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Olympiad Test: Playing With Numbers - Class 5 MCQ


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20 Questions MCQ Test - Olympiad Test: Playing With Numbers

Olympiad Test: Playing With Numbers for Class 5 2024 is part of Class 5 preparation. The Olympiad Test: Playing With Numbers questions and answers have been prepared according to the Class 5 exam syllabus.The Olympiad Test: Playing With Numbers MCQs are made for Class 5 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Playing With Numbers below.
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Olympiad Test: Playing With Numbers - Question 1

What are the numbers which have more than two factors called?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 1

Numbers which have more than two factors are called composite numbers.

Olympiad Test: Playing With Numbers - Question 2

What are the numbers which have only two factors (1 and the number itself) called?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 2

Numbers which have only two factors (1 and itself) are called prime numbers.

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Olympiad Test: Playing With Numbers - Question 3

Which is the number that is neither prime nor composite?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 3
Number that is neither prime nor composite:

  • 1: The number 1 is neither prime nor composite. A prime number is a number greater than 1 that has no positive divisors other than 1 and itself. Since 1 only has one positive divisor (itself), it does not meet the definition of a prime number. Similarly, a composite number is a positive integer greater than 1 that can be formed by multiplying two smaller positive integers. Since 1 does not meet this criteria either, it is considered neither prime nor composite.

Olympiad Test: Playing With Numbers - Question 4

Which of the following is the L.C.M. of 36 and 72?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 4

The prime factorization of 36 is: 2 x 2 x 3 x 3

The prime factorization of 72 is: 2 x 2 x 2 x 3 x 3

Eliminate the duplicate factors of the two lists, then multiply them once with the remaining factors of the lists to get LCM = 2 x 2 x 2 x 3 x 3 = 72 

Olympiad Test: Playing With Numbers - Question 5

What is the L.C.M. of 17 and 5?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 5
Explanation:

  • Step 1: Find the prime factors of each number


    • 17 = 17 (prime number)

    • 5 = 5 (prime number)


  • Step 2: Identify the common and uncommon prime factors


    • Common prime factors: None

    • Uncommon prime factors: 17, 5


  • Step 3: Multiply all the prime factors to get the L.C.M.


    • L.C.M. = 17 x 5 = 85



Therefore, the L.C.M. of 17 and 5 is 85.
Olympiad Test: Playing With Numbers - Question 6

What is the H.C.F. of 17 and 5?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 6

No factor except 1 is common to them.

Olympiad Test: Playing With Numbers - Question 7

Give an example for twin primes.

Detailed Solution for Olympiad Test: Playing With Numbers - Question 7

The first few twin prime pairs are: (3, 5), (5, 7), (11, 13), (17, 19), (29, 31), (41, 43), (59, 61), (71, 73), (101, 103), (107, 109), (137, 139), … ... Five is the only prime in two distinct pairs.

Olympiad Test: Playing With Numbers - Question 8

What is the H.C.F. of two co-prime numbers?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 8

H.C.F. of two co-prime numbers is 1.

Olympiad Test: Playing With Numbers - Question 9

Which of the following is an example of an even number?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 9

Of the given options 973572 is an even number.

Olympiad Test: Playing With Numbers - Question 10

What is the H.C.F. of 120, 144 and 216?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 10

∴ H.C.F. of 120 & 144 =24

Olympiad Test: Playing With Numbers - Question 11

What do you get when you multiply two factors?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 11

When two factors are multiplied we get a product.

Olympiad Test: Playing With Numbers - Question 12

Every number is a _____ and a _____ of itself.

Detailed Solution for Olympiad Test: Playing With Numbers - Question 12
Factors and Multiples

  • Factors: A factor of a number divides that number exactly without leaving a remainder.

  • Multiples: A multiple of a number is the result of multiplying that number by an integer.


Relationship Between Factors and Multiples

  • Every number is considered a factor and a multiple of itself because:

    • A number is always divisible by itself, making it a factor.

    • The product of a number and 1 is the number itself, making it a multiple.



  • For example, the number 5:

    • Factors of 5 are 1 and 5 (1 x 5 = 5).

    • Multiples of 5 are 5, 10, 15, 20, and so on.




Conclusion

  • Therefore, every number is both a factor and a multiple of itself due to the nature of division and multiplication.

  • This relationship holds true for all integers, making it a fundamental property of numbers.

Olympiad Test: Playing With Numbers - Question 13

What are the numbers which are multiples of 2 called?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 13
Even Numbers:

  • Definition: Even numbers are integers that are divisible by 2 without leaving a remainder.

  • Examples: 2, 4, 6, 8, 10, etc.

  • Properties:

    • Even numbers always end in 0, 2, 4, 6, or 8.

    • When you add or subtract two even numbers, the result is always an even number.

    • Even numbers are opposite to odd numbers in the number line.



Olympiad Test: Playing With Numbers - Question 14

What is the H.C.F. of the two numbers equal to?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 14
Explanation:

  • H.C.F. (Highest Common Factor) of two numbers is the greatest number that divides both of them without leaving a remainder.

  • L.C.M. (Least Common Multiple) of two numbers is the smallest number that is a multiple of both numbers.

  • Let the two numbers be a and b, and their H.C.F. be x and L.C.M. be y.

  • According to the property, a * b = x * y.

  • Therefore, x = (a * b) / y.

  • So, the H.C.F. of the two numbers is equal to the product of the numbers divided by their L.C.M.

  • Hence, the correct answer is Option A: Product of the numbers divided by their L.C.M.

Olympiad Test: Playing With Numbers - Question 15

Which of these numbers is a factor of every number?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 15

1 is a factor of every number.

Olympiad Test: Playing With Numbers - Question 16

How many prime numbers are there between 1 and 50?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 16

1 is not a prime number so these are all possible prime numbers between 1 to 50

“2,3,5,7,11,13,17,19,23,29,31,37,41,43,47” which are 15 in number

Olympiad Test: Playing With Numbers - Question 17

A is the 5th prime number. B is the 7th prime number. What is B - A?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 17

2,3,5,7,11,13,17,19,23,29,31,37,41,43,47

A = 11 and
B = 17
17-11 = 6

Olympiad Test: Playing With Numbers - Question 18

What is the number of prime numbers between 50 and 60?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 18

53 and 59 are the prime number between 50 and 60

Olympiad Test: Playing With Numbers - Question 19

Which of the following is the prime factorisation of 140?

Detailed Solution for Olympiad Test: Playing With Numbers - Question 19

A: 2 × 2 × 7 = 28

B: 2 × 2 × 5 = 20

C: 2 × 2 × 5 × 7 = 140

D: 2 × 2 × 5 × 7 × 3 = 420

Olympiad Test: Playing With Numbers - Question 20

The successor of every even number is

Detailed Solution for Olympiad Test: Playing With Numbers - Question 20

Even numbers are 2,4,6,8,10 and so on.

In between these even numbers, we have odd numbers 3,5,7,9..

Hence, successor of even number, is an odd number.

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