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Test: Comprehension Based Questions: States of Matter - JEE MCQ


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2 Questions MCQ Test - Test: Comprehension Based Questions: States of Matter

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Test: Comprehension Based Questions: States of Matter - Question 1

X and Y are two volatile liquids with molar weights of 10 g mol–1 and 40 g mol–1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure.  The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is first
observed at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.

Q. The value of d in cm (shown in the figure), as estimated from Graham’s law, is    (JEE Adv. 2014)

Detailed Solution for Test: Comprehension Based Questions: States of Matter - Question 1

According to Graham’s law of diffusion, if all conditions are identical,

As in this question, all conditions are identical for X and Y, then

⇒   d = 48 – 2d   ⇒   3d = 48 ⇒   d = 16 cm

Test: Comprehension Based Questions: States of Matter - Question 2

X and Y are two volatile liquids with molar weights of 10 g mol–1 and 40 g mol–1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure.  The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is first
observed at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.

Q. The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is due to (JEE Adv. 2014)

Detailed Solution for Test: Comprehension Based Questions: States of Matter - Question 2

The general formula of mean free path (λ) is

(d = diameter of molecule, p = pressure inside the vessel) Since d and p are same for both gases, ideally their l are same. Hence it must be the higher drift speed of X due to which it is facing more collisions per second with the inert gas in comparison to gas Y. Hence X faces more resistance from inert gas than Y and hence covers lesser distance than that predicted by Graham’s law.

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