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Periodic Trends in Properties of Elements

Effective Nuclear Charge

  • Between the outer most valence electrons and the nucleus of an atom, there exists finite number of shells containing electrons. 
  • Due to the presence of these intervening electrons, the valence electrons are unable to experience the attractive pull of the actual number of protons in the nucleus. 
  • These intervening electrons act as shield between the valence electrons and protons in the nucleus. 
  • Thus, the presence of intervening (shielding) electrons reduces the electrostatic attraction between the protons in the nucleus and the valence electrons because intervening electrons repel the valence electrons. 
  • The concept of effective nuclear charge allows us to account for the effects of shielding on periodic properties.
  • The effective nuclear charge (Zeff) is the charge felt by the valence electron. Zeff is given by Zeff = Z - s. Where Z is the actual nuclear charge (atomic number of the element) and s is the shielding (screening) constant.
Effective Nuclear Charge

Atomic Radius

An atom has no sharp boundary because the probability of finding an electron never becomes exactly zero at any finite distance. Therefore atomic radius is an operational or effective size - typically defined as the distance of closest approach between nuclei in bonded or nearest-neighbour atoms. Several radii are used depending on the context.

(A) Covalent Radius

(A) Covalent Radius

The covalent radius (for a single bond) is one-half of the distance between the centres of two identical atoms joined by a single covalent bond. Covalent radii are most useful for non-metals and are commonly used to estimate bond lengths.

For homoatomic diatomic molecules,

(A) Covalent Radius(A) Covalent Radius

For near-homonuclear (heterodiatomic with similar electronegativities),

(A) Covalent Radius

For heteronuclear diatomic molecules with a significant electronegativity difference, Stevenson and Schomaker gave an empirical correction:

(A) Covalent Radius

where XA and XB are electronegativities of atoms A and B respectively.

Example . Calculate the bond length of C-X bond, if C-C bond length is 1.54 Å, X-X bond length is 1.00 Å and electronegativity values of C and X are 2.0 and 3.0 respectively.

Sol.
C-C bond length = 1.54 Å
rC = 1.54/2 = 0.77 Å
rX = 1.00/2 = 0.50 Å
Using the Stevenson-Schomaker correction,

dC-X = rC + rX - 0.09 (XX - XC)

dC-X = 0.77 + 0.50 - 0.09(3 - 2) = 1.27 - 0.09 = 1.18 Å

Thus the C-X bond length is 1.18 Å.

(B) van der Waals Radius (Collision Radius)

(B) van der Waals Radius (Collision Radius)

The van der Waals radius is one-half of the internuclear distance between two non-bonded adjacent atoms in neighbouring molecules in the condensed phase (usually solid or liquid). It describes how close two atoms can approach when they are not chemically bonded.

van der Waals radii depend on how atoms are packed in the solid state and are not applicable to metallic bonding.

Comparison between covalent and van der Waals radii:

  • van der Waals interactions are weak and the internuclear distances between non-bonded atoms are generally larger than those in covalently bonded atoms; therefore van der Waals radii are larger than covalent radii.
  • Covalent bonding involves orbital overlap that brings nuclei closer together, so covalent radii are smaller.
ElementHOFSBr
Covalent radius (Å)0.370.660.641.041.11
van der Waals radius (Å)1.201.401.351.851.95

(C) Metallic Radius (Crystal Radius)

(C) Metallic Radius (Crystal Radius)

The metallic radius is one-half of the distance between the nuclei of two adjacent metal atoms in a metallic crystal lattice. Metallic radii are usually larger than covalent radii because metallic bonding is delocalised and generally weaker than covalent bonding, producing longer internuclear distances.

For example :  

MetalMetallic radius (pm)Covalent radius (pm)
K231203
Na186154
(C) Metallic Radius (Crystal Radius)
(C) Metallic Radius (Crystal Radius)(C) Metallic Radius (Crystal Radius)

Variation In a Period

Variation In a Group

In a period left to right:

In a group top to bottom :

Z increases by one unit

Z increases by more than one unit

Zeff. also increases

Zeff. almost remains constant (due to increased screening effect of inner shells electrons)

n remains constant (no of orbits)

n increases (no. of orbits)

As a result of these electrons are pulled close to the nucleus by the increased Zeff.

rn ∝ 1/Z* 

Thus atomic radii decreases with increase in atomic number in a period from left to right

The effect of increased number of atomic shells overweigh the effect of increased screening effect.
As a result of this the size of atom increases from top to bottom in a given group.

  • The atomic radius of noble (inert) gases is usually given as the van der Waals radius (largest in a period) since they exist as monoatomic species; their van der Waals radii increase down the group.
(C) Metallic Radius (Crystal Radius)
  • In the first transition series, covalent radii generally decrease across the series because Z increases while the added d-electrons do not shield the nuclear charge effectively; near the end there may be slight increases. Radii of Cr to Cu are very similar due to progressive addition of d-electrons which screen the 4s electrons.
(C) Metallic Radius (Crystal Radius)
  • The lanthanide contraction is the steady decrease of ionic and atomic radii across the lanthanide series (4f-electron filling). It reduces the expected size increase between transition metals of successive periods; for example, covalent and ionic radii of Nb (5th period) and Ta (6th period) are almost the same because f-electrons provide poor shielding.

Ionic Radius

The ionic radius is the effective distance from the nucleus of an ion up to which it has an influence in an ionic bond. Ionic radii depend on the charge and the electron configuration of the ion.

Cation

Anion

It is formed by the toss of one or more electrons from the valence shell of an atom of an element.
Cations are smaller than the parent atoms because
(1) The whole of the outer shell of electrons is usually removed.

(ii) In a Cation, the number

It is formed by the gain of one or more electrons In the valence shell of an atom of an element.

Anions are larger than the parent atoms because (1) Anion Is formed by gain of one or more electrons in the neutral atom and thus number of electron

Example: Na and Cl


NaNa+
Number of protons1111
Electronic configuration1s2 2s2p6 3s1
1s22s2 2p6

Cl
Cl
Number of electrons1718
Number of protons1717
  • Ionic sizes increase down a group for ions of the same charge 
    Li< Na+ < K+ < Rb+ Be2+ < Mg2+ < Ca2+ < Sr2+ F- < Cl- < Br- < I
  • d and f orbitals shield nuclear charge poorly. As a result, sizes drop unexpectedly for elements just after filling d or f shells; this contributes to lanthanide contraction (e.g., Zr and Hf have nearly identical radii).
  • Isoelectronic species are ions/atoms with the same number of electrons but different nuclear charges. For example N3- , O2-, F-, Ne, Na+ , Mg2+ and Al3+ all have 10 electrons. Within an isoelectronic series, ionic radius decreases as nuclear charge increases (greater attraction pulls electrons closer).
Ionic Radius
Ionic Radius
  • Pauling's empirical formula for ionic radius is given in the input as an illustrative relation.Ionic Radius
  • Examples of isoelectronic series: (i) S2- Cl- KCa+2 Sc+3   (ii) SO2,  NO3-, CO32-   (iii) N2, CO,  CN-      (iv) NH3, H3O-

Ionisation Enthalpy (Ionisation Energy)

Ionisation enthalpy (IE) or ionisation energy is the energy required to remove an electron from an isolated gaseous atom (or ion) to form a cation. For successive removals we have first ionisation enthalpy IE1, second IE2, third IE3, etc.

General trend: IE1 < IE2 < IE3 ... because as electrons are removed the remaining electrons are held more strongly by the nucleus.

Ionisation Enthalpy (Ionisation Energy)
  • Units of ionisation energy: kJ mol-1, kcal mol-1, or eV per atom (1 eV = 96.485 kJ mol-1 approximately, or for energy comparisons 1 eV ≈ 23.06 kcal mol-1 is used in examples).
  • Factors influencing ionisation energy:
  • Atomic size: IE decreases as atomic size increases because valence electrons are farther from the nucleus and less strongly held.
  • Nuclear charge: IE increases with increasing nuclear charge (more protons attract electrons more strongly).
  • Shielding effect: Inner electrons screen valence electrons from nuclear charge; increased shielding lowers IE.Ionisation Enthalpy (Ionisation Energy)
  • Penetration: Electrons in orbitals with better penetration (s > p > d > f) are held more tightly; for orbitals of the same principal quantum number IE increases with penetration.
  • Electronic configuration: Atoms with fully filled or half-filled subshells have extra stability; IE values may be higher than expected (e.g., Be IE1 > B IE1 because Be has 2s2 configuration).
    Ionisation Enthalpy (Ionisation Energy)Ionisation Enthalpy (Ionisation Energy)

As noble gases have completely filled electronic configuration, they have highest ionisation energies in their respective periods.

  Ionisation Enthalpy (Ionisation Energy)

Ionisation Enthalpy (Ionisation Energy)

Ionisation Enthalpy (Ionisation Energy)
Ionisation Enthalpy (Ionisation Energy)

Elements with high ionisation energies are less electropositive (less metallic); decreasing IE corresponds to increasing metallic (electropositive) character, greater reducing power and higher chemical reactivity for metals (exceptions exist, e.g., Li among alkali metals).

Example 3. First and second ionisation energies of Mg(g) are 740 and 1450 kJ mol-1. Calculate percentage of Mg+ (g) and Mg2+ (g), if 1 g of Mg(g) absorbs 50 kJ of energy.

Sol.

Sol. Number of moles of 1g of Mg =  1/24 = 0.0417

Energy required to convert Mg(g) to Mg+(g) = 0.0417 x 740 = 30.83 kJ
Remaining energy = 50 - 30.83 = 19.17 kJ
Number of moles of Mg2+ formed =  17.19/1450 = 0.0132

Thus, remaining Mg+ will be = 0.0417 -  0.0132 = 0.0285

% Mg+ = (0.0285/ 0.0417) × 100 = 68.35%

% Mg+ = 100 - 68.35 = 31.65%

Electron Gain Enthalpy (Electron Affinity)

Electron gain enthalpy (electron affinity, EA) is the enthalpy change when an electron is added to a neutral gaseous atom to form an anion. It measures the ease with which an atom accepts an electron.

Electron Gain Enthalpy (Electron Affinity)
Electron Gain Enthalpy (Electron Affinity)

Electron addition may be exothermic (negative EA) or endothermic (positive EA). The addition of a second electron to a singly charged anion is usually endothermic due to electrostatic repulsion.

Electron Gain Enthalpy (Electron Affinity)

EA(i) (first electron gain) is typically exothermic, but EA(ii) (second electron gain) is endothermic for most atoms.

  • Group 17 elements (halogens) have large negative electron gain enthalpies because they achieve noble gas configuration by gaining one electron.
  • Noble gases have large positive (or less negative) electron gain enthalpies because the incoming electron must occupy a new shell.
  • O and F have less negative EA than S and Cl respectively because in the n = 2 shell added electrons experience stronger electron-electron repulsion in the smaller volume.
  • Alkaline earth metals have small or positive electron gain enthalpies as the extra electron must enter a filled s-orbital.
  • Across a period left to right EA generally becomes more negative (higher tendency to gain electrons) due to increasing Zeff. Down a group EA becomes less negative (weaker tendency) because added electron would be farther from nucleus.
  • (i) Electron affinity Electron Gain Enthalpy (Electron Affinity)

    (ii) Electron affinity ∞ Effective nuclear charge (zeff)

    (iii) Electron affinityElectron Gain Enthalpy (Electron Affinity)

Key relations noted in the input:

  • Electron affinity correlates with effective nuclear charge Zeff.
  • Stability of half-filled and completely filled subshells lowers the tendency to accept an extra electron; EA values may be less negative in those cases.

Example 4. How many Cl atoms can you ionise in the process [reaction shown in image] if the energy liberated for the process [image] for one Avogadro number of atoms. Given IP = 13.0 eV and EA = 3.60 eV.

Sol.
Let n atoms be ionised. 6.02 × 1023 × EA = n × IP

Electron Gain Enthalpy (Electron Affinity)

Example 5. The first ionisation potential of Li is 5.4 eV and the electron affinity of Cl is 3.6 eV. Calculate ΔH in kcal mol-1 for the reaction [image].

Sol.
The overall reaction is written into two partial equations Electron Gain Enthalpy (Electron Affinity)

= 1.8 × 23.06 kcal mol-1 = 41.508 kcal mol-1

Example 6. For the gaseous reaction [image] the value was calculated to be 19 kcal under conditions where cations and anions were prevented by electrostatic separation from combining with each other. The ionisation potential of K is 4.3 eV. What is the electron affinity of F?

Sol.

Electron Gain Enthalpy (Electron Affinity)
Electron Gain Enthalpy (Electron Affinity)

Example 7. The electron affinity of chlorine is 3.7 eV. How much energy in kcal is released when 2 g of chlorine is completely converted to Cl- ion in the gaseous state? (1 eV = 23.06 kcal mol-1)

Sol.

Electron Gain Enthalpy (Electron Affinity)
35.5 3.7 × 23.06 kcal

l .'. Energy released for conversion of 2 g gaseous chlorine into CI- ions

Electron Gain Enthalpy (Electron Affinity) × 2 = 4.8 kcal

Hydration Enthalpy

Hydration enthalpy (hydration energy) is the energy released when one mole of gaseous ions becomes surrounded by water molecules and forms hydrated ions in aqueous solution. It is an important component of solvation and helps determine solubility and reaction energetics in aqueous phase.

  • Hydration enthalpy is proportional to the charge density of the ion: smaller ions with higher charge have larger (more negative) hydration enthalpies.
  • Hydration enthalpy decreases down a group because ionic size increases, reducing ion-water interactions.
  • For example, Mg2+ has a higher hydration enthalpy than Na+ because Mg2+ has higher charge density.
  • Hydration process is exothermic; large hydration enthalpies stabilise solvated ions and affect solubility trends (e.g., solubility of Group 2 hydroxides changes down the group because lattice enthalpy and hydration enthalpy change at different rates).

Note: Hydration enthalpy decreases down the group because ions become larger and their charge density decreases; lattice enthalpy often decreases faster (due to r-1 dependence in many lattice energy approximations), so overall solubility trends result from the balance between lattice and hydration enthalpies.

Lattice Enthalpy

Lattice enthalpy is the energy associated with formation of one mole of an ionic solid from its gaseous ions. It is a measure of the strength of the ionic lattice and strongly influences melting point, hardness, solubility and other physical properties of ionic compounds.

  • Lattice enthalpy is large and exothermic when oppositely charged ions are brought together to form a crystal; its magnitude depends on the charges and sizes of the ions and on the crystal structure.
  • High lattice enthalpy generally means low solubility and high melting point; the competition between lattice enthalpy and hydration enthalpy determines solubility in water.

Electronegativity

Electronegativity is the tendency of an atom (in a bonded molecule) to attract shared electrons towards itself. It is a dimensionless quantity and cannot be measured directly; several scales have been proposed to quantify it.

Electronegativity

The magnitude of electronegativity depends on ionisation potential and electron affinity; higher IE and more negative EA typically indicate higher electronegativity.

  • Electronegativity generally decreases with increasing atomic size (the valence electrons are farther from the nucleus).
  • Electronegativity generally increases with increasing effective nuclear charge and with increasing oxidation state (higher positive charge on an atom increases its polarising power and electronegativity).
Electronegativity
Electronegativity
Electronegativity

No single direct experimental method exists to determine electronegativity; common scales are:

(a) Pauling Scale

Linus Pauling introduced a semi-empirical scale based on bond dissociation energies. The difference in Pauling electronegativities is related to extra stabilization (ionic character) in an A-B bond compared to the average of A-A and B-B bonds.

Electronegativity
Electronegativity

(b) Mulliken Scale

Mulliken proposed that electronegativity can be taken as the arithmetic mean of ionisation energy (IE) and electron affinity (EA):

Electronegativity

When IE and EA are in electron-volts, Mulliken values may be converted to the Pauling scale by an empirical factor (Mulliken values are larger numerically by a factor ≈ 2.8 compared to Pauling values).

(c) Allred-Rochow Scale

Allred and Rochow defined electronegativity as the electrostatic force exerted by the nucleus on valence electrons, proportional to effective nuclear charge divided by the square of an appropriate radius:

Electronegativity

where Zeffective is the effective nuclear charge and r is the covalent radius (in Å).

  • Francium (Fr) has a slightly higher effective nuclear charge compared to cesium (Cs), resulting in subtle differences in some scales; however, both are among the least electronegative elements.
  • Noble gases (in their ground state, isolated atoms) are often assigned zero electronegativity in Pauling terminology since electronegativity is primarily a property of bonded atoms.

Example 8. Ionisation potential and electron affinity of fluorine are 17.42 eV and 3.45 eV respectively. Calculate the electronegativity of fluorine according to Mulliken.

Sol.

Electronegativity

When both IP and EA are taken in eV, Mulliken electronegativity = (IP + EA) / 2.

Electronegativity

Applications of Electronegativity

(I) Nomenclature. In binary compounds of two non-metals, the more electronegative element is named last with the suffix -ide. The less electronegative element is named first.

Example 9. Write correct formula and name of the following:

(a) ICl or ClI (b) FCl or ClF (c) BrCl or ClBr (d) BrI or IBr (e) OF2 or F2O (f) Cl2O or OCl2

Sol.
(a) ICl : Iodine chloride (I+ Cl-)
(b) ClF : Chlorine fluoride (Cl+ F-)
(c) BrCl : Bromine chloride (Br+ Cl-)
(d) IBr : Iodine bromide
(e) OF2 : Oxygen difluoride (oxygen is less electronegative than fluorine so O is written first)
(f) Cl2O : Dichlorine monoxide

(II) Nature of bond. If the difference of electronegativities is ≳ 1.7 (Pauling criterion) the bond is largely ionic; if the difference is less, the bond is largely covalent. (HF is an exception: although Δχ ≈ 1.9, the bond is largely covalent.)

(III) Metallic and nonmetallic character. Metals have low electronegativity; nonmetals have high electronegativity.

(IV) Partial ionic character in covalent bonds. Difference in electronegativities produces partial ionic character. Hanni and Smith provided an empirical relation to estimate percentage ionic character from Δχ.

Percentage ionic character =

Applications of Electronegativity
Applications of Electronegativity

where Δ = XA - XB, with X being electronegativity values.

(V) Bond length. Increasing difference of electronegativities generally shortens bond length due to increased bond polarity (Shoemaker and Stephenson equation referenced in the input).Applications of Electronegativity

(VI) Bond strength and stability. Bond strength A-B increases with increasing difference of electronegativities; for example, H-F > H-Cl > H-Br > H-I.

Example 10. Electronegativity is highest for which?
(1) -CH3(sp3)
(2) H2C = CH2(sp2)  
 (3) CH ≡ CH(sp)
 (4) Equal in all 

Ans. (3)

Ex.11 CF3NH2 is not a base, whereas CH3NHis a base. What is the reason ?

Sol. Fluorine atoms are strongly electronegative and withdraw electron density from nitrogen through inductive effect, reducing availability of the lone pair on N for protonation; hence CF3NH2 is a much weaker base than CH3NH2.

Example 12. OF2 is called oxygen difluoride, whereas Cl2O is called dichlorine monoxide. Why?

Sol. In OF2, fluorine is more electronegative than oxygen, so O carries positive character and is written first. In Cl2O, oxygen is more electronegative than chlorine, so Cl appears first as positive centres and O last as negative centre.

Example 13. Calculate electronegativity of fluorine from the following data:
EH - H = 104.2 kcal mol-1,
EF-F = 36.6 kcal mol-1
EH-F = 134.6 kcal mol-1,
X= 2.1 

Sol.
Using Pauling's equation relating bond energies,

Applications of Electronegativity

Applications of Electronegativity

Example 14 (repeat of Ex.7 in input). The electron affinity of chlorine is 3.7 eV. How much energy in kcal is released when 2 g of chlorine is completely converted to Cl- ion in a gaseous state? (1 eV = 23.06 kcal mol-1)

Sol.

Applications of Electronegativity

35.5 3.7 × 23.06 kcal

∴ Energy released for conversion of 2 g gaseous chlorine into Cl- ions

Applications of Electronegativity × 2 = 4.8 kcal

Example 15 (Pauling repeat). Calculate electronegativity of fluorine from: EH-H = 104.2 kcal mol-1, 
EF-F = 36.6 kcal mol-1, 
EH-F = 134.6 kcal mol-1, 
XH = 2.05.

Sol.

Applications of Electronegativity

Applications of Electronegativity

From (i)

Applications of Electronegativity = = 1.5534

xF = x+ 1.4434 = 2.05 + 1.5534 = 3.6034

METALLIC PROPERTY

Metals tend to lose electrons to form cations; this electropositive tendency defines their metallic character. Trends in metallic character follow ionisation energy and atomic size: metallic character increases where ionisation energy is low and size is large.

METALLIC PROPERTY
METALLIC PROPERTY
METALLIC PROPERTY
METALLIC PROPERTY

Oxides

Oxygen reacts with most elements (exceptions: noble gases and some noble metals like Au, Pd, Pt under ordinary conditions) to form oxides. Oxides vary in bonding and properties according to the element:

  • Metallic oxides (e.g., most Group 1 and 2 oxides) are ionic (O2-) and are basic; many dissolve in water to form hydroxides.
  • Peroxides (contain O22-, e.g., Na2O2) and superoxides (contain O2-, e.g., KO2) are formed by heavier alkali metals under certain conditions.
  • Oxides of non-metals are usually covalent and acidic (e.g., CO2, SO3, P4O10), producing acids on reaction with water.

The tendency of Group 1 (alkali) metals to form oxygen-rich compounds (peroxides, superoxides) increases down the group due to increasing cation radius and decreasing charge density. In Group 2, heavier members (Ca, Sr, Ba) form peroxides under appropriate conditions (Be does not).

Oxides of IA and IIA dissolve in water forming basic solution where as other oxides do not dissolve in water.

Oxides

Oxygen combines with many non-metals to form covalent oxides such as CO, CO2, SO2, P4O10, Cl2O7 etc.

Examples of nonmetal oxide hydrolysis:

P4O10 + 6H2O → 4H3 PO4 ;
SO3 + H2O → H2SO4 : Cl2O7 + H2O → 2HClO4

  • Across a period the nature of oxides changes from basic (left) → amphoteric (middle) → acidic (right).
  • Down a group oxides become more basic (or less acidic).
  • Metalloids often form amphoteric oxides (e.g., Al2O3, ZnO, SnO)

Na2O

MgO

Al2O3

SiO2

P4O10

SO3 

Cl2O7

Strongly
Acidic      

basic

Basic

amphoteric

 Weakly Acidic    

acidic              

Acidic

 Strongly acidic CO, N2O, NO and H2O are neutral oxides.

Oxidation State (Valency)

Oxidation state (or valency in simple contexts) is the formal charge that an atom would have if all bonds were considered completely ionic. It can be inferred from electronic configuration or by counting electrons in the valence shell.

Oxidation State (Valency)
  • Valence electrons are those in the outermost shell and largely determine typical valency.
  • For s- and p-block elements, valency is often equal to the number of valence electrons or 8 minus that number (in simple compounds).
  • For d- and f-block elements, valency involves outer s and inner d (and sometimes f) electrons; common oxidation states are +2 and +3 for many transition metals.
Oxidation State (Valency)

Variation of Oxidation State within a Period

Across a period left to right the number of valence electrons increases from 1 to 8. When elements combine with hydrogen or oxygen, oxidation states vary; for example, in Na2O oxygen is -2 and Na is +1, whereas in F2O oxygen is +2 and fluorine is -1 because fluorine is more electronegative than oxygen.

Variation of Oxidation State within a Group

Down a group the number of valence electrons remains the same so elements of a group commonly show similar valences (e.g., alkali metals are typically +1, alkaline earths +2).

Guidelines for Assigning Oxidation States

  • Oxidation state of an element in its elemental form (H2, O2, N2, P4, S8, Fe(s), etc.) is zero.
  • Oxygen is usually -2; in peroxides (e.g., H2O2, Na2O2) oxygen is -1; in superoxides O2- per oxygen average is -½ per O atom.
  • Hydrogen is usually +1 but is -1 in metal hydrides (e.g., NaH, LiH).
  • Halogens are usually -1 when combined with less electronegative elements, except when bonded to oxygen or other halogens where higher positive oxidation states are possible.
  • Alkali metals are +1; alkaline earth metals are +2 in their common compounds.

Anomalous Periodic Properties of Second Period Elements

The elements of the second period (Li, Be, B, C, N, O, F) show several anomalous properties compared with the heavier elements of the same groups. These anomalies arise mainly from small size, high electronegativity and absence of inner d/f orbitals.

Anomalous Periodic Properties of Second Period Elements

Observed anomalies and reasons:

  • Small atomic/ionic sizes, leading to higher polarising power and stronger covalent bonding tendencies (e.g., Li and Be form covalent compounds more readily than heavier group mates).
  • High electronegativity compared with heavier congeners.
  • Large charge/radius ratio (high polarising ability) causes greater covalency and formation of compounds with significant covalent character.
  • Limited availability of orbitals for bonding: second-period elements use only 2s and 2p orbitals (four valence orbitals), whereas third-period elements can utilize 3d in addition to 3s and 3p, allowing higher coordination numbers and higher oxidation states (e.g., Al vs B in fluoride complexes: [BF4]- vs [AlF6]3-).
  • Diagonal relationships: second-period elements may resemble the next heavier element of the next group (e.g., Li ≈ Mg, Be ≈ Al) in some properties because of compensating effects of charge/radius and electronegativity.
The document Periodic Trends in Properties of Elements is a part of the NEET Course Chemistry Class 11.
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FAQs on Periodic Trends in Properties of Elements

1. What is the effective nuclear charge and how does it impact the physical properties of elements?
Ans. The effective nuclear charge is the net positive charge experienced by an electron in a multi-electron atom. It affects the atomic radius, ionization energy, electron affinity, and electronegativity of an element.
2. How does the atomic radius change as you move across a period in the periodic table?
Ans. The atomic radius decreases as you move across a period from left to right due to the increasing effective nuclear charge, which pulls the electrons closer to the nucleus.
3. What is the trend in ionization energy as you move down a group in the periodic table?
Ans. Ionization energy decreases as you move down a group in the periodic table due to the increasing atomic size and shielding effect, which makes it easier to remove an electron.
4. How does electronegativity vary across a period in the periodic table?
Ans. Electronegativity tends to increase across a period from left to right due to the increasing effective nuclear charge, which attracts electrons more strongly.
5. Why do elements within a group in the periodic table have similar chemical properties?
Ans. Elements within a group have similar chemical properties because they have the same number of valence electrons, leading to similar reactivity and ability to form similar types of compounds.
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