JEE Exam  >  JEE Tests  >  Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - JEE MCQ

Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - JEE MCQ


Test Description

30 Questions MCQ Test - Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced

Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced for JEE 2024 is part of JEE preparation. The Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced questions and answers have been prepared according to the JEE exam syllabus.The Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced below.
Solutions of Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced questions in English are available as part of our course for JEE & Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced | 38 questions in 80 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 1

The shortest wavelength of X-rays emitted from an X-ray tube depends on

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 1

Note : Shortest wavelength means highest frequency.
This means highest energy.
The energy of X-rays depends on the accelerating voltage provided in the X-ray tube.
Also, accordin g to Moseley’s law √n= a(Z –b) .
Thus the frequency also depends on the atomic number.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 2

The threshold wavelength for photoelectric emission from a material is 5200 Å. Photoelectrons will be emitted when this material is illuminated with monochromatic radiation from a

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 2

The threshold wavelength is 5200Å. For ejection of electrons, the wavelength of the light should be less than 5200 Å, so that frequency increases and hence the energy of incident photon increases. U.V light has less wavelength than 5200 Å.

1 Crore+ students have signed up on EduRev. Have you? Download the App
*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 3

From the following equations pick out the possible nuclear fusion reactions

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 3

Nuclear fusion occurs when two or more lighter nuclei combine to form a heavier nucleus with release of a huge amount of energy.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 4

In Bohr ’s model of the hydrogen atom

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 4

We know, rn ∝ n2

| P.E. | = 2 × | K.E. |

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 5

Select the correct statement from the following

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 5

A diode can be used as a rectifier.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 6

For a given plate voltage, the plate current in a triode valve is maximum when the potential of

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 6

is the correct option. The electrons emitted by emitter are collected to the maximum by the plate in this case.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 7

The X-ray beam coming from an X-ray tube will be

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 7

is the correct option.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 8

The mass number of a nucleus is

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 8

In the case of hydrogen, atomic number = mass number In the other atoms, atomic number < mass number.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 9

Four physical quantities are listed in Column I. Their values are listed in Column II in a random order:

The correct matching of Columns I and II is given by

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 10

Photoelectric effect suppor ts quantum nature of light because

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 11

During a negative beta decay

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 12

During a nuclear fusion reaction

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 13

The potential difference applied to an X-ray tube is increased. As a result, in the emitted radiation

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 14

A freshly prepared radioactive source of half life 2 hr emits radiation of intensity which  is 64 times the permissibe safe level. The minimum time after which it would be possible to work safely with this source is

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 14

Note:  The intensity of radiation emitted is proportional to the rate of decay which in turn is proportional to number of atoms left (radioactive).

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 15

The impurity atoms with which pure silicon should be doped to make a p-type semiconductor are those of 

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 15

Boron and Aluminium are trivalent impurities.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 16

Two identical p-n junctions may be connected in series with a battery in three ways, fig. The potential drops across the two p – n junctions are equal in

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 16

Since the p-n junction arrangement are in series, therefore the potential drop across a p-n junction will be proportional to their resistances. When the resistances will be equal, the potential drops will be equal. In circuit I, the two p-n junctions are attached such that one is forward biased (low resistance) and other is reverse biased (high resistance). Whereas in the other two circuits both are either forward biased or reversed biased.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 17

The decay constant of a radioactive sample is λ . The halflife and mean-life of the sample are respectively given by

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 17

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 18

When a monochromatic point source of light is at a distance of 0.2 m from a photoelectric cell, the cut off voltage and the saturation current are respectively 0.6 V and 18.0 mA. If the same source is placed 0.6 m away from the photoelectric cell, then

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 18

Since the stopping potential depends on the frequency and not on the intensity and the source is same, the stopping potential remains unaffected. The saturation current depends on the intensity of incident light on the cathode of the photocell which in turn depends on the distance of the source from cathode. The intensity (I) of light is inversely proportional to the square of the distance between the light source and photocell.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 19

In an n-p-n transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector,

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 19

Ic = 10 mA

90% of electrons emitted pr produce a collector current of 10 mA. The base current

Now, Ie = Ib + Ic = 1 + 10 = 11mA

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 20

A star initially has 1040 deuterons. It produces energy via the processes  and  If the average power radiated by the star is 1016 W, the deuteron supply of the star is exhausted in a time of the order of

The masses of the nuclei are as follows :

M (H2) = 2.014 amu;
M (p) = 1.007 amu; M(n) = 1.008 amu; M (He4) = 4.001amu.

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 20

1H2 + 1H21H3 + p
1H2 + 1H32He4 + n
Net Reaction 31H22He4 + p + n
Δm = 3 (2.014) – [4.001 + 1.007 + 1.008] = 0.026
3 deuterons release 3.87 × 10–12 J

= 1.29 × 1028J

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 21

When photons of energy 4.25 eV strike the surface of metal A, the ejected photoelectrons have maximum kinetic energy, TA eV and de Broglie wavelength λA. The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy 4.70 eV is TB = (TA- 1.50) eV. If the de Broglie wavelength of these photoelectrons is λB = 2λA, then

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 21

 For metal A

4.25 = WA + TA           ...(i)

For metal B

4.7 = (TA – 1.5) + WB ...(iii)

Dividing equation (iv) by (ii),

[∵ λ B = 2λA given]

⇒ 4TA – 6 =TA ⇒ TA = 2 eV
From (i), WA = 2.25 eV
From (iii), WB = 4.2 eV
Also TB = TA – 1.5 ⇒ TB = 0.5eV

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 22

Which of the following statement(s) is (are) correct?

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 23

Holes are charge carriers in

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 23

Holes are electron vacancies which participate in electrical conductivity. These are produced in semiconductors.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 24

A transistor is used in the common emitter mode as an amplifier. Then

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 24

The circuit for a p-n-p transistor used in the common emitter mode as an amplifier is shown in figure. The base emitter junction is forward-biased and the input signal is connected in series with the voltage applied to bias the base emitter junction.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 25

Let mp be the mass of a proton, mn the mass of a neutron, M1 the mass of a  nucleus and M2 the mass  of a  nucleus. Then

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 25

KEY CONCEPT : Due to mass defect (which is finally responsible for the binding energy of the nucleus), mass of a nucleus is always less than the sum of masses of its constituent particles.

is made up of 10 protons plus 10 neutrons.
Therefore, mass of  nucleus
M1 < 10 (mp + mn)
Note :
Heavier the nucleus, more is the mass defect.
20 (mn + mp) – M2 > 10 (mp + mn) – M1
Thus, 10 (mn + mp) > M2 – M1
or M2 < M1 + 10 (mp + mn)
Now, since M1 < 10 (mp + mn)
∴ M2 < 2M1

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 26

The electron in a hydrogen atom makes a transition n→ n2 where n1 and n2 are the principal quantum numbers of the two states. Assume the Bohr model to be valid. The time period of the electron in the initial state is eight times that in the final state. The possible values of n1 and n2 are

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 26

The time period of the electron in a Bohr orbit is given

Since for the nth Bohr orbit, mvr = n (h/2π), the time period becomes

Since the radius of the orbit r depends on n, we replace r. Bohr radius of a hydrogen atom is

It is given that T1 / T2 = 8, hence, n1/n2 = 2.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 27

The half-life of 131I is 8 days. Given a sample of 131I at time t = 0, we can assert that

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 27

The result follows from the formula based on laws of radioactive decay N = N0e–λt The nucleus start decaying after time t = 0

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 28

In a p-n junction diode not connected to any circuit,

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 28

At junction a potential barrier/depletion layer is formed as shown, with n-side at higher potential and p-side at lower potential. Therefore, there is an electric field at the junction directed from the n-side to p-side

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 29

X-rays are produced in an X-ray tube operating at a given accelerating voltage. The wavelength of the continuous X-rays has values from

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 29

The continuous X-ray spectrum is shown in figure.

All wavelengths > λmin are found.

Here V is the applied voltage.

*Multiple options can be correct
Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 30

The work function of a substance is 4.0 eV. The longest wavelength of light that can cause photoelectron emission from this substance is approximately

Detailed Solution for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced - Question 30

View more questions
Information about Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced Page
In this test you can find the Exam questions for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced solved & explained in the simplest way possible. Besides giving Questions and answers for Test: MCQs (One or More Correct Option): Modern Physics | JEE Advanced, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE