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31 Year NEET Previous Questions: Motion in a Plane - 1 Free MCQ Practice


MCQ Practice Test & Solutions: 31 Year NEET Previous Year Questions: Motion in a Plane - 1 (31 Questions)

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Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 60 minutes
  • - Number of Questions: 31

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31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 1

A boat which has a speed of 5 km/hr in still water crosses a river of width 1 km along the shortest possible path in 15 minutes. The velocity of the river water in km/hr is [1998, 2000]

Detailed Solution: Question 1

Speed along the shortest path

 4 km/hr

Speed of water

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 2

A child is swinging a swing. Min imum and maximum heights of swing from earth’s surface are 0.75 m and 2m respectively. The maximum velocity of this swing is [2001]

Detailed Solution: Question 2

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 3

Two particles of mass M and m are moving in a circle of radii R and r. If their time-periods are same, what will be the ratio of their linear velocities? [2001]

Detailed Solution: Question 3

Linear velocity v = rω

[ω is same in both cases because time period is same]

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 4

The angle between the two vectors will be

Detailed Solution: Question 4

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 5

From a 10 m high building a stone 'A' is dropped, and simultaneously another identical stone 'B' is thrown horizontally with an initial speed of 5 ms–1. Which one of the following statements is true?[2002]

Detailed Solution: Question 5

h and g are same for both the balls, so time of fall ‘t’ will also be the same for both of them (h is vertical height]

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 6

A body of 3 kg moves in the XY plane under the action of a force given by .Assuming that the body is at rest at time t = 0, the velocity of the body at t = 3s is [2002]

Detailed Solution: Question 6

Given:

  • Mass of the body, m = 3 kg
  • Force acting on the body, F = (6t2 i + 4t j) N
  • Initial velocity at t = 0, v(0) = 0 (body is at rest)
  • Find velocity at t = 3 s

Step 1: Calculate acceleration

Using Newton's second law, F = m a, acceleration a is:

a = F / m = (6t2 i + 4t j) / 3 = 2t2 i + (4/3) t j

Step 2: Express acceleration as the derivative of velocity

a = dv/dt = 2t2 i + (4/3) t j

Step 3: Integrate acceleration to get velocity

Since the body starts from rest:

v = ∫ a dt = ∫ (2t2 i + (4/3) t j) dt = ∫ 2t2 dt i + ∫ (4/3) t dt j

Integrate each term:

  • ∫ 2t2 dt = (2)(t3/3) = (2/3) t3
  • ∫ (4/3) t dt = (4/3)(t2/2) = (2/3) t2

Therefore, velocity as a function of time is:

v = (2/3) t3 i + (2/3) t2 j + C

Since v(0) = 0, constant of integration C = 0.

Step 4: Calculate velocity at t = 3 s

v(3) = (2/3) (3)3 i + (2/3) (3)2 j = (2/3)(27) i + (2/3)(9) j = 18 i + 6 j

Final answer:
Velocity at t = 3 s is 18 i + 6 j.

This corresponds to option C.

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 7

The vector sum of two forces is perpendicular to their vector differences. In that case, the forces[2003]

Detailed Solution: Question 7

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 8

A particle moves along a circle of radius  with constant tangential acceleration. If the velocity of the particle is 80 m/s at the end of the second revolution after motion has begun, the tangential acceleration is [2003]

Detailed Solution: Question 8

Circumference

Distance travelled in 2 revolutions  = 2 × 40 = 80 m
Initial velocity = u = 0
Final velocity v = 80m/sec
Applying the formula, v2 = u2 + 2as
(80)2 = 02 + 2 × a × 80 ⇒ a = 40 m/sec2

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 9

If then the value of is 

Detailed Solution: Question 9

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 10

A stone is tied to a string of length ℓ and is whirled in a vertical circle with the other end of the string as the centre. At a certain instant of time, the stone is at its lowest position and has a speed u.
The magnitude of the change in velocity as it reaches a position where the string is horizontal (g being acceleration due to gravity) is [2004]

Detailed Solution: Question 10

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 11

If a vector is perpendicular to the vector then the value of α is  [2005]

Detailed Solution: Question 11

For two vectors to be perpendicular to each other

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 12

If the angle between the vectors  the value of the product is equal to [2005]

Detailed Solution: Question 12

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 13

Two boys are standing at the ends A and B of a ground where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity v1. The boy at A starts running simultaneously with velocity v and catches the oth er boy in a time t, where t is [2005]

Detailed Solution: Question 13

Velocity of A relative to B is given by

By taking x-components of equation (1), we get

By taking Y-components of equation (1), we get

.....(3)

Time taken by boy at A to catch the boy at B is given by

[From equation (1)]

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 14

A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]

Detailed Solution: Question 14

and direction along the radius towards the centre.

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 15

The cir cular motion of a particle with constant speed is [2005]

Detailed Solution: Question 15

In circular motion of a particle with constant speed,  particle repeats its motion after a regular interval of time but does not oscillate about a fixed point. So, motion of particle is periodic but not simple harmonic.

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 16

A car runs at a constant speed on a circular track of radius 100 m, taking 62.8 seconds in every circular loop. The average velocity and average speed for each circular loop respectively, is [2006]

Detailed Solution: Question 16

Distance covered in one circular loop = 2πr = 2 × 3.14 × 100 = 628 m

Speed 

Displacement in one circular loop = 0

Velocity 

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 17

For angles of projection of a projectile (45° – θ) and (45° + θ), the horizontal ranges described by the projectile are in the ratio of [2006]

Detailed Solution: Question 17

(45º – θ) & (45º + θ) are complementary angles as 45º – θ + 45º + θ = 90º. We know that if angle of projection of two projectiles make complementary angles, their ranges are equal.
In this case also, the range will be same. So the ratio is 1 : 1.

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 18

The vectors are such that  The angle between the two vectors is [1991, 1996, 2001, 2006]

Detailed Solution: Question 18

So, angle between A & B is 90º.

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 19

A particle starting from the origin (0, 0) moves in a straight line in the (x, y) plane. Its coordinates at a later time are . The path of the particle makes with the x-axis an angle of [2007]

Detailed Solution: Question 19

Let θ be the angle which the particle makes with x axis.
From figure, 

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 20

 are two vectors and θ is the angle between them, if , the valueof θ is[2007]

Detailed Solution: Question 20

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 21

Three forces acting on a body are shown in the figure. To have the resultant force only along the y- direction, the magnitude of the minimum additional force needed is: [2008]

Detailed Solution: Question 21

Th e componen ts of 1N and 2N forces along + x axis = 1 cos60° + 2 sin30°

The component of 4 N force along –x-axis

Therefore, if a force of 0.5N is applied along + x-axis, the resultant force along x-axis will become zero and the resultant force will be obtained only along y-axis.

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 22

A particle of mass m is projected with velocity v making an angle of 45° with the horizontal. When the particle lands on the level ground the magnitude of the change in its momentum will be: [2008]

Detailed Solution: Question 22

The magnitude of the resultant velocity at the point of projection and the landing point is same.

Clearly, change in momentum along horizontal (i.e along x-axis) = mvcosθ – mv cosθ = 0
Change in momentum along vertical (i.e. along y–axis) = mv sinθ – (–mv sinθ) = 2 mvsinθ = 2mv × sin 45°

Hence, resultant change in momentum

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 23

A block of mass m is in contact with the cart C as shown in the Figure. [2010]

The coefficient of static friction between the block and the cart is μ . The acceleration α of the cart that will prevent the block from falling satisfies:

Detailed Solution: Question 23

Forces acting on the block are as shown in the fig. Normal reaction N is  provided by the force mα due to acceleration α

∴ N = mα For the block not to fall, frictional force,

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 24

Six vectors, have the magnitudes and directions indicated in the figure. Which of the following statements is true? [2010]

Detailed Solution: Question 24

Using the law of vector addition, is as shown in the fig.

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 25

A particle moves in a circle of radius 5 cm with constant speed and time period 0.2πs. The acceleration of the particle is [2011]

Detailed Solution: Question 25

Centripetal acceleration ac = ω2r

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 26

A missile is fired for maximum range with an initial velocity of 20 m/s. If g = 10 m/s2, the range of the missile is 

Detailed Solution: Question 26

For maximum range, the angle of projection, θ = 45°.

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 27

A projectile is fired at an angle of 45° with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection is [2011M]

Detailed Solution: Question 27

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 28

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectiles is : [2012]

Detailed Solution: Question 28

Horizontal range

....(1)

Maximum height

....(2)

According to the problem   R = H

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 29

A particle ha s initial velocity and acceleration . The magnitude of velocity after 10 seconds will be : [2012] 

Detailed Solution: Question 29

31 Year NEET Previous Year Questions: Motion in a Plane - 1 - Question 30

The velocity of a projectile at the initial point A is m/s. It’s velocity (in m/s) at point B is [NEET 2013]

Detailed Solution: Question 30

At point B the direction of velocity component of the projectile along Y - axis reverses.

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