Here is a short study guide to help you crack questions on “Simplification and Approximation“
B = Bracket,
O = Order (Powers, Square Roots, etc.)
D = Division
M = Multiplication
A = Addition
S = Subtraction
Example 1: Solve 12 + 22 ÷ 11 × (18 ÷ 3)^2 - 10
Solution:
= 12 + 22 ÷ 11 × 6^2 - 10 (Brackets first)
= 12 + 22 ÷ 11 × 36 - 10 (Exponents)
= 12 + 2 × 36 - 10 = 12 + 72 - 10 (Division and multiplication, left to right)
= 84 - 10 = 74 (Addition and Subtraction, left to right)
Example 2: Solve 4 + 10 - 3 × 6 / 3 + 4
Solution:
= 4 + 10 - 18/3 + 4 = 4 + 10 - 6 + 4 (Division and multiplication, left to right)
= 14 - 6 + 4 = 8 + 4 = 12 (Addition and Subtraction, left to right)
|x|= x {if x ≥ 0} and −x {if x < 0}
Exmaple: Solve |8|
Solution: |8| = |-8| = 8
Example1: Solve 4433.764 - 2211.993 - 1133.667 + 3377.442
Solution: Here,
4433.764 = 4434
2211.993 = 2212
1133.667 = 1134
3377.442 = 3377Now simplify, 4434 - 2212 - 1134 + 3377 = 4466
Example 2: Solve 530 x 20.3% + 225 x 16.8%
Solution: Here, 20.3% becomes 20% and 16.8% becomes 17%
Now, simplify 530 x 20% + 225 x 17%
= 106 + 38.25 = 144.25
NOTE: Check that the outside number squared times the inside number should equal the original number inside the square root.
Following are some solved examples to help you prepare well for the upcoming exams:
Ques1. A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes, and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has?
A. 45
B. 60
C. 75
D. 90
Answer: Option D
Explanation:
Let the number of notes of each denomination be x.
Then x + 5x + 10x = 480
=> 16x = 480
Therefore, x = 30.
Hence, total number of notes = 3x = 90.
Ques2. There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
A. 20
B. 80
C. 100
D. 200
View Answer
Answer: Option C
Explanation:
Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
Therefore, The required answer A = 100.
Ques3. The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is:
A. Rs. 3500
B. Rs. 3750
C. Rs. 3840
D. Rs. 3900
View Answer
Answer: Option D
Explanation:
Let the cost of a chair and that of a table be Rs. x and Rs. y respectively.
Then, 10x = 4y or y = 5/2 x.
Therefore, 15x + 2y = 4000
=> 15x + 2*(5/2)x = 4000
=> 20x = 4000
Therefore, x = 200.
So, y = (5/2) * 200 = 500.
Hence, the cost of 12 chairs and 3 tables = 12x + 3y
= Rs. (2400 + 1500)
= Rs. 3900.
Ques4. If a - b = 3 and a2 + b2 = 29, find the value of ab.
A. 10
B. 12
C. 15
D. 18
Answer: Option A
Explanation:
2ab = (a2 + b2) - (a - b)2
= 29 - 9 = 20
=> ab = 10.
Ques5. The price of 2 sarees and 4 shirts is Rs. 1600. With the same money one can buy 1 saree and 6 shirts. If one wants to buy 12 shirts, how much shall he have to pay ?
A. Rs. 1200
B. Rs. 2400
C. Rs. 4800
D. Cannot be determined
E. None of these
View Answer
Answer: Option B
Explanation:
Let the price of a saree and a shirt be Rs. x and Rs. y respectively.
Then, 2x + 4y = 1600 .... (i)
and x + 6y = 1600 .... (ii)
Divide equation (i) by 2, we get the below equation.
=> x + 2y = 800. --- (iii)
Now subtract (iii) from (ii)
x + 6y = 1600 (-)
x + 2y = 800
----------------
4y = 800
----------------
Therefore, y = 200.
Now apply value of y in (iii)
=> x + 2 x 200 = 800
=> x + 400 = 800
Therefore x = 400
Solving (i) and (ii) we get x = 400, y = 200.
Therefore, Cost of 12 shirts = Rs. (12 x 200) = Rs. 2400.
Example 6: 64 × 99
Solution 6:
⇒Step 1: 64 – 1 = 63
⇒Step 2: Complement of 64 = 100 – 64 = 36
Ans: 6336.
Example 7: 678 × 999 = ?
Solution 7:
⇒Step 1: 678 – 1 = 677
⇒Step 2: Compliment of 678 = 1000 – 678 = 322
Ans: 677322.
Example 8: 78 × 999 = ?
Solution 8: Take 78 as 078 and solve normally.
⇒Step 1: 078 – 1 = 077
⇒Step 2: Compliment of 078 = 1000 – 078 = 922
Ans: 77922
Example 9: Square of number 988?
Solution 9: Nearest best to 988 = 1000. 988 is less than 100 by 12
⇒Step 1: Subtract 988 by 12 = 988 – 12 = 976.
⇒Step 2: Square of 12 = 144 (Number of digits should be equal to number of zeros in base)
Ans: 976144
Example 10: Square of number 102?
Solution: Nearest best to 102 = 100. 102 is more than 100 by 2
⇒Step 1: Add 102 by 2 = 102 + 2 = 104.
⇒Step 2: Square of 2 = 04 (Number of digits should be equal to number of zeros in base)
Ans: 10404.
296 videos|297 docs|179 tests
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1. What are the basic rules of simplification? |
2. How can one effectively crack approximation questions in exams? |
3. What is the difference between simplification and approximation? |
4. What are some tips for mastering simplification and approximation for exams? |
5. How important are simplification and approximation skills in competitive exams? |
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