG = ΔH - TΔS

Therefore, For forward rxn ΔS < 0

 

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

(Ellingham diagram for formation of M2Ox)

Ellingham diagram is a plot of formation of an element oxide between ΔG & ΔT

 

Ex. Which of the following statements are true :

A → Mg(s)  Class 12, Ores and Metallurgy,Question and Answer (Q & A)O2(g) Class 12, Ores and Metallurgy,Question and Answer (Q & A) MgO(s)

B → Mg(l)  Class 12, Ores and Metallurgy,Question and Answer (Q & A)O2(g) Class 12, Ores and Metallurgy,Question and Answer (Q & A) MgO(s)

C → Mg(g)  Class 12, Ores and Metallurgy,Question and Answer (Q & A)O2(g) Class 12, Ores and Metallurgy,Question and Answer (Q & A) MgO(s)

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

I : Below 1350° Mg can reduce Al2O3

II : Above 1350° C Mg Will reduce Al2O3

III : Below 1350° Al can reduce MgO

IV : Above 1350° Al can reduce MgO

V : At 1350° C there is no change in free energy i.e., ΔG = 0

Sol. Class 12, Ores and Metallurgy,Question and Answer (Q & A) ΔG < 0

    (Its ΔG high)                     (Its ΔG less)

Al2O3 + 3 Mg Class 12, Ores and Metallurgy,Question and Answer (Q & A) 3 MgO + 2Al

At 1350° C both reactions have same G Therefore,ΔG = 0

To carry out smelting below 800°C, CO is used as reducing agent while above 800°C, smelting is carried out by coke.

2C(s) + O2(g) → 2CO (g) + ΔH = -221.0 kJ/mole

DS = 179.4 J kJ/mol

C(s) + O2(g) → CO2(g) + ΔH = - 393.5 kJ/mol

ΔS = 2.89 JK-1 mole-1

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Aluminium can be extracted from Alumina by carbon reduction but the method is highly uneconomical because -

(i) As the smelting occurs above 200°C hence a part of the aluminium will go into vapour phase (M.P. = 2520°C)

(ii) At this high temperature the liberated Al will combine with the carbon & aluminium carbide will be formed.

(iii) ΔHfor of alumina is high - ve value

Therefore,It is thermodynamically more stable & reduction is more difficult

To extract metal from sulphide ore is carried out by firstly roasting it into metal oxide & followed by its smelting. Metal sulphide or sulphide ore is not directly smelted to metal.

2PbS C Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2Pb + CS2 (Thermodynamically Not feasible)

Pbs  Class 12, Ores and Metallurgy,Question and Answer (Q & A)O2 Class 12, Ores and Metallurgy,Question and Answer (Q & A) PbO + SO2­

PbO + C Class 12, Ores and Metallurgy,Question and Answer (Q & A) Pb CO ­ Thermodynamically feasible

ΔGf of PbS = -21.9 kcal/mol

ΔGf of CS2 = 17.15 kcal/mol

ΔGf of PbO = -45.1 kcal/mol

ΔGf of SO2 = -71.7 kcal/mol

ΔGf of CO = - 32.8 kcal/mol

 

Flux : Additional substances which are used during metal extration to remove acidic or basic impurity are called flux depending upon nature of impurity flux are of two types.

(i) Basic Flux : It is used to remove acidic impurity eg : CaO, MgO, CaCO3, MgCO3 FeCO3 etc.

(ii)Acidic Flux : It is used to remove basic impurity eg : SiO2, B2O3, P2O5, Na2B4O7. (Borax)

Smelting : Phenomenon of slag formation by combining flux with impurity is called smelting.

Flux + Impurity → Slag (Smelting)

        (Basic or acidic)

 

Properties of slag :

(i) Slag has low melting point than metal.

(ii) Slag is lighter than metal therfore it floats over the molten metal and prevents further oxidation of molten metal by air.

(iii) Slag immiscible with molten metal therefore it can be easily separted from molten metal.

 

(b) Gold Schmidt Thermite Reduction :

Thermite : Al powder

Cr2O3  + 2Al Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2Cr + Al2O3

(DGf = -540 kJ/mole) (DG3 = -827 kJ/mole)

B2O3 + 2Al Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2B + Al2O3

2Mn3O4 + 8Al Class 12, Ores and Metallurgy,Question and Answer (Q & A) 9Mn + 4 Al2O3

Fe2O3 + 2Al Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2Fe + Al2O3

This method is used for reduction of those metal oxides which are highly stable if they are reduced by coke it will occur at very high temprature & at this high temperature the liberated metal will combine with the coke & carbide will be formed hence Al powder i.e., thermite is used

 

(c) Reduction by Hydrogen :

Because of inflammable nature of hydrogen its use as a reducing agent is very restricted.

Cu2O + H2 Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2Cu + H2O

MOO3 + 3H2 Class 12, Ores and Metallurgy,Question and Answer (Q & A) M0 + 3H2O

BCl3 +  3/2H Class 12, Ores and Metallurgy,Question and Answer (Q & A) B + 3HCl

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

Reduction by other metals :

SiCl4 + 2Mg Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2MgCl2  Si

Kroll process used for extraction of Ti & Zr

TiCl4 + 2Mg Ti 2MgCl2

ZrCl4  2Mg Class 12, Ores and Metallurgy,Question and Answer (Q & A) Zr 2MgCl2

I.M.I Process (Imperial Metal Industries)

TiCl4  4Na Class 12, Ores and Metallurgy,Question and Answer (Q & A) Ti 4NaCl

(ii) By Self reduction or Auto reduction or Air Reduction :

This method is used for extraction of copper, lead, mercury i.e., it is used for the extraction of metal from their sulphide ores.

In this method the sulphide ore is roasted in free supply of air to its metal oxide & then air supply is cut off followed by heating by increasing temprature & metal is extracted by self reduction.

PbS  Class 12, Ores and Metallurgy,Question and Answer (Q & A) Class 12, Ores and Metallurgy,Question and Answer (Q & A) PbO SO2 ­

PbS 2O2 Class 12, Ores and Metallurgy,Question and Answer (Q & A) PbSO4

Now air supply is cut off followed by heating

PbS(s)  2PbO(s) Class 12, Ores and Metallurgy,Question and Answer (Q & A) 3Pb(l)  SO2 ­

Self reduction is responsible for acid rain than roasting because SO2 dissolves in air, (3927cc CO2 in 1000cc of H2O)

 

(iii) By Metal Displacement Method or By Hydrometallurgy :

Class 12, Ores and Metallurgy,Question and Answer (Q & A) Class 12, Ores and Metallurgy,Question and Answer (Q & A)

In this method the concentrated ore is treated/ leached with specific chemical reagent that converts the ore into water soluble salt. Now, on adding more electropositive metal into the aqueous salt solution the metal (less electro positive) is displaced

e.g.

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Iron is found to be an impurity in the copper ores hence if Zn is added to extract copper, iron will also be displaced along with copper & that is why iron is used.

Both metals which extracted & by which we extracted are water insoluble

 

(iv) Electro Metallurgy : The metal is extracted by passing electricity into its fused salt or in aqueous solution.

Extraction of sodium :

⇒ By electrolysis of Aq. NaCl solution :

NaCl(s) x H2Class 12, Ores and Metallurgy,Question and Answer (Q & A) Na (aq) Cl-(aq)

H2Class 12, Ores and Metallurgy,Question and Answer (Q & A) H   OH-

On passing electricity

At cathode : 2H   2eClass 12, Ores and Metallurgy,Question and Answer (Q & A) H2 ­

ΔG = - n FE°

Therefore,Na  does not discharge at cathode

At anode : 2Cl- Class 12, Ores and Metallurgy,Question and Answer (Q & A) Cl2­ 2e-

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

In sol : Na   OH- Class 12, Ores and Metallurgy,Question and Answer (Q & A) NaOH

⇒ By electrolysis of fused NaCl :

 

On Passing electricity

At cathode : 2Na +  2e- Class 12, Ores and Metallurgy,Question and Answer (Q & A) Na

At Anode : 2Cl- Class 12, Ores and Metallurgy,Question and Answer (Q & A) Cl2 ­+   2e-

In sol. Na + OH- Class 12, Ores and Metallurgy,Question and Answer (Q & A) NaOH

 

Electrochemical Principles of Metallurgy :

We have seen how principles of thermodynamics are applied to pyrometallurgy. Similar priniciples are effective in the reductions of metal ions in solution or molten state. Here they are reduced by electrolysis or by adding some reducing element.

In the reduction of molten metal salt, electrolysis is done. Such methods are based on electrochemical principles which could be understood through the equation,

ΔG° = -nE°F ..................... (16)

Here n is the number of electrons and E° is the electrode potential of the redox couple formed in the system. More reactive metals have large negative values of the electrode potential. So their reduction is difficult. If the difference of two E° values corresponds to a positive E° and consequently negative DG° in equation (16), then the less reactive metal will come out of the solution and the more reactive metal will go to the solution, e.g.,

Cu2 (aq) Fe(s) → Cu(s) Fe2 (aq)

In simple electrolysis, the Mn  ions are discharged at negative electrodes (cathodes) and deposited there. Precautions are taken considering the reactivity of the metal produced and suitable materials are used as electrodes. Sometimes a flux is added for making the molten mass more conducting.

=======================================================

Methods of Refining of Metals - Isolation of Elements, Class 12, Chemistry 

Step V: Purification or refining of crude metal :

(A) By physical Methods :

(a) liquation

(b) Distillation

(c) Zone refining

(B) By Chemical Methods

(a) Oxidation

(b) Poling

(c) Vapour Phase Refining

(C) By Electrolytic Refining

(A) By Physical Method :

(a) Liquation Method :

Class 12, Ores and Metallurgy,Question and Answer (Q & A) Class 12, Ores and Metallurgy,Question and Answer (Q & A)

This method is used for refining of those metal which have very low m.p. in comparison to impurity present in them.

e.g. → Sn, Pb, Hg, Bi, Zn

(b) Distillation Method : It is used for refining of those metals which are volatile & hence it is used for refining of Zn, Cd, Hg (i.e., is of filled d orbital metal)

(c) Zone Refining : (Si, Ge, Pb, B, Ga, In)

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Concept : Impurities are more soluble in the melt than in the solid state. (Fractional crystallization)

 

(B) By Chemical Methods :

(a) Oxidation : (Fe, Sn, Pb)

eg. Pig iron : M.P. 1080

Impurities : C, P, Mn, Si

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

This method is used for the refining of metals in which impurtities are more oxidisable than metal itself.

When impurities oxidise they are converted into either volatile oxides or non volatile oxides Non-volatile oxides are removed either by slag formation or by removing their skum Oxidation is known by various names : bassemerization (Fe), Cupellation (Ag), Softening (Pb) or Puddling (for iron), tossing (for iron)

 

(b) Polling : When along with impurities the metal to be refine is also oxidised part then this method is used. In this method the molten impure metal is steared with green wood log, The hydrocarbons released from the log reduce metal oxide into metal while impurity oxides are not reduced. This method is used for refining of Cu & Tin. In both metals during poling iron get oxidised into FeO which in turn is oxidised into Fe2O3 while in case of Sn, SnO2 is reduced to tin (Sn) & in case of Cu copper (I) oxide i.e., cuprous oxide is reduced to Cu,

Cu2O → Cu

(c) Vapour Phase Refining : Impure metal is allowed to react with a suitable reagent such that a volatile unstable compound is formed & then the compound is decomposed to pure free metal when it is subjected to heat.

Mond's Process : used for refining of Ni

 

(C) By Electrolytic Refining :

Anode : Impure metal

cathode : Pure metal

Electrolyte : Aq. salt sol. of metal/fused metal salt Acid

Anode Mud : Metals which are less electropositive than the metal to be refined.

In electrolyte : More electropositive metals are found.

eg. in Cu : Ag, Au, Fe, Zn

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

1. Gold :

Occurrence :

Found mostly in free state in quartz veins called auriferous quartz.

Extraction of gold from native ore :

(A) Crushing and concentration :

The gold ore is crushed, powdered finely and concentrated by washing with water.

(B) (Treatment with 0.25-1% sodium cyanide or potassium cyanide solution) Extraction of Au, from Native ore by Mac-Arthur forest cyanide process.

4Au + 8NaCN + 2H2O O2 → 4Na[Au(CN)2] + 4NaOH

                                                      soluble

2Na[Au(CN)2] Zn → Na2[Zn(CN)2] 2Au¯

                                         (Impure)

Impure Au is purified by Electrolytic refining method or by amalgamation.

 

(C) Electrolytic refining method :

Anode : Impure Au

Cathode : Pure Au

Electrolyte : 4% AuCl3 solution acidified with 10% HCl

Purple of Cassius : It is of colloidial gold solution :

2AuCl3 + 3SnCl2 → 2Au + 3SnCl4

                                                (Very dil.)

The gold thus precipitated is absorbed by Sn (OH)4 formed by hydrolysis of SnCl4

SnCl4 + 4H2O → Sn(OH)4 + 4HCl

This form of gold is purple in colour named after its discoverer, Cassius.

 

2. Silver :

Ores : (i) Siliver glance or argentite Ag2S (main ore)

(ii) Ruby silver or pyrargyrite 3Ag2S. Sb2S3

(iii) Horn silver or chlorargyrite AgCl.

 

Extraction of silver from silver glance :

(A) Crushing and concentration : The ore is crushed, powdered and concentrated by froth floatation process.

(B) Extraction of Ag by Mac-Arthur forrest cyanide process : (Treatment with 0.4-0.7% sodium cyanide solution)

Ag2S + 4NaCN Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2Na [Ag(CN)2] + Na2S

soluble

The role of air is to oxidise Na2S so that reaction proceed in the forward direction.

 Impure Ag is purified by Electolytic refining method or by amalgamation.

 

(C) Electrolytic refining : Anode : Impure Ag

Cathode : Pure Ag

Electrolyte : AgNO3(aq) HNO3.

 

Silver from (commercial lead) argentiferous lead by Parke's process :

Desilverisation of Lead :

Lead extracted from galena (PbS) contains impurities of Cu, Ag, Bi, As, Fe Zn, Sn, etc. and is called commercial lead or argentiferous lead. This contains Ag upto 2% which is extrated by parkes process. Commerical lead is mixed with a large quantity of Zn and the mixture is melted, where Zn-Ag alloy is formed and Pb remains in the molten state. The alloy is strongly heated where Zn is distilled of leaving Ag. This silver contains some Pb impurity which is removed by cupellation process. Impure Ag is melted in a cupel (a boat shaped dish made of bone ash) by passing Hot blast of air. Pb is oxidised to PbO (litherge) which is either absorbed by cupel or carried away by blast of air leaving pure Ag.

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Separation of silver from gold (Parting with conc. H2SO4)

Alloy (Au < 20%) is boiled with conc. H2SO4 where Ag is dissolved as Ag2SO4and Au remains as spongy mass.

Ag2SO4  + Zn → 2Ag + ZnSO4 (Metal displacement reaction)

                           (sparingly

                          soluble solution)

If alloy contains Au > 20%, then some Ag is added to it so as to reduce the % Au below 20.

Silver from silver coin or silver ornaments :

(Ag Cu) Class 12, Ores and Metallurgy,Question and Answer (Q & A) Ag (aq) Cu2 (aq) 3NO3-(aq) Class 12, Ores and Metallurgy,Question and Answer (Q & A) AgCl¯ Cu2 (aq) 3NO3-

 

Recovergy of Ag from AgCl :

(i) By treating with KCN solution :

2AgCl + 2NaCN → 2Na[Ag(CN)2] + 2NaCl

soluble complex

2Na[Ag(CN)2] + Zn(dust) → 2Ag + Na2[Zn(CN)4]

(ii) Boiling with caustic soda and glucose.

2AgCl + 2NaOH → Ag2O + 2NaCl + H2Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2Ag + C6H12 + O7 (Gluconic Acid)

(iii) 2AgCl Na2CO3 Class 12, Ores and Metallurgy,Question and Answer (Q & A)2Ag CO2  O2  2NaCl

 

3. Copper :

Ores :

Copper pyrites or Chalcopyrites CuFeS2 (main ore) ; Cuprite or ruby copper Cu2O ; Malachite CuCO3Cu(OH)2(green) ; Azurite 2CuCO3.Cu(OH)2(Blue) ; Copper glance Cu2S, bornite (peacock ore) Cu5FeS4.

 

Extraction of copper from copper pyrites :

(A) Crushing and concentration : Ore is first crushed and then powedered finely and powdered ore is concentrated by froth floatation process.

(B) Roasting : Concentrated ore along with SiO2 is heated in excess of air in a reverberatory furnace.

(Cu2S FeS FeS2) + 2CuFeS + O2 → Cu2S + 2FeS SO2­

2FeS + 3O2 → 2FeO + 2SO2­ (Major oxidation)

2Cu2S + 3O→ 2Cu2O + 2SO2­ (Minor oxidation)

Cu2O + FeS → Cu2S + FeO

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Reverberatory Furance

S O2 → SO2 ­ ; 4As SO2 → 2As2O3­ ; 4Sd 3O2 → 2Sb2O3­

Volatile impurities are removed in this step.

 

(C) Slag formation :

Roasted ore mixed with sand and strongly heated in furnace.

FeO + SiO2 → FeSiO3

flux slag

Upper layer containing slag is removed and lower layer contains mostly Cu2S (98%) with little amount of FeS(2%) is called matte.

(D) Bessemerisation : (Self - reduction)

2FeS + 3O2 Class 12, Ores and Metallurgy,Question and Answer (Q & A)2FeO + 2SO2

FeO + SiO2 Class 12, Ores and Metallurgy,Question and Answer (Q & A)FeSiO3(slag)

2Cu2S + 3O2 Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2Cu2O 2SO2 (partial roasting)

                             (limited air)

Cu2S + 2Cu2Class 12, Ores and Metallurgy,Question and Answer (Q & A) 6Cu + SO2 (self reduction)

                                           (R.A.) (impure)

Impure copper obtained has blister appearances and therefore called blister copper.

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Poling : Molten Cu is stirred with poles of green wood to reduce any copper oxide impurity into Cu.

Electrolytic refining :

Anode - impure Cu ;

Cathode - Pure Cu ;

Electrolyte CuSO4, H2SO4.

The more electropositive impurities like Zn, Fe, Ni etc. get dissolved in solution and less positive impurities like Ag, Au collect below anode as anode mud.

 

4. Lead :

Ores : Galena PbS (Main ore) ; Anglesite PbSO4 ; Cerussite PbCO3

Extraction of lead from galena :

Crushing and conentration : The ore is crushed, grinded finely and concentrated by froth floatation process.

Roasting : In reverberatory furnance, limited supply of air is passed at moderate temperature.

PbS + 2OClass 12, Ores and Metallurgy,Question and Answer (Q & A) PbSO4 ;

2PbS + 3O2 Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2PbO + 2SO2

Self reduction : Air supply is cut off and the temperature is increased to melt the change in reverberatory furnace.

PbS + 2PbO 3Pb SO2

           (R.A.) impure

PbS PbSO4 2Pb 2SO2

(R.A.) impure

SiO2  CaO (flux) Class 12, Ores and Metallurgy,Question and Answer (Q & A) CaSiO3 (slag)

PbSiO3  CaO (lime) Class 12, Ores and Metallurgy,Question and Answer (Q & A) PbO CaSiO3 (slag)

In this way, lime (CaO) prevents formation of PbSiO3.

Impure Pb is purified by electrolytic refining method or by liquation and poling.

Electrolytic refining :

Anode - Impure Pb

Cathode - Pure Pb

Electrolyte - PbSiF6  H2SiF6  gelatine?

 

5. Tin :

Ores : (i) Cassiterite or Tin stone SnO2 (Main ore) (It contains impurities of pyrites of Cu and Fe and magnetic impurity of wolframite which is a mixture of FeWO4  MnWO4).

This mineral is also called black tin to distinguish it from the metal Sn which is also called white tin.

 

Extraction of Sn from cassiterite :

(i) Crushing and concentration :

The ore is crushed and washed with a stream of runing water to remove lighter silicious impurities followed by magnetic separation method to remove the magnetic impurity of Wolframite.

 

(ii) Roasting :

Concentraed ore is heated in pressence of air, and volatile impurities (S as SO2, As as As2O3 and Sb as Sb2O3) are removed. The impurities of pyrites of Cu and Fe are converted into their respective oxides and sulphates.

 

(iii) Washing :

Sulphates of copper and iron are dissolved in water. The ore thus obtained contains 60-70% SnO2 and is called as black tin.

Carbon reduction :

The black tin is mixed with anthracite coal and heated to about 1300°C. If SiO2 is present as impurity then CaO is added as flux.

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

Refining :

(i) Liquation and poling :

Impure Sn is melted on the sloping hearth where Sn(m.pt. 232°C) is first melt and flows out leaving behind the less fusible impurities of Cu, Fe, W etc. The liquid Sn is then strirred with poles of green wood to reduce SnO2 (Impurity) to Sn.

 

(ii) Electrolytic refining :

Anode : Impure Sn

Cathode : Pure Sn

Electrolyte : SnSO4, H2SO4

 

6. Iron :

Ores : Haematite Fe2O3(Main ORE) ; Limonite Fe2O3.3H2O ; Magnetite Fe3O4 ; Siderite FeCO; Iron pyrites FeS2

Extraction of Iron from ore haematite :

Crushing and concentration : The oxide ore is first crushed in jaw crushers and then is broken in small pieces. Haematite (non-magentic) is washed with running water to remove earthy and siliceous impurities by levigation.

Calcination following by roasting :

The concentrated ore is roasted with excess air in a reverberatory furnace. During roasting step, the following changes occur :

(a) If FeCO3 is present as impurity, it gets decomposed into FeO which is oxidised by air to Fe2O3.

FeCO3 Class 12, Ores and Metallurgy,Question and Answer (Q & A) FeO CO2 (calcination)

siderite

4FeO O2 (air) Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2Fe2O3 (Roasting)

In this way, formation of FeSiO3 slag is prevented during melting, and following reaction does not occur.

SiO2  FeO → FeSiO3 (slag)

(b) The impurities of S, As are also removed as their volatile oxides

S O2 → SO2­

4As 3O2 → 2As2O3­,

The entire mass becomes porous and hence the reduction of Fe2O3 to spongy iron becomes easy at later stage.

 

Reduction in blast furnace.

(Fe2Oore lime stone coke) is smelted in blast furnace and following changes take place.

(i) Combustion Zone (155 - 1700°C)

(a) (Combustion zone) a blast of dry preheated air is blown into the furnace from near the bottom of the furnace. Near the bottom, the preheated air comes in contact with the falling coke and combustion of coke into CO2 takes place.

C O → CO2 DH = - 393.5 kJ

CO2 produced in the combustion zone rises up and meets with more coke in fusion zone and gets reduced to CO.

CO2  C → 2CO DH = 163.0 kJ

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

(ii) Reduction zone (250 - 700°C)

Near the top of the furnace (reduction zone), the temperature varies from 250-700°C. Here the oxide ore (Fe2O3) is reduced to spongy iron with the help of uprising vapours of CO produced in the zone of fusion.

Fe2O3  3COClass 12, Ores and Metallurgy,Question and Answer (Q & A)2Fe 3CO2

Actually above Reduction, takes in 3 steps :

3Fe2O3  CO → 2Fe3O4  CO2 ­

Fe3O4  CO → 3FeO CO2 ­

FeO CO → Fe CO2 ­

(Spongy iron)

Any Fe2O3 which escapes from reduction in reduction zone is reduced in fusion zone.

 

(iii) Slag formation zone (700-1000°C)

In the middle of the furnace (slag formation zone) where the temperature varies from 700-1000°C, lime stone (CaCO3) present in the change decomposes into CaO and CO2.

CaCO3 Class 12, Ores and Metallurgy,Question and Answer (Q & A) CaO CO2

CaO combines with the impurity of SiO2 and forms a fusible slag of CaSiO3. Thus CaO acts as a basic flux.

CaO(basic flux) SiO2 (acidic impurity) → CaSiO3(slag)

Slag is lighter than the molten iron. It moves down and floats over molten iron. This region where slag is fromed is called slag formation zone.

(iv) Fusion Zone (1000 - 1500°C)

Since the reduction of CO2to CO is an endothermic reaction (Heat is required), temperature is decreased to about 1500°C. Fe2O3 is reduced to Fe which might not have been reduced in the reduction zone.

Fe2O3  3C → 2Fe 3CO

Impurities are also reduced and get mixed up with spngy Iron.

MnO2  2C → Mn 2CO

2P2O5  10C → P4  10CO

SO2  C → S 2CO

SiO2  2C → Si 2CO

Spongy iron produced in the reduction zone melts here and gets impured in called pig iron, while slag being lighter floats over and thus prevents oxidation of Fe by blast of hot air.

 

Types of Iron :

1. Cast iron (2% to 5% carbon & other impurity)

2. Steel (0.5% to 2% carbon & other impurity)

3. Wrought iron (< 0.5% carbon & other impurity)

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

Manufacturing of wrought from cast Iron :

Wrought iron is mannfactured from puddling furnace having inner lining of haematite (Fe2O3) oxidant for impurities present in cast iron.

Mn Fe2O3 → MnO 2 Fe

(O.A.) (basic)

Si Fe2O3 → SiO2  2 Fe

(O.A.) (basic)

MnO SiO2 → MnSiO3  (slag)

(O.A.) (basic)

S Fe2O3 → SO2­ 2 Fe

C Fe2O3 → 3CO 2 Fe

3P4  10Fe2O→ 6P2O5  20Fe

P2O5  Fe2O3 → 2FePO4(slag)

 

Manufacturing of steel from cast from :

(i) Bassemerisation (already discussed)

(ii) Open-Hearth process (Siemen Marthin's process)

(iii) Electrical furnace process

Open hearth process (siemen Mortin's process)

Mn Fe2O3 → MnO 2 Fe

(O.A.) (basic)

 

Si Fe2O3 → SiO2  2 Fe

(O.A.) (Acidic)

MnO SiO2 → MnSiO3  (slag)

(O.A.) (basic)

S Fe2O3 → SO2­ Fe

(O.A.)

C Fe2O3 → 3CO ­ 2Fe

3P4  10Fe2O→ 6P2O5  20Fe

P2O5  3CaO → Ca3(PO4)2 (Thomas slag)

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Open hearth furnace for the manufacture steel from cast iron

 

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

After adding requried amount of spiegeleisen steel is formed.

In this method 2 - 5% iron is also oxidised by air because hearth is open therefore this method is discarded is modern age.

In modern age steel is manufactured by electrical furnace process or by L.D. process. In electrical fumace process heating effect is produced by passing electricity and all chemical reaction are similar to open-hearth process.

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

Heating Treatment of STEEL

(i) Annealing : Process of heating steel upto redness and then cooling it slowly is called annealing, In this way steel becomes soft, malleable and elastic.

(ii) Quenching : Process of heating steel upto redness and then cooling it suddenly by plundging in into oil or water is called quenching. In this way steel become hard and brittle.

(iii) Tempering : Process of heating quenched steel much below redness and then colling it slowly is called tempering. In this steel becomes neither so hard nor so brittle.

Surface Treatment of steel :

(i) Case - Hardening : Process of forming hard coating of iron carbide over mild steel by heating it with charcoal is called case - hardening.

(ii) Nitriding : Process of forming hard coating of iron nitride by heating steel with ammonia gas is called nitriding.

 

7. Zinc :

Ores : Zinc blende ZnS (main ore), Zincite (ZnO), Calamine, ZnCO3.

 

 

Extraction of zinc from zinc blende :

 

(A) Crushing and concentration :

The ore is crushed and concentrated by froth floatation process.

 

(B) Roasting :

The concentrated ore is roasted in presence of excess of air 

2ZnS 3O2 Class 12, Ores and Metallurgy,Question and Answer (Q & A)2ZnO 2SO2­

ZnS 2O2 Class 12, Ores and Metallurgy,Question and Answer (Q & A) ZnSO4

2ZnSO4 Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2ZnO­ 2SO2  O2

ZnSO4 decomposed at higher temperature

 

(C) Carbon Reduction (Balgian process) :

Roasted ore is heated with coke in a vertical fire clay retort.

ZnO­ Class 12, Ores and Metallurgy,Question and Answer (Q & A) Zn ­ CO

(R.A.) vapour

Vapours of zinc are collected by rapid cooling to get zinc spelter (Impure Zn).

Impure Zn is purified either by electrolytic refining method or by distillation.

==============================================================

Electrolytic Refining - Isolation of Elements, Class 12, Chemistry

(D) Electrolytic refining :

Anode : Impure Zn

Cathode : Aluminium Electrode

Electrolyte : ZnSO4(aq) H2SO4

* Extraction of Cr From FeCr2O4(FeO.Cr2O 3) Chromite ORE :

Conc. Step : Chromite ore is concentrated by gravity sep. Method to remove light impurites followed by magnetic sep. method to remove non-magnetic impurities.

Chemical Method to Separate Cr2O3 :

4FeO.Cr2O3  7O2 (air) 8 Na2CO3/16NaOH Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2Fe2O3  8Na2CrO4  8CO2/8H2O

Class 12, Ores and Metallurgy,Question and Answer (Q & A) Class 12, Ores and Metallurgy,Question and Answer (Q & A)

2Na  (aq) Cr2O72-(aq) SO42- (aq) Class 12, Ores and Metallurgy,Question and Answer (Q & A) 2Na (aq) CrO42- (aq)

(Orange Solution) yellow solution

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Na2Cr2O7.2H2 O Class 12, Ores and Metallurgy,Question and Answer (Q & A) NaCrO2 Class 12, Ores and Metallurgy,Question and Answer (Q & A) Cr(OH)3¯

(orange crystal) (green ppt)

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Cr2O3 (green solid)

Al-reduction method : (Goldsmith alumino thermite process)

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

Impure Cr is purified by electrolytic refining method.

Anode : Impure chromium

Cathode : Hg-electrode

Electrolyte : CrCl3  HCl

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

* Extraction of Mn from MnO2 (Pyrolusite) :

Pyrolusite is concentrated by gravity separation method followed by magnetic separation method to remove non-magnetic impurity.

Calcination :

MnO2 gives explosive rxn. with Al therefore in this step it is converted into mixed oxide Mn3O4.

3MnO2 Class 12, Ores and Metallurgy,Question and Answer (Q & A) Mn3O4(MnO Mn2O3) O2­

Al-reduction method : (Goldsmith alumino thermite process)

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Impure Mn is purified by electrolytic refining method.

Anode : Impure Mn

Cathode : Hg-electrode

Electrolyte : MnSO4  H2SO4

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

8. Aluminium :

Ores :

(i) Bauxite Al2O3.2H2O (main ORE) ; Diaspore Al2O3.H2O ; Corundum Al2O3

(ii) Mica K2O.3Al2O3.6SiO 2.2H2O ; Kaolin Al2O3.2SiO2.2H 2O

(iii) Cryolite Na3AIF6

Extraction of Al from Bauxite :

Purification of Bauxite : 

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

 

Electrolysis of pure fused Al2O3 (Hall - Heroult method)

Cathode - iron tank lined with graphite

Anode - Carbon rods dipped in molten electrolyte

Electrolyte - molten (20% Al2O3  60% Cryolite 20% CaF2) Temp » 1100°C

Cryolite lowers the melting point of mixture and makes the molten mix conducting.

Na3AlF6 Class 12, Ores and Metallurgy,Question and Answer (Q & A) 3NaF AlF3

AlF3 → Al 3  3F-

At cathode Al 3  3e- → Al

At anode 3F- → 3F 3e-

Al2O3  6F → 2AIF3   Class 12, Ores and Metallurgy,Question and Answer (Q & A)O2­

C  Class 12, Ores and Metallurgy,Question and Answer (Q & A) O2 → CO

CO  Class 12, Ores and Metallurgy,Question and Answer (Q & A) O2 → CO2

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

Anodes are periodically changed as they are consumed by oxygen liberated at anode.

Electrolytic refining (Hoppe's Method)

Iron box lined with carbon, contains the three molten layers.

Bottom layer : Impure Al as anode

Middle layer : (Na3AlF6  BaF2) Molten electrolyte

Tope layer : molten pure Al as cathode.

On passing the current aluminium is deposited at cathode from the middle layer and an equivalent amount is taken from andoe (bottom layer) levaing behind the impurites. In this way aluminium obtained is 99.98% pure.

 

9. Magnesium : (Dow's process)

Ores :

Carnallite MgCl2.KCl 6H2O (main ore) ; Epsom MgSo4.7H2O magnesite MgCO3 ; Kiesserite MgSO4. H2O ; Dolomite MgCO3. CaCO3 ; Kainite K2SO4. MgSO4. MgCl2.6H2O (Mg is also found in Talc, sabestos and chlorophyll)

Sea water contains 0.13% magnesium as chloride and sulphate. It involves following steps.

(a) Precipitation of magnesium as magnesium hydroxide by slaked lime :

MgCl2  Ca(OH)2 → Mg(OH)2 ¯ CaCl2 (ppt. reaction)

 

(b) Preparation of hexahydrated magnesium chloride :

Mg(OH)2  2HCl(aq) → MgCl2  2H2O (Neutralisation reaction)

The solution on concentration and crystallisation gives the crystals of MgCl2.6H2O

 

(c) Preparation of anhydrous magnesium chloride :

MgCl2.6H2Class 12, Ores and Metallurgy,Question and Answer (Q & A) MgCl2  6H2O

* It is not made anhydrous by simple heating because it gets hydrolysed.

MgCl2.6H2Class 12, Ores and Metallurgy,Question and Answer (Q & A) MgO 5H2O 2HCl

 

(d) Electrolysis of fused anhydrouns MgCl2 :

Magnesium chloride obtained by any of the above methods is fused and mixed with sodium chloride and calcium chloride in the temperature range of 972 - 1023K. The molten mixture is electrolysed. Magnesium is liberated at the carhode (iron pot) and chlorine is evolved at graphite anode.

MgCl2 Class 12, Ores and Metallurgy,Question and Answer (Q & A) Mg2   2Cl-

At cathode : Mg2   2e- → Mg(99% pure) ;

At anode : 2Cl- → Cl2  2e-

Class 12, Ores and Metallurgy,Question and Answer (Q & A)

The document Isolation of Elements, Class 12, Chemistry Detailed Chapter Notes is a part of Class 12 category.
All you need of Class 12 at this link: Class 12

FAQs on Isolation of Elements, Class 12, Chemistry Detailed Chapter Notes

1. What is meant by isolation of elements?
Ans. Isolation of elements is the process of obtaining pure metals from their ores. It involves various steps such as concentration of ores, conversion of ores into oxides, and reduction of oxides to obtain pure metals.
2. What are the different methods used for the isolation of elements?
Ans. The different methods used for the isolation of elements are: 1. Electrolytic method 2. Chemical reduction method 3. Zone refining method 4. Vapour phase refining method 5. Distillation method 6. Froth floatation method
3. What is electrolytic refining?
Ans. Electrolytic refining is a process of refining metals using electrolysis. In this process, impure metal is made the anode and a pure metal sheet is made the cathode. The impure metal dissolves in the electrolyte and pure metal is deposited on the cathode.
4. What is meant by zone refining?
Ans. Zone refining is a method used to purify metals. In this process, a circular mobile heater is used to melt a small section of the metal. The heater is slowly moved along the length of the metal, causing the impurities to move along with it. The process is repeated until the desired purity level is achieved.
5. What is the froth floatation method?
Ans. Froth floatation method is a method used for the concentration of ores. In this process, the ore is finely powdered and mixed with water and chemicals. Air is blown through the mixture to create bubbles, which carry the ore particles to the surface. The froth containing the ore particles is skimmed off, and the impurities are left behind.
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