Test: MCQs (One or More Correct Option): Chemical Bonding & Molecular Structure | JEE Advanced - JEE MCQ

 CO₂, HgCl₂ and C₂H₂ have linear structure (sp hybridization), while SnCl₂ is trigonal planar (sp² hybridisation). NO₂ has angular structure (V-shape).

[O = N = O]⁺; [N ≡ C – O]^–; S = C = S
It can be seen from the structure shown above that CS₂ being sp hybridized has a linear shape and other two molecules are isoelectronic to CS₂, so they are also linear. SnCl₂ and SO₂ are sp² hybridised and are not linear.

The outer most shells of C, N & O has 4, 5 and 6 electrons respectively. Thus CN^– and NO⁺ each has 10 electrons to accommodate in the molecular orbitals.
So their bond order is same. O^-₂ has 13 and CN⁺ has 12 electrons in outermost orbits.

So, (b) and (c).

(A) The molecular orbital energy configuration of C₂^2– is

In the MO of C₂^2– there is no unpaired electron hence it is diamagnetic

(B) Bond order of O₂²⁺ is 3 and O₂ is 2 therefore bond length of O₂ is greater than O₂²⁺

(C) The molecular orbital energy configuration of N⁺₂ is

Bond order of 

The molecular orbital energy configuration of N^–₂ is

Bond order of 

(D) He⁺₂ has less energy in comparison to two isolated He atoms because some energy is released during the formation of He⁺₂ from 2 He atoms.