JEE Exam  >  JEE Test  >  Chapter-wise Tests Main & Advanced  >  Test: JEE Main 35 Year PYQs- States of Matter - JEE MCQ

JEE Main 35 Year PYQs- States of Matter Free MCQ Practice Test [Updated]


MCQ Practice Test & Solutions: Test: JEE Main 35 Year PYQs- States of Matter (15 Questions)

You can prepare effectively for JEE Chapter-wise Tests for JEE Main & Advanced with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: JEE Main 35 Year PYQs- States of Matter". These 15 questions have been designed by the experts with the latest curriculum of JEE 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 30 minutes
  • - Number of Questions: 15

Sign up on EduRev for free to attempt this test and track your preparation progress.

Test: JEE Main 35 Year PYQs- States of Matter - Question 1

For an ideal gas, number of moles per litre in terms of its pressure P, gas constant R and temperature T is

Detailed Solution: Question 1

PV = nRT (number of moles = n/V) ∴ n/V = P/RT..

Test: JEE Main 35 Year PYQs- States of Matter - Question 2

Value of gas constant R is [2002]

Detailed Solution: Question 2

Value of gas constant ( R ) = 0.0821L atm K–1 mol–1          
= 8.314 × 107 ergs K–1mol–1          
= 8.314JK–1mol–1  = 1.987 cal K–1 mol–1

Test: JEE Main 35 Year PYQs- States of Matter - Question 3

Kinetic theory of gases proves [2002]

Detailed Solution: Question 3

Kinetic theory of gases proves all the given gas laws.

Test: JEE Main 35 Year PYQs- States of Matter - Question 4

According to the kinetic theory of gases, in an ideal gas, between two successive collisions a gas molecule travels

Detailed Solution: Question 4

ln between two successive collisions, no force is acting on the gas molecules. Resultantly they travel with uniform velocity during this interval and hence, moves along a straight line.

Test: JEE Main 35 Year PYQs- States of Matter - Question 5

As the temperature is raised from 20ºC to 40ºC, the average kinetic energy of neon atoms changes by a factor of which of the following ? [2004]

Detailed Solution: Question 5

Test: JEE Main 35 Year PYQs- States of Matter - Question 6

In van der Waals equation of state of the gas law, the constant ‘b’ is a measure of [2004]

Detailed Solution: Question 6

In van der waals  equation ‘b’ is for volume correction

Test: JEE Main 35 Year PYQs- States of Matter - Question 7

Which one of the following statements is NOT true about the effect of an increase in temperature on the distribution of molecular speeds in a gas? [2005]

Detailed Solution: Question 7

Distribution of molecular velocities at two different temperature is given shown below.

NOTE : At higher temperature more molecules have higher velocities and less molecules have lower velocities.
As  evident from fig. thus it is clear that With the increase in temperature the most probable velocity increase butthe fraction of such molecules decreases.

Test: JEE Main 35 Year PYQs- States of Matter - Question 8

If 10–4 dm3 of water is introduced into a 1.0 dm3 flask at 300 K, how many moles of water are in the vapour phase when equilibrium is established ? [2010]

(Given : Vapour pressure of H2O at 300 K is 3170 Pa; R = 8.314 J K–1 mol–1)

Detailed Solution: Question 8

From the ideal gas equation :

PV = nRT or n =  = 1.27 × 10–3

Test: JEE Main 35 Year PYQs- States of Matter - Question 9

‘a’ and ‘b’ are van der Waals’ constants for gases. Chlorine is more easily liquefied than ethane because [2011]

Detailed Solution: Question 9

The value of a is a measure of the magnitude of the attractive forces between the molecules of the gas.
Greater the  value of ‘a’, larger is the attractive intermolecular force between the gas molecules.
The value of b related to the effective size of the gas molecules. It is also termed as excluded volume.
The gases with higher value of a and lower value of b are more liquefiable, hence for Cl2 “a” should be greater than for C2H6 but for it b should be less than for C2H6.

Test: JEE Main 35 Year PYQs- States of Matter - Question 10

The compressibility factor for a real gas at high pressure is :  [2012]

Detailed Solution: Question 10

 = RT at high pressure  can be

neglected

PV – Pb = RT    and  PV = RT + Pb

Z > 1 at high pressure

Test: JEE Main 35 Year PYQs- States of Matter - Question 11

For gaseous state, if most probable speed is denoted by C*, average speed by and mean square speed by C, then for a large number of molecules the ratios of these speeds are : [JEE M 2013]

Detailed Solution: Question 11

Most probable speed  

Average Speed 

Root mean square velocity (c)

 = 1 :1.128 : 1.225

Test: JEE Main 35 Year PYQs- States of Matter - Question 12

If Z is a compressibility factor, van der Waals equation at low pressure can be written as: [JEE M 2014]

Detailed Solution: Question 12

Compressibility factor (Z) = 

(For one mole of real gas) van der Waals equation

At low pressure, volume is very large and hence correction term b can be neglected in comparison to very large volume of V.

i.e. 

Hence, 

Test: JEE Main 35 Year PYQs- States of Matter - Question 13

The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1 : 4. The ratio of number of their molecule is: [JEE M 2014]

Detailed Solution: Question 13

Number of moles of O2

Number of moles of  

∴ Ratio =  = 7 : 32

Test: JEE Main 35 Year PYQs- States of Matter - Question 14

The intermolecular interaction that is dependent on the inverse cube of distance between the molecules is : [JEE M 2015]

Detailed Solution: Question 14

Hydrogen bond is a type of strong electrostatic dipole-dipole interaction and dependent on the inverse cube of distance between the molecular ion-dipole interaction

Test: JEE Main 35 Year PYQs- States of Matter - Question 15

Two closed bulbs of equal volume (V) containing an ideal gas initially at pressure pi and temperature T1 are connected through a narrow tube of negligible volume as shown in the figure below. The temperature of one of the bulbs is then raised to T2. The final pressure pf is : [JEE M 2016]

Detailed Solution: Question 15

For a given mass of an ideal gas, the volume and amount (moles) of the gas are directly proportional if the temperature and pressure are constant. i.e V ∝ n Hence in the given case.
Initial  moles  and  final  moles  are  equal (nT)i = (nT)f

446 docs|929 tests
Information about Test: JEE Main 35 Year PYQs- States of Matter Page
In this test you can find the Exam questions for Test: JEE Main 35 Year PYQs- States of Matter solved & explained in the simplest way possible. Besides giving Questions and answers for Test: JEE Main 35 Year PYQs- States of Matter, EduRev gives you an ample number of Online tests for practice
Download as PDF